the formula for the area of a rectangle is a=lw , where a is the area, l is the length, and w is the width . a rectangular garden has a length of 10 ft. its width is 6 ft less than its length. what is the area of the garden? 14 ft² 16 ft² 40 ft² 60 ft²
Answers
l=10, w=6
a=10x6
a=60ft^2
so, the answer is 60ft^2
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F(x)=5x + 4When f(x) =54
Find the lengths of two segments whose sum is 45 and whose ratio is 2:3
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There are 8 crackers in 1 serving, 16 crackers in 2 servings, 24 crackers in 3 servings, and so on. How many crackers are in a box of 12 servings?
Answers
The length of the thread for the project in meters is A = 1.54 meters
What is unit conversion?
In order to translate measurements of a particular amount between different units, a mathematical conversion factor is usually used. This modifies the measurement of the quantity without altering its effects.
The particular circumstances or the intended result control the conversion process. This may be governed by law, a contract, a list of technical specifications, or other publicly available standards.
A precise conversion from one system to another is necessary for some measures in order to maintain the precision of both the original measurement and the conversion.
Based on the connection between a particular pair of original units and a particular pair of target units, each conversion factor is chosen.
Given data ,
Let the length of the thread for the project in meters be A
Now , the length of the thread = 154 cm
From the unit conversion , we get
100 cm = 1 m
So , 154 cm = 1.54 m
And , length of the thread for the project in meters A = 1.54 meters
Therefore , the value of A is 1.54 meters
Hence , the unit conversion is solved
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Answers
Answer:
No she is wrong.
Explanation:
Answers
Well the square would be 18+18+13+13 = 62. And the rectangle would be 12+6+12+6 = 36
So combined they would be 62+36 = 98
Area
18 x 13 = 234 for the square and 12 x 6 = 72 for the rectangle which altogether is 234+72= 306
Answer:
368 units
Step-by-step explanation:
Well let’s start with the square.
square)
Dimensions: 18 and 13
Area 18*13 = 234
Perimiter: 18+18+13+13
= 62
234 + 62
= 296
rectangle)
Dimensions: 12 and 6
Area: 12*6 = 36
Perimiter: 12+12+6+6
=36
36 + 36
= 72
72+296
=368
Thus,
the sum of both areas and perimeters is 368units.
Answers
Answer:
1,000g:60sec
or 10 gram every singular second.
Step-by-step explanation:
x – y = 2,342
Solve the system of equations. How many contemporary titles does Jarred have?
1,158
1,737
2,342
2,921
Answers
There are 2,921 contemporary titles does Jarred have.
What is an expression?
Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
His inventory shows that he has a total of 3,500 DVDs.
He has 2,342 more contemporary titles than classic titles.
Let number of contemporary titles = x
Number of classic titles = y
The system of equations are;
⇒ x + y = 3,500
⇒ x - y = 2,342
Solve the system of equations as;
Add equation (i) and (ii) , we get;
2x = 3,500 + 2,342
2x = 5,842
Divide by 2, we get;
x = 5,842 / 2
x = 2,921
Thus, There are 2,921 contemporary titles does Jarred have.
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Answers
60 feet above the water. So what you're really asking is: Calculate whether
the stone can reach 40 feet above Henry, and we can forget about the creek ?
Call Henry's elevation zero, and the height of the stone at any time after
the toss 'H'.
Way back among the pages in your Physics book that are clean and shiny
because they have never yet been exposed to air or sunlight, you will find
the formula for the height of an object in free-fall:
Height = H₀ + V₀t + 1/2 A t²
H₀ = the object's height when it was released
V₀ = the object's speed when it was released, negtive if downward
A = the object's acceleration, negative if downward
t = time since the object was released
In the case that involves Henry on the bridge . . .
H₀ = 0
V₀ = +50 ft/sec
A = -32 ft/sec² (acceleration due to gravity)
We want to know if the height of the object can ever be +40 feet.
We can plug all the numbers into the equation, and solve it. Since the equation
is written in terms of ' t ', any solution we get will be a 'time'. That's not what
we're looking for, but if there's any real solution, then we'll know that it's possible.
40 = 50t + 16t²
Subtract 40 from each side:
16t² + 50t - 40 = 0
Just to make the numbers more manageable, divide each side by 2 :
8t² + 25t - 20 = 0
Plug this into the quadratic formula:
t = (1/16) x (-25 plus or minus the square root of [625 - 640] )
Do you see that 'square root of -15 in there ?
The ' -15 ' is called the 'discriminant' of our quadratic equation, and
since it's negative, our equation has no real solutions ... there's no
such thing as the real square root of a negative number.
So the answer to the question is: No. The stone never reaches a height
of 40 feet above Henry, or 60 feet above the creek.
Whew!
===============================================
A slightly easier way to do it:
Henry throws the stone upward at 50 ft/sec.
The acceleration of gravity is 32 ft/sec² downward.
The stone keeps rising for (50/32) = 1.5625 second, until its upward speed
has shrunk to zero, and then it starts falling.
How high is it when it stops rising ?
Its upward speed was 50 when Henry tossed it, and zero when it stopped rising.
Its average speed on the way up was (1/2)(50 + 0) = 25 ft/sec upward.
It has that average speed for 1.5625 seconds.
How far does it climb in that time ?
H = (25 ft/sec) x (1.5625 sec) = 39.0625 feet.
That's pretty close, but not quite 40 feet above Henry.
So the answer to the question is: No.
K.E.=P.E(at the max height)
1/2mv^2=mgh
m cancels out,
or, h=1/2v^2/g
or, h=1/2*50*50/32
or, h=39 ft (approx.)
As he is 20 ft above water so total height the stone an reach 39+20=59 ft.
Hence, it can't reach 60 ft over the creek.