Given that QRST is a kite and that ST = TQ, find ST.

Answers

Answer 1

Answer: Q/R = S/T as Q/T = R/S

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Choose the correct simplification of the expression −4x2(6x − 5x2 − 5).20x4 + 24x3 + 20x2 −9x4 + 2x3 − 9x2 20x4 − 24x3 + 20x2 −20x4 + 24x3 − 20x2
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7-^3Simplify this expression. Use 7 as the base.

Kiara has a ribbon that measures 1/4 of an inch and Jillian has a ribbon that measures 2/3 of an inch. Jillian says their ribbons are equal in length because her numerator is one more than kiara's and her denominator is one less, therefore balancing the two fractions. Is she correct? Why or why not?

Answers

Answer:

Jillian is Incorrect as fraction can never be balanced based on numerator or denominator.

Step-by-step explanation:

Given:

Measure of ribbon Kiara has = $(1)/(4) \ inch$

Measure of ribbon Jillian has = $(2)/(3) \ inch$

Now given:

Jillian says their ribbons are equal in length because her numerator is one more than kiara's and her denominator is one less, therefore balancing the two fractions.

we need to find whether statement is correct or not.

First we will find the decimal value of the given fraction's

$(1)/(4) \ inch$ can rewritten as $0.25\ inch$

Measure of ribbon Kiara has = 0.25 inch

$(2)/(3) \ inch$ can be Rewritten as $0.67\ inch$

Measure of ribbon Jillian has = 0.67 inch

Now we can see that;

0.67 inch is greater than 0.25 inch.

Hence we can say that ribbons are not in equal length.

Also the fraction can never be balanced by decreasing or increasing the numerator or denominator.

The formula that relates the length of a ladder, L, that leans against a wall with distance d from the base of the wall and the height h that the ladder reaches up the wall is mc024-1.jpg. What height on the wall will a 15-foot ladder reach if it is placed 3.5 feet from the base of a wall?

Answers

We will use the Pythagorean theorem to determine the height: $h^(2)=15^(2) - 3.5^(2)$ $h^(2) =225 - 12.25=212.75$ Finally: $h= √(212.75)=14.5859$
Answer Ladder will reach the height of 14.59 feet ( to the nearest hundredths).

Answer: it's 14.6 feet

Share 60 in the ratio 6:4

Answers

Answer:

36:24

Step-by-step explanation:

6+4=10

60/10=6

6*6:4*6

=36:24

Verify the identity. Show your work.

(1 + tan2u)(1 - sin2u) = 1

Answers

I assume you mean (1 + tan^2u)(1 - sin^2u) = 1 so I solved it like that

because tanu = sinu / cosu ⇒ tan^2u = sin^2u / con^2u

(1 + sin^2u/cos^2u)(1 - sin^2u) =
(cos^2u/cos^2u + sin^2u/cos^2u)(1 - sin^2u) =
((cos^2u + sin^2u)/(cos^2u)) (1 - sin^2u) =

and because cos^2u + sin^2u = 1 we'll have

(1/(cos^2u)) (1 - sin^2u) =
1/(cos^2u) - sin^2u/(cos^2u) =
(1 - sin^2u) / (cos^2u) =

notice that 1 - sin^2u is equal to cos^2u

cos^2u / cos^2u = 1

Find the value of the expression below for r = 4 and t = 2
t^3 - r + 20 divided by r

Answers

Answer:

The value of the expression $t^3-r+(20)/(r)$ is, 9

Step-by-step explanation:

Given: The expression $t^3-r+(20)/(r)$

Substitute the value of r=4 and t=2 in above expression to find its value;

$t^3-r+(20)/(r) = (2)^3-4+(20)/(4)$

Cube: the cube of a number t is its third power, the result of the number multiplied by itself twice. i.e, $t^3 = t * t * t$

Now, solve further we have;

$(2)^3-4+(20)/(4) = 8 -4+(20)/(4)$

Further, divide the number 20 by 4 we get the result 5 ;

⇒ 8-4+5 = 4+5 =9

Therefore, the value of the expression $t^3-r+(20)/(r)$ is, 9.

Which is another way to check the sum of 52+23+10+78

Answers

well first off those numbers add up to 163.

A way to check this is to add 52 with 23 which is 75 then add 78 by 10 which is 88 now add 75 with 88 which is 163

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