The cause for the revision of the research plan is because of the added information that is learned by the researcher is the cause for the change in the research question. Therefore, option (C) is the correct answer.
You might discover fresh points of contention as you revise and edit your work, leading you to conduct additional research or take a closer look at a subject, so enhancing your analytical and research abilities.
Re-examining your work and considering what you're attempting to achieve, how effectively you've done it thus far, and where adjustments still need to be made are the goals of revision plans.
It's possible that you need to clarify your points, provide more proof for your assertions, or remove extraneous information. Read your essay aloud.
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Answer:
Probably C
Explanation:
That question lowkey hard
a) responding
b) understanding
c) evaluating
d) selecting
remembering
Answer:
understanding
Explanation:
Answer:
0 or -3375
Explanation:
The question is somewhat ambiguous because we can't be sure whether B will be positive integers which are multiples of both 3 and 2 or 3 and 2 separately.
For the former:
There a 4 multiples of 6 less than 30: 6, 12, 18, 24.
Positive integers (whole numbers) less than 30: 1-29 ; multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27 and of those, only 6, 12, 18 and 24 are multiples of both 2 and 3.
Therefore we have (4-4)^3 = 0
For the latter:
multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27 ; Multiples of 2: 2 4 6 8 10 12 14 16 18 20 22 24 26 28 (remove common multiples)
Therefore (4-19)^3 = -3375
Answer:
0
Explanation:
Let $x$ be a multiple of $6$. Then $x = 6 \cdot n$ for some integer $n$. So $x = 2 \cdot (3n)$ and $x = 3 \cdot (2n)$. This means that $x$ is a multiple of $3$ and $x$ is a multiple of $2$. So multiples of $6$ must be multiples of $2$ and multiples of $3$.
Every number that is a multiple of both 2 and 3 must also be a multiple of the least common multiple of 2 and 3, which is 6. Hence any number that is a multiple of $3$ and a multiple of $2$ is a multiple of $6$.
We have shown that the numbers that are multiples of $6$ and the numbers that are multiples of $2$ and multiples of $3$ are exactly the same numbers, since any multiple of $6$ is a multiple of $2$ and a multiple of $3$, and any number that is a multiple of $2$ and a multiple of $3$ is a multiple of $6$. So we must have $a = b$. A number minus itself is zero, so our final answer is$$(a - b)^3 = 0^3 = 0
b. information that is part of the accepted knowledge about a particular event.
c. information that is objective and un-opinionated.
d. information from someone who was there when an event happened, which has been unfiltered by other researchers.
Your answer is D
Information from someone who was there when the event happend which has been unfiltered by other researchers
Answer:
CHOICES PLEASE
Explanation:
Answer:
well i dont have enough info to help you with this
b. symbolism
c. paradox
d. understatement
Answer:
D Understatement
Explanation: