Nora has a ribbon that is 3/4 yard long. She will use 1/2 of it to make a bow. What length of the ribbon will she use for the bow?

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:


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Kenny worked 6.5 hours on Monday, and 5 hours on Tuesday. If he received a check for $143.75 for working those 2 days, how much does Kenny make per hour?

Answers

Answer:

Kevin makes $12.50 per hour.

Step-by-step explanation:

If Kevin works 6.5 hours on Monday and 5 hours on Tuesday, he works a total of 11.5 hours. Over 11.5 hours he makes $143.75. To find your answer, you have to divide your total earned, 143.765, by the total time worked, 11.5 hours. Your answer should then be 12.5, which is the amount per hour kevin earns.

Emily has 27 Barbie dolls. She put equal number of dolls in each of 5 boxes. How many dolls are left over?

Answers

Answer:

2 barbies are left over

Step-by-step explanation:

5(5)=25

27-25=2

Leaving 2 barbies.

Solve system by Substitution
method, provide steps.
y = 8x + 12
3.x – 3y = 6

Answers

Step-by-step explanation:

y = 8x + 12 _____(1)

3x - 3y = 6 ______(2)

Substituting the.the expression for y in eqn (1)

into eqn (2).

3x - 3(8x + 12) = 6

3x - 24x - 36 = 6

-21x = 42

x = -2.

y = 8(-2) + 12 = -4.

hence x = -2 and y = -4.

Answer:

54

Step-by-step explanation:

What is the solution to the system of equations?3x+10y=-47
5x - 7y=40
O (1.-5)
O (1,5)
0 (-1,-5)
0 (-1,5)

Answers

Answer:

x=1 ,y=-5

Step-by-step explanation:

3x + 10y = 47

5x - 7y = 40

____________

21x + 70y = 329. equ 1

50x - 70y = 400. equ 2

subtract equ 1 from 2

=71x = 71

divide both sides by the 71

71/71 = 71/71

x = 1

_________

to find y

substitute x into either equ 1 or equ 2

am using equ 2

5x - 7y = 40

5(1) - 7y = 40

5 - 7y = 40

7y = 5 - 40

7y = -35

divide both sides by the coffecient of y

7y/7 = -35/7

y = - 5

Can anyone help me plzzzzz

Answers

Step-by-step explanation:

cmon man its a blank screen

. A field will be made in the shape of a rectangle with an area of 400 square meters. One side of the field is along a river and a fence will be built along the other three sides. A brick wall perpendicular to the river will be built to divide the field into two equal halves. the wall costs $20 per meter and the fence costs $10 per meter to build. what is the lowest possible cost to build such a field?

Answers

Answer:

The correct answer is $800.

Step-by-step explanation:

Let the length and width of the field be equal to l meters and b meters respectively and l > b.

Area of the field is given by l × b = 400 square meters.

The river is supposed to be along the longest side so that the price of fencing the other three sides is minimum. Thus the total perimeter of the fence is b+ b+ l = 2b+l.

Total cost for fencing the other sides of the field = $ 10 × (2b + l)

The wall is supposed to be perpendicular to the river and thus the length of the wall is b meters.

Total cost for the wall is $ 20 × b

Therefore, the total price for making the field is given by

C = 10 × (2b + l) + 20 × b

⇒ C = 40b + 10l

⇒ C = (16000)/(l) + 10l

To minimize the cost we differentiate the cost with respect to l and equate it to zero.

(dC)/(dl) = 0 = - (16000)/(l^(2)) + 10

l^(2) = 1600

l = 40 ; [ negative sign neglected as length cannot be negative ]

b = 10

The second order derivative of C is positive giving the minimum value of the cost.

Thus the minimum cost required to make the field is given by $800.

Final answer:

To find the lowest possible cost to build the field, we need to determine the dimensions that will yield the minimum perimeter and then calculate the total cost of building the field. By differentiating the cost equation and solving for x, we can find the dimensions that minimize the cost.

Explanation:

To find the lowest possible cost to build the field, we need to determine the dimensions that will yield the minimum perimeter. Since the area of the field is 400 square meters and it will be divided into two equal halves by a brick wall, each half will have an area of 200 square meters. Let's say the length of the field is x meters. Then the width of each half will be 200/x meters.

The perimeter of the field is the sum of the lengths of the three sides:

Perimeter = 2x + 200/x + 200/x

Now, we can define the total cost to build the field as:

Total Cost = Cost of wall + Cost of fence

Cost of wall = 2x * $20 (since there are two halves)

Cost of fence = (2x + 200/x + 200/x) * $10 (since there is a fence on three sides)

Therefore, the total cost is: Total Cost = 2x * $20 + (2x + 200/x + 200/x) * $10.

To minimize the cost, we can differentiate the total cost with respect to x and set it equal to zero:

d(Total Cost)/dx = 0

Simplifying this equation will give us the value of x that minimizes the cost. We can solve this equation to find the minimum cost to build the field.

Learn more about field here:

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