A teacher recorded the time, in minutes, it took each student in two classes to complete a quiz. The results are shown in the box plots below.

Answer:

12:6 or 6:12 cant remember but i thinks its the first one lol

Step-by-step explanation:

a) The probability that a new municipal bond issued by a city will receive an A rating is 0.625 or 62.5%.

b) 56% of municipal bonds are issued by cities.

c) The proportion of municipal bonds issued by suburbs is 0.325 or 32.5%.

Let's solve each part of the problem:

a. If a new municipal bond is to be issued by a city, what is the probability that it will receive an A rating?

Use conditional probability here.

Using conditional probability notation, we have:

P(A | City)

To calculate this, use the following formula:

P(A | City) = P(A and City) / P(City)

We are given:

- P(A) = 0.70 (probability of an A rating)

- P(B) = 0.20 (probability of a B rating)

- P(C) = 0.10 (probability of a C rating)

For bonds issued in cities:

- P(City | A) = 0.50 (probability that it's a city if it's rated A)

- P(City | B) = 0.60 (probability that it's a city if it's rated B)

- P(City | C) = 0.90 (probability that it's a city if it's rated C)

Now, let's calculate:

P(A and City) = P(A) * P(City | A)

P(City) = P(A) * P(City | A) + P(B) * P(City | B) + P(C) * P(City | C)

Substitute the values:

P(A and City) = 0.70 * 0.50

                      = 0.35

P(City) = (0.70 * 0.50) + (0.20 * 0.60) + (0.10 * 0.90)

          = 0.35 + 0.12 + 0.09

          = 0.56

Now, calculate the conditional probability:

P(A | City) = P(A and City) / P(City)

                = 0.35 / 0.56

                = 0.625

So, the probability is 0.625 or 62.5%.

b. What proportion of municipal bonds are issued by cities?

56% of municipal bonds are issued by cities.

c. What proportion of municipal bonds are issued by suburbs?

To find the proportion of municipal bonds issued by suburbs,  use a similar approach:

P(Suburb) = P(A) * P(Suburb | A) + P(B) * P(Suburb | B) + P(C) * P(Suburb | C)

We are given:

- P(Suburb | A) = 0.40

- P(Suburb | B) = 0.20

- P(Suburb | C) = 0.05

Now, calculate:

P(Suburb) = (0.70 * 0.40) + (0.20 * 0.20) + (0.10 * 0.05)

                 = 0.28 + 0.04 + 0.005

                 = 0.325

So, the proportion of municipal bonds issued by suburbs is 0.325 or 32.5%.

Learn more about Probability here:

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Final answer:

The probability that a municipal bond issued by a city will receive an A rating is 35%. The proportion of all municipal bonds issued by cities is 56%. The proportion of all municipal bonds issued by suburbs is 32.5%.

Explanation:

This question requires an understanding of probability and conditional probability.

a) To find the probability that a new municipal bond issued by a city will receive an A rating, we must first determine the likelihood that an A-rated municipal bond is issued by a city. Given that 50% of A-rated bonds are issued by cities and that 70% of all bonds receive an A rating, we can calculate this probability as (0.50)*(0.70) = 0.35, or 35%.

b) To find the proportion of municipal bonds issued by cities, we must add up the bonds issued by cities across all ratings. So, (0.70*0.50) + (0.20*0.60) + (0.10*0.90) = 0.35 + 0.12 + 0.09 = 0.56, or 56%.

c) To calculate the proportion of municipal bonds issued by suburbs, we do the same calculation as in part b) but for suburbs. So, (0.70*0.40) + (0.20*0.20) + (0.10*0.05) = 0.28 + 0.04 + 0.005 = 0.325, or 32.5%.

Learn more about Probability here:

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Answer:

The answer is 46 when x = 5

Step-by-step explanation:

8*x + 6

So x = 5

8*5 + 6

40 + 6

46

Answer:

b

Step-by-step explanation:

lim x → ∞ x^4 x^8 + 2

Combine exponents:

lim x → ∞ x^(4 +8) + 2

lim x → ∞ x^12 + 2

The limit at infinity of a polynomial, when the leading coefficient is positive is infinity.

Answer:

144

Step-by-step explanation:

first digit of the code: only 2 and 4 are the only even numbers availible, so only 2 possibilities for the first digit.

2nd digit of code: 2,5,7,9,1 so 6 possibilities for the 2nd digit.

3rd digit of code: 2,5,7,9,1 so 6 possibilities for the 3rd digit.

4th digit of code: only 7 and 9 are greater tyhan 6 so only 2 possibilities for the 4th digit.

SO...

2 x 6 x 6 x 2 = 144