MATHEMATICS HIGH SCHOOL

Which set is a function?a) {(0,3), (3,0), (0,4), (4,0)}
b) {(0,2), (2,0), (4,6), (6,4)}
c) {(2,6), (3,6), (4,6), (2,0)}
d) {(6,2), (2,0), (4,6), (6,4)}

Answers

Answer 1
Answer: b is the answer because the value of x does not repeat

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Find the complex number to solve the equation: 9(2-4i) - 6(x+yi) = 14-3iPlease solve and explain in detail.

Answers

9(2-4i)-6(x+yi)=14-3i\n18-36i-6x-6yi=14-3i\n-6x-6yi=-4+33i\n-6x=-4 \wedge -6y=33\nx=(4)/(6) \wedge y=-(33)/(6)\nx=(2)/(3) \wedge y=-(11)/(2)\n\n\boxed{x+yi=(2)/(3)-(11)/(2)i}

What is the reference angle for -275 degrees?

Answers

Look\ at\ the\ picture.

A for-profit institution that works with the general public to open and manage savings accounts is known as a(n) _____

Answers

Answer:

Saving Banks.

Step-by-step explanation:

A saving bank is a financial institution focused on receiving saving deposits, which will generate paying interests to costumers.

So, A for-profit institution for general public, managing savings accounts is known as a saving bank.

Which of the following is the conjugate of a complex number with 2 as the real part and −8i as the imaginary part?(A. -2+8i; B. 2+8i; C. 2-8i; D.-2-8i)

Answers

Hi,

The complex number is

z = a+bi

For a = 2 and b = -8 

z = 2+(-8)i
z = 2-8i

The conjugate is 

z = a-bi

For a = 2 and b = -8 

z = 2-(-8)i
z = 2+8i

Answer:

B. 2+8i

For one full week, Cheng spent $12.50 per day on lunch. Determine the total amount of money he spent on lunches.

Answers

Answer:

Step-by-step explanation:

To determine the total amount of money Cheng spent on lunches for one full week, we need to multiply the amount he spent per day by the number of days in a week.

Given that Cheng spent $12.50 per day on lunch, we can calculate the total amount as follows:

$12.50 x 7 days = $87.50

Therefore, Cheng spent a total of $87.50 on lunches for one full week.

To calculate this, we multiplied the cost per day ($12.50) by the number of days in a week (7 days). This gives us the total amount of money Cheng spent on lunches.

Find the distance between the pair of parallel lines, y = -2x+1 & y = -2x+16.

Answers

Given \ the \ equations \ of \ two \ non-vertical \ parallel \ lines:\n\ny = mx+b_1\ny = mx+b_2\n\nthe \ distance \ between \ them \ can \ be \ expressed \ as : \n\nd= (|b_(1)-b_(2)|)/( √( m^2+1) )

y = -2x+1\ny = -2x+16 \n\n\nd= (|b_(1)-b_(2)|)/( √( m^2+1) ) =(| 1-16|)/( √( (-2)^2+1) ) =(| -15|)/( √( 4+1) ) =(15)/(√(5))\cdot (√(5))/(√(5))=\n \n\n=(15√(5))/(5)=3√(5)\approx 3\cdot 2.24 \approx 6.72
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