PHYSICS COLLEGE

Patricia places 1500g of fruit on a scale compressing it by 0.02m. What is the force constant of the spring on the scale. Hint: you need 2 equations to solve this.

Answers

Answer 1
Answer:

Answer:

The force constant of the spring is 735 N/m.    

Explanation:

It is given that,

Mass of fruit, m = 1500 g = 1.5 kg

Compression in the scale, x = 0.02 m

We need to find the force constant of the spring on the scale. The force acting on the scale is given by using Hooke's law. So,

F=-kx

Also, F = mg

mg=kx

k is force constant

k=(mg)/(x)\n\nk=(1.5* 9.8)/(0.02)\n\nk=735\ N/m

So, the force constant of the spring is 735 N/m.

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in the demolition of an old building,a 1,300 kg wrenching ball hits the building at 1.07m/s^2.Calculate the amount of force at which the wrecking ball strikes the building

Answers

Answer:

1391 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1300 × 1.07

We have the final answer as

1391 N

Hope this helps you

Two charged particles are separated by 10 cm. suppose the charge on each particle is doubled. By what factor does the electric force between the particles change?

Answers

Answer:

The electric force increases by a factor of 4.

Explanation:

The electric force between two charges q_1 and q_2 separated a distance d can be calculated using Coulomb's Law:

F=(kq_1q_2)/(d^2)

where k=9*10^9Nm^2/C^2 is the Coulomb constant.

If the value of each charge is doubled, then we will have a force between them which is:

F'=(k(2q_1)(2q_2))/(d^2)=4(kq_1q_2)/(d^2)=4F

So the new force is 4 times larger than the original force.

Final answer:

Doubling the charge on each particle increases the electric force between them by a factor of 4.

Explanation:

The force between two charged particles is given by Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. So, if we denote the electric force as F, the charges as q1 and q2, and the distance as r, we can write Coulomb's law as F = k* q1*q2/r^2, where k is a constant.

Now if you double the charges (q1 and q2 become 2q1 and 2q2), and use these values in the formula, we get Fnew = k*(2q1) *(2q2)/r^2 = 4 * k*q1*q2/r^2 = 4F.

So, by doubling the charge on each particle, the electric force between them is multiplied by the factor of 4. So, the force increases fourfold.

Learn more about Coulomb's Law here:

brainly.com/question/32002600

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Answers

when sound travels on a certain wave pattern or medium once it hits the surface or surfaces of another wave or mdeium and then it bounces back that is a reflected sound wave.

Hello I would like to know if there is a course or a book in which to learn quantum mechanics is easier, I am currently studying quantum mechanics, but it is a little complicated because I have some mathematical doubts, but nevertheless I would like to know if there is a course or book that explains and develops the problems so that they are understandable. and if there is no book or course I would appreciate an honest and complete answer, thank you very much and greetings.Sorry I know that this is not a problem but what better to ask the experts do not believe.

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Answer:

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Explanation:

A golf ball is dropped from rest from a height of 9.50 m. It hits the pavement, then bounces back up, rising just 9.70 m before falling back down again. A boy catches the ball on the way down when it is 1.20 m above the pavement. Ignoring air resistance calculate the total amount of time the ball is in the air, from drop to catch?

Answers

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A manufacturer claims that a carpet will not generate more than 5.8 kV of static electricity What magnitude of charge would have to be transferred between a carpet and a shoe for there to be a 5.8 kV potential distance d = 2.8 mm ? Approximate the area of a shoe as 30 cm x 8 cm. Express your answer using two significant figures.

Answers

Answer:

4.4×10⁻⁷ Coulomb

Explanation:

V = Voltage = 5.8 kV

d = Potential distance = 2.8 mm = 0.0028 m

A = Area = 0.3×0.08 = 0.024 m²

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