CHEMISTRY HIGH SCHOOL

A certain radioactive atom has 90 protons and 142 neutrons. If this atom undergoes alpha decay, what is the mass number of the daughter atom? The mass number of the daughter atom is .

Answers

Answer 1
Answer:

Answer:

228

Explanation:

alpha decay is removing alpha particle _2^(4)He

2 number of protons, 4 mass number = 2 protons + 2 neutrons

We have

      90 protons and 142 neutrons

      - 2 protons         -  2 neutrons

      88 protons         140 neutrons

Mass number of new (daughter) atom = 88 +140 = 228
Answer 2
Answer:

Answer:

Correct Answer: 228

Explanation:

alpha decay is removing alpha particle

2 number of protons, 4 mass number = 2 protons + 2 neutrons

________________________________________________

We have:

_______________________

90 protons and 142 neutrons

     - 2 protons         -  2 neutrons

     88 protons         140 neutrons

Mass number of new (daughter) atom = 88 +140 = 228

Hope I helped you\ Have a great day / good luck on your studies :)

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Answers

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Reaction 2 occurs when an excess of 6 M HCI(aq) solution is added to 100. mL of NaOCl(aą) of unknown concentration. If the reaction goes to completion and 0.010 mol of Cl2(g) is produced, then what was the molarity of the NaOCl(aq) solution? (A) 0.0010 M
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Answers

The molarity of the NaOCl solution is 0.10M

The correct answer to the question is Option C. 0.10 M

We'll begin by calculating the number of mole of NaOCl required to produce 0.010 mole of Cl₂.This can be obtained as follow:

NaOCl + 2HCl —> Cl₂ + NaCl + H₂O

From the balanced equation above,

1 mole of NaOCl reacted to produce 1 mole of Cl₂.

Therefore

0.010 mole of NaOCl will also react to produce 0.010 mole of Cl₂.

  • Finally,we shall determine the molarity of the NaOCl solution.

Mole of NaOCl = 0.01 mole

Volume = 100 mL = 100 / 1000 = 0.1 L

Molarity of NaOCl =?

Molarity = mole / Volume

Molarity of NaOCl = 0.01 / 0.1

Molarity of NaOCl = 0.1 M

Therefore, the molarity of the NaOCl solution is 0.1 M

Learn more: brainly.com/question/12755239

Answer:

Option C 0.10 M

Explanation:

you are not providing the reaction, but luckily we have data to write the equation. We know that we are taking HCl and NaOCl to produce Cl2, the reaction is as follow:

NaOCl + 2HCl ---------> Cl₂ + NaCl + H₂O

From this reaction, we know that we have excess of acid that is added to 100 mL (0.1 L) of NaOCl, and this produces 0.010 moles of Chlorine.

All we have to do here, is apply stechiometry. We already know that the acid is in excess, so the moles produced would be the moles of the limiting reactant, in this case, the NaOCl.

According to the reaction NaOCl and Cl2 has a mole ratio of 1:1, so the moles of Cl2 would be the same moles that NaOCl lost so:

moles Cl2 = moles NaOCl = 0.010 moles

Then the concentration:

M = 0.010 / 0.1

M = 0.10 M

This is the molarity of NaOCl
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