What is the volume of a cone with a radius of 6 cm and a height of 12 cm? Use 3.14 for pi. Round your answer to the nearest hundredth. (4 points) Group of answer choices 452.16 cm3 465.24 cm3 472.12 cm3 480.50 cm3
Answers
Answer:
The volume of a cone is .
Step-by-step explanation:
We have,
Radius of a cone is 6 cm and its height is 12 cm
It is required to find the volume of a cone. Volume of a cone is given by :
r is radius
h is height
Plugging all the given values in the above formula,
So, the volume of a cone is .
Answer:
The volume of a cone is kp;m
Step-by-step explanation:
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How do i solve this answer ugh please help
Which answer describes this series? 2 + 4 + 12 + 48 +... e) Neither arithmetic nor geometric f) Both arithmetic and geometric g) arithmetic h) geometric
X-2y=3
4xsquared-5xy+6y=3
Answers
4x^2 - 5xy + 6y = 3
lets solve for x the first and substitute in the second:
x = 3 + 2y
4(3 + 2y)^2 - 5(3 + 2y)y + 6y = 3
4(9 + 12y + 4y^2) - 15y - 10y^2 = 3
36 + 48y +16y^2 - 15y - 10y^2 = 3
6y^2 + 33y + 33 = 0
we can solve using the general quadratic formula:
y = (-33 +- √(33^2 - 4*6*33))/12
y = (-33 +- √(297))/12
so there are 2 solutions for y:
y1 = (-33 + √(297))/12
y2 = (-33 - √(297))/12
pick one and then substitute the y value in the first equation to find x
4(3+2y)^2 - 5(3+2y)y + 6y = 3
4(4y^2 + 12y + 9) - 5(3y + 2y^2) + 6y - 3 = 0
16y^2 + 48y + 36 - 15y - 10y^2 + 6y - 3 = 0
6y^2 + 39y + 33 = 0
6y^2 + 6y + 33y + 33 = 0
6y(y+1) + 33(y+1) = 0
(y+1)(6y+33) = 0
y = -1, -11/2
x = 3 + 2y
x = 3 + 2(-1)
x = 3 + 2(-11/2)
x = 1, -8
Equation 2: 3m = 4 + 4n
Step 1:
−3(m) = −3(8 + 2n) [Equation 1 is multiplied by −3.]
3m = 4 + 4n [Equation 2]
Step 2:
−3m = −24 − 6n [Equation 1 in Step 1 is simplified.]
3m = 4 + 4n [Equation 2]
Step 3:
−3m + 3m = −24 − 6n + 4n [Equations in Step 2 are added.]
Step 4:
0 = −24 − 2n
Step 5:
n = −12
In which step did the student first make an error?
Step 4
Step 3
Step 2
Step 1
Answers
Answer:
Step 3
Step-by-step explanation:
Hello
the student made a mistake in the step number 3.
let´s see
in the step number 1 he multiplied by -3 in order to add this new equation with equiation 2 and then eliminate the terms with m
Step one
-3(m)=-3(8+2n)
-3m= -24 - 6 n, it is ok
in step two he simplified, he did it well.
in the step 3 he added the equations
-3m = -24-6n
3m = 4 +4n
_____________
0 = -20-2n
he did not add properly -24+4, here , he made his first mistake.
step 4 is already wrong
continuing..to find n
0= -20-2n
20=-2n
n=-10
Have a great day
Answers
Answer:
Step-by-step explanation:
Let x be the random variable representing the height of players on the football team. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,
z = (x - µ)/(σ/√n)
Where
x = sample mean
µ = population mean
σ = standard deviation
n = number of samples
From the information given,
µ = 74 inches
σ = 1 inch
n = 50
x = 74 inches
the probability that a player is less than 74 inches tall is expressed as
P(x < 74)
For x = 74,
z = (74 - 74)/(1/√50) = 0
Looking at the normal distribution table, the probability corresponding to the z score is 0.5
Therefore,
P(x < 74)
The players less than 74 inches is
0.5 × 50 = 25 players
Answers
Answer:
n o
Step-by-step explanation:
Answer:
Yes.
Step-by-step explanation:
A whole number is a number greater than or equal to zero that does not have any fractions and/or cannot be written with a fractional component. It can also be defined as an integer, though it should be noted that integers include negative numbers. 3, 5, 14, 2, and 0 are all whole numbers and are also all integers. 1.5, 16.32, and -4.598 are not whole numbers and are thus not integers.
Answers
Answer:
Step-by-step explanation:
You have a 10 gallon jug and a 3 gallon jug and need exactly 5 gallons of water.
This what you do:
- Fill the 3 gallons jug full and pour into the 10 gallons keg
- Repeat the above a second time making a total of 6 gallons of water in the 10 gallons jug.
- Fill the 3 gallons jug a third time and pour into the 10 gallons jug making 9 gallons
- Fill the 3 gallons jug the fourth time and pour into the 10 gallons jug till full leaving 2 gallons of water remaining in the 3 gallons jug.
- Then empty out the 10 gallons jug and pour the 2 gallons of water in the 3 gallons jug into the 10 gallons jug.
- Then, fill the 3 gallons jug again and pour into the 10 gallons jug holding the 2 gallons of water making a total of 5 gallons of water in the 10 gallons jug.
Hope, that helps!!!
Answers
a₁ = 43
a₂ = 4² + 3² = 16 + 9 = 25
a₃ = 2² + 5² = 4 + 25 = 29
a₄ = 2² + 9² = 4 + 81 = 85
a₅ = 8² + 5² = 64 + 25 = 89
a₆ = 8² + 9² = 64 + 81 = 145
a₇ = 1² + 4² + 5² = 1 + 16 + 25 = 42
a₈ = 4² + 2² = 16 + 4 = 20
a₉ = 2² + 0² = 4 + 0 = 4
a₁₀ = 4² = 16
a₁₁ = 1² + 6² = 1 + 36 = 37
a₁₂ = 3² + 7² = 9 + 49 = 58
a₁₃ = 5² + 8² = 25 + 64 = 89
As we can see, the first integer that appears twice in the sequence is 89.