HeLpPLZZZ (Edge). Which line on the graph represents the information in the table? Cost of Pencils Number of Pencils Total Cost (in $) 2 0.50 4 1.00 6 1.50 8 2.00 On a coordinate plane, the x-axis is labeled Number of pencils and the y-axis is labeled total cost in dollars. Line a goes through points (1, 4) and (2, 8). Line b goes through points (1, 2) and (2, 4). Line c goes through (2, 1) and (4, 2). Line d goes through (4, 1) and (8, 2). line a line b line c line d

Answers

Answer 1

Answer:

Answer:

Line D- (4, 1) and (8, 2).

Step-by-step explanation:

The table representing the information is given below:

$\left|\begin{array}{c|c}$Number of Pencils(x)&$Total Cost(in $)(y)\n----&----\n2&0.50\n4&1.00\n6&1.50\n8&2.00\end{array}\right|$

On the coordinate plane, the x-axis is labeled Number of pencils and the y-axis is labeled total cost in dollars.

Therefore, any point that matches with the (x,y) pair on the table represents the information in the table.

Only Line D matches with the pair (4,1) and (8,2)

Answer 2

Answer:

Answer:

Line D

Step-by-step explanation:

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Given ƒ(x) = 3x - 1 and g(x)= -x + 6, find ƒ(-2) + g(5).-668

Sequencing of rigid motions matters . true or false ?

Answers

Answer:

False.......................

Step-by-step explanation:

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San Pablo is having a festival. Tickets for children under 12 cost $2, adult tickets are $6 and senior citizen tickets are $3. One sixth of the tickets sold were children’s tickets. The 40 senior citizens with tickets sat in the shade under the trees and watched the children play. Half the people attending the festival purchased adult tickets. How much money was collected from ticket sales?

Answers

The total of tickets sold would be 100% or 1, so we have 1/6 of total tickets for kids and 1/2 of total of tickets for adults, for finding the part of tickets sold for seniors we calculate: 1/6 + 1/2 + x = 1 here x is the part of tickets for seniors.
Solve for x: x=1/3.
Now let total of tickets be "T", we know the amount of tickets sold for seniors (40) so we can say: 1/3*T = 40, solve for T and get T = 40*3 = 120 tickets sold.
Finally we can calculate the money collected from tickets sold multiplying the cost*the part of tickets sold for each group*120 and add all of them, this is:
$2*1/6*120 + $6*1/2*120 + $3*1/3*120 = $40 + $360 + $120 = $520
The money collected from ticket sales is: $520

Chocos is a dish made from wheat, sugar, and cocoa. Bertha is making a large pot of chocos for a party. Wheat(w) cost $5 per pound, sugar(s) costs $3 per pound, and cocoa(c) costs $4 per pound. She spends $48 on 12 pounds of food. She buys twice as much cocoa as sugar.

Answers

The question is incomplete, complete question is;

Chocos is a dish made from wheat, suguar, and cocoa. Bertha is making a large pot of chocos for a party. Wheat (w) costs $5 per pound, sugar (s) costs $3 per pound, and cocoa (c) costs $4 per pound. She spends $48 on 12 pounds of food. She buys twice as much cocoa as sugar. How much wheat, sugar, and cocoa will she use (in pounds) in her dish?

Answer:

She uses 3 pounds of wheat, 3 pounds of sugar and 6 pounds of cocoa in her dish.

Step-by-step explanation:

Given,

Total amount of spent money = $ 48

Total quantity of ingredients = 12 pounds

Let the quantity of wheat, sugar and cocoa she buys be x, y z pounds respectively.

$\therefore x+y+z=12\ equation 1\nand\ 5x+3y+4z=48\ equation2$

And according to question, quantity of cocoa is 2 times of sugar.

$\therefore z=2y$

Now substituting the value of z in equation 1and 2, we get;

$x+y+2y=12\nx+3y=12\ equation3$

$5x+3y+4*2y=48\n5x+3y+8y=48\n5x+11y=48\ equation\ 4$

Now multiply equation 3 by 5 and then subtract equation 4 from it.

$5(x+3y)=5*12\n(5x+15y=60)-(5x+11y=48)\n4y=12\ny=(12)/(4)=3$

$\therefore z=2y=2*3=6$

And substituting the value of y in equation 3, we get;

$x+3y=12\nx+3*3=12\nx+9=12\nx=12-9=3$

Thus the amount she uses is 3 pounds of wheat, 3 pounds of sugar and 6 pounds of cocoa in her dish.

What is 138% of 250?

Answers

345. (138/100 = x/250)

What is the average rate of change for (0,80) and (15,10)

Answers

Answer:

-14/3

Step-by-step explanation:

formula: (y₂ - y₁) / (x₂ - x₁)

(10 - 80) / (15 - 0)

(-70) / (15)

simplify

-14/3

Y/X
10-80/15-0
-70/15
=-14/3

Leona tracks her calories burned while boxing. The number of calories she burns is expressed by the function c(t) = 425t, where t is the number of hours spent boxing.To burn more calories, Leona wears heavier gloves while boxing. The number of calories she burns while wearing heavier gloves is expressed by the function b(c) = 1.1c, where c is the number of calories burned while boxing without heavy gloves.

Which of the following composite functions expresses the calories, as a function of time, Leona burns while boxing with heavy gloves?

c[b(t)] = 467.5t
c[b(t)] = 426.1t
b[c(t)] = 467.5t
b[c(t)] = 426.1t

Answers

The function for the number of calories burnt as a function of time is:
c(t) = 425 t

And for the number of calories burnt while boxing with gloves is:
b(c) = 1.1c

Therefore, the composite function that expresses the calories, as a function of time, Leon burns while boxing with heavy gloves is:
b[c(t)] = 1.1 (425 t)
b[c(t)] = 467.5 t

The answer is the third option

Answer:C. I took the test.

Step-by-step explanation:

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