you have a 1.5 litre bottle of water and drink 295 millilitres and your friend drinks 135 millilitres, how much water is left

Answers

Answer 1
Answer: 1,070 milliliters of water is left

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The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room.Which equations can be used to solve for y, the length of the room? Check all that apply.

y(y + 5) = 750
y2 – 5y = 750
750 – y(y – 5) = 0
y(y – 5) + 750 = 0
(y + 25)(y – 30) = 0

Answers

Answer:

Option B , C  and E are correct

y^2-5y =750

750 -y(y-5)=0

(y+25)(y-30)=0

Step-by-step explanation:

Given : Area of rectangular room is 750 square feet.

Width of the room is 5 feet less than the length of the room.

Let y be the length of the room

then,

As per the given condition

width of the room is: y-5

Area of rectangle is multiply the length by its width.

Area of rectangle = length * width

Substitute the given values in above formula we get;

750 = y(y-5)                            ......[1]

or we can write this as;

750 -y(y-5)=0

[1] ⇒y(y-5) =750  or

y^2-5y =750 or

y^2-5y-750=0

y^2-25y+30y-750=0

(y+25)(y-30)=0

Therefore, the equation which can be used to solve for y are;

y^2-5y =750 , 750 -y(y-5)=0  and (y+25)(y-30)=0




Hello,

A:False
B:True
C:True
D:False
E:True


What is the seventh term of the sequence 1, 3, 9, 27, ...? 81 243 729 2187

Answers

The answer is 729. Hope this helps

Answer:

729

Step-by-step explanation:

The ice skating rink charges an hourly fee for skating and $3 to rent skates for the day. Gillian rented skates and skated for 3 hours and was charged $21. Which equation represents the cost, c(x), of ice skating as a function of x, the number of hours of skating?

Answers

c(x) = 6x + 3
shee skated for 3 hrs and was charged $21
c(3) = 6(3) + 3
c(3) = 18 + 3
c(3) = 21
correct....so it is c(x) = 6x + 3

C(x) = 6x + 3 (in USD)

Further explanation

Given:

  • The fee to rent is $3 for the day.
  • Gillian rented skates and skated for 3 hours and was charged $21.

Question:

The equation that represents cost, C(x), ice skating as a function of x, the number of hours of skating.

The Process:

We try solving a word problem about the single variable equation.

Step-1: calculate the cost of skates per hour.

Let the rate of using the skating rink be R per hour. We will seek the value of R.

On that day Gillian rented skating for 3 hours and paid $ 21. The equation that will determine this given by:

\boxed{ \ 3R + 3 = 21 \ }

Both sides subtracted by 3.

\boxed{ \ 3R = 18 \ }

We isolate R on the left side. Both sides are divided by 3.

Hence, the fee of skates per hour is \boxed{R = \$6}

Step-2: determine the cost equation for ice skating

Let x as the number of hours of skating.

Recall the fee of skates per hour is $6 and the fee to rent is $3 for the day.

Thus, the equation which represents the cost of ice skating as a function of x, the number of hours of skating, will be given by:

\boxed{ \ C(x) = 6x + 3 \ } (in USD)

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Keywords: the ice skating rink, charges an hourly fee, Gillian rented skates,  the equation represents the cost, C(x), a function of x, the number of hours of skating, a word problem, the single variable equation

Find all numbers such that the square of the number is 48 more than double the number. If you find more than one, then list all the numbers you find in increasing order, separated by commas.?

Answers

Answer:

-6, 8

Step-by-step explanation:

Let the numbers be represented by y

Square of y = y^2

Double y = 2 × y = 2y

Square of the number is 48 more than double the number is written mathematically as

y^2 = 2y +48

y^2 - 2y - 48 = 0

This is a quadratic equation and can be solved by method of factorisation

y^2 -2y - 48 = 0

y^2 + 6y - 8y - 48 = 0

(y^2 + 6y) - (8y - 48) = 0

y(y + 6) - 8(y + 6) = 0

(y + 6)(y - 8) = 0

y = -6, 8

The numbers are -6, 8

Answer:

8, -6

Step-by-step explanation:

Let the number be $n$, so we have $n^2 =48 + 2n$. Rearranging this equation gives $n^2 -2n-48=0$ and factoring gives $(n-8)(n+6)=0$. So, the numbers that fit the problem are $\boxed{n = -6~\text{and}~n = 8}$.

Given ABCDEFGH, what rigid motion,or composition of rigid motions maps ABCD
to EFGH?
I need help
immediately!!!

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