Given the reaction below, which is the reduced substance?Mg + Cl2 Right arrow. Mg2+ + 2Cl-
2CI-
CI2
Mg
Mg2+

Answers

Answer 1
Answer: Cl2 is the reduced substance

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Which polyatomic ion is found in the compound represented by the formula NaHCO3?(1) acetate (3) hydrogen sulfate

(2) hydrogen carbonate (4) oxalate

Answers

Answer is (2) - hydrogen carbonate


Explanation:


NaHCO₃ is an ionic compound which is made from Na⁺ and HCO₃⁻ ions. The decomposition is

NaHCO₃ → Na⁺ + HCO₃⁻


Among the resulted ions, Na⁺ is a monatomic ion while HCO₃⁻ is a polyatomic ion.


Polyatomic ions mean ions which are made of two or more different atoms.


HCO₃⁻ is made from 3 atoms as H, C and O. The name of HCO₃⁻ ion is bicarbonate or hydrogen carbonate.

2. The characteristic bright-line spectrum (color) of an element is produced whenA elections are ermitted by the nucleus as beta particles
B electrons move to higher energy levels
** C electrons are gained by an atom in
D. člectrons fall bàok to lower energy levels

Answers

Answer:

option d= electrons fall back to the lower energy levels

Explanation:

Excitation:

When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits.

De-excitation:

When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum.

Fluorescence:

In fluorescence the energy is absorbed by the electron having shorter wavelength and high energy usually of U.V region. The process of absorbing the light occur in a very short period of time i.e. 10 ∧-15 sec. During the fluorescence the spin of electron not changed.

The electron is then de-excited by emitting the light in visible and IR region. This process of de-excitation occur in a time period of 10∧-9 sec.

Phosphorescence:

In phosphorescence the electron also goes to the excitation to the higher level by absorbing the U.V radiations. In case of Phosphorescence the transition back to the lower energy level occur very slowly and the spin pf electron also change.

Final answer:

The characteristic color (spectrum) of an element is produced when its electrons fall back to lower energy levels. They absorb energy to jump to a higher level, then emit it in the form of light of a specific wavelength when returning to their original or lower level.

Explanation:

The characteristic bright-line spectrum (color) of an element is produced when electrons fall back to lower energy levels (Option D). This process is part of the quantum mechanical model of the atom, particularly in the field of spectroscopy. Each element possesses unique energy levels. When an electron in an atom absorbs energy, it jumps to a higher energy level. When the electron returns to its original or lower energy level, it emits energy in the form of light of a specific wavelength. This is viewed as a unique color in the spectrum.

Learn more about Electron Energy Levels here:

brainly.com/question/24373411

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Are spider multicellular

Answers

Yes, the only single cell organisms that exist are the cells that make up an organism

Can someone list the observable changes that indicate a physical change has occurred? Same for chemical change?

Answers

go to google and search list the observable changes that indicate a physical change has occurred? and its the second one from the bottom

a. Atomic #= 3 b. Mass #=7 c. # of Protons = d. # of Neutrons = e. # of Electrons = E in Ist energy level = E in 2nd energy level = E in 3rd energy level = 0 # of Valence E = Li​

Answers

I hope you can understand my writing :)

How long would it take for a car to travel 200km if it has an aventage speed of 55 km/ hr

Answers

Answer: 3.64 hours

Explanation:

Formula of Average speed : \text{Average speed}=\frac{\text{Distance}}{\text{Time}}

Given : Distance = 200km    ; Average speed = 55 km/ hr

To find : Time

Substitute values for distance and average speed in the above formula , we get

 55=\frac{200}{\text{Time}}\n\n\Rightarrow\text{Time}=(200)/(55)=3.63636363636\approx3.64\ hr

Hence, it would take 3.64 hours for a car to travel 200km .