MATHEMATICS COLLEGE

What is the least common denominator of the equation StartFraction 2 Over 9 EndFraction x + two-thirds x = 7?

Answers

Answer 1

Answer:

Answer:

the answer is b

Step-by-step explanation:

Answer 2

Answer:

Answer: b

Step-by-step explanation:

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-5 1/2 + 6 3/4 + (-4 1/4)

Answers

Answer:

$-5(1)/(2) +6(3)/(4)+(-4(1)/(4))$

-3 is the answer

On an intramural softball team, the proportion of hits to at bats for the entire team during the last season was 30% of 300 attempts. Estimate the true proportion of hits using a 90% CI. The answers need to be proportions (not percents) and rounded to the nearest hundredth (two (2) decimal places) to be counted as correct. (For example, if my CI is (0.1002, 0.2159) then they need to be input as 0.10 and 0.22 to be correct. **These are not the answers to this question :-) **)The lower bound is____ and the upper bound is ____

Answers

Answer: The lower bound is 0.26 and the upper bound is 0.34.

Step-by-step explanation:

Formula to find the confidence interval for population proportion (p) is given by :_

$\hat{p}\pm z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

z* = Critical value. (two-tailed)

$\hat{p}$ = Sample proportion.

Let p be the true population proportion of hits to at bats for the entire team during the last season.

As per given , we have

n= 300

$\hat{p}=0.30$

By z-table , the critical value for 90% confidence interval : z* = 1.645

Now , 90% confidence interval for the proportion of hits to at bats for the entire team during the last season:

$0.30\pm (1.645) \sqrt{(0.30(1-0.30))/(300)}$

$0.30\pm (1.645) √(0.0007)$

$0.30\pm (1.645) (0.0264575131106)$

$\approx0.30\pm0.0435$

$=(0.30-0.0435,\ 0.30+0.0435)\n\n=(0.2565,\ 0.3435)\approx(0.26,\ 0.34)$

The lower bound is 0.26 and the upper bound is 0.34.

The similar triangle is the image of the bigger triangle after a sequence of transformations. What is the value of x?

Answers

Answer:

The value of x is: 2.5 units

Step-by-step explanation:

Two triangles are said to be similar if the ratio of the corresponding sides of the two triangles are equal.

i.e. if two triangles ΔABC and ΔDEF are similar such that the sides of the triangle ABC are a, b and c and the corresponding sides in ΔDEF are d,e and f respectively then we have:

$(a)/(d)=(b)/(e)=(c)/(f)$

Here we have the base length of the orange i.e. the quadrant above the x-axis as: 8 units

and the base length of the similar triangle i.e. triangle below x-axis as: 4 units.

i.e. we have: a=8 and d=4

and b=5 and e=x

Hence, we have:

$(5)/(x)=(8)/(4)$

i.e.

$x=(5* 4)/(8)$

Hence, we have:

$x=2.5$

We have
$(5)/(x) = (8)/(4) \: so \n 20 = 8x \: so \n x = (20)/(8) = (10)/(4) = (5)/(2) = 2 (1)/(2)$

-3 < 5 true or false

Answers

Answer:

true

Step-by-step explanation:

Answer:

true?

Step-by-step explanation:

Equations
Solve T = C(9+ AB) for B

Answers

Answer:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

T = (forAB2C + 9forBC)

Solving

T = forAB2C + 9forBC

Solving for variable 'T'.

Move all terms containing T to the left, all other terms to the right.

Simplifying

T = forAB2C + 9forBC

Step-by-step explanation:

Simplifying

T = C(9 + AB) * forB

Reorder the terms for easier multiplication:

T = C * forB(9 + AB)

Multiply C * forB

T = forBC(9 + AB)

T = (9 * forBC + AB * forBC)

Reorder the terms:

17.Find the value of k that will make 4x² – 12x + k a perfect square trinomial.
k =
Enter your next step here
-
G
O Tool

Answers

Solution:

Using formula (a-b)^2 = a^2-2ab+b^2

$4x^(2) - 12x + k \n = > (2x) ^(2) - 2(2x)(3) + {3}^(2) \n \n = > {(2x)}^(2) - 2(2x)(3) + 9$

Answer:

k = 9

Answer:

Using formula (a-b)^2 = a^2-2ab+b^2

4x 2 −12x+k

=>(2x) 2 −2(2x)(3)+3 2

=>(2x) 2 −2(2x)(3)+9

=> k = 9

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