PHYSICS COLLEGE

Shameeka is studying for an exam she took the notable about calcium and chlorine which are known to for my comic born's which shameekas error?

Answers

Answer 1

Answer: The individual calcium atom has a positive and not negative, 2 charge

Answer 2

Answer:

Answer:

The individual calcium atom has a positive, not negative, 2 charge.

Explanation:

Did the quiz also had it on the unit test on edgunity.

Hope this helps guys!

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Solve for x
–30 = 5(x + 1)

Answers

Answer:

-30=5(x+1) is -7

Explanation:

distribute flip subtract 5 from both sides divide both sides by 5

-30=(5)(x)+(5)(1) (Distribute)
-30=5x+5
Flip equation
5x+5=-30
Subtract 5 from both sides
5x+5-5=-30-5
5x=-35
Divide both sides by 5
X=-7

At one instant, a 17.0-kg sled is moving over a horizontal surface of snow at 4.10 m/s. After 6.15 s has elapsed, the sled stops. Use a momentum approach to find the magnitude of the average friction force acting on the sled while it was moving.

Answers

Answer:

force = 11.33 $kg-m/s^(2)$

Explanation:

given data:

sled mass = 17.0 kg

inital velocity (U) = 4.10 m/s

elapsed time (T) 6.15 s

final velocity (V) = 0

final momentum P2 = 0

Initial momentum of sledge is

$P_(1)=mU$

$P_(1)= 17.0 * 4.10 = 69.7 kg- m/s$

from newton second law of motion

$F=(\Delta P)/(\Delta t)$

$F = (P_(1)-P_(2))/(T)$

Kgm/s^2

$F = (69.7-0)/(6.15)= 11.33[tex]kg-m/s^(2)$ [/tex]

How long would it take a 500. W electric motor to do 15010 J of work?

Answers

time = energy / power = 15010 / 500 = .... seconds

1. A surfboarder rides a wave for 23.7 m at a constant rate of 4.1 m/s. How long did his triptake?

Answers

Answer:

His trip took 5.78 seconds

Explanation:

23.7m divided by 4.1m/s = 5.78048780488

Guitar string has an overall length of 1.22 m and a total mass of 3.5 g before being strung on a guitar. Once it is used on the guitar, there is a distance of 70 cm between fixed end points. The guitar string is tightened to a tension of 255 N.What is the frequency of the fundamental wave on the guitar string?

Answers

Answer:

Fundamental frequency= 174.5 hz

Explanation:

We know

fundamental frequency= $(velocity)/(2 *length)$

velocity = $\sqrt{(tension)/(mass per unit length) }$

mass per unit length= $(3.5)/(1000*1.22)$ =0.00427 $(kg)/(m)$

Now calculating velocity v= $\sqrt{(255)/(0.00427) }$

=244.3 $(m)/(sec)$

Distance between two nodes is 0.7 m.

Plugging these values into to calculate frequency

f = $(244.3)/(2 *0.7)$ =174.5 hz

The predictions of Rutherford's scattering formula failed to correspond with experimental data when the energy of the incoming alpha particles exceeded 32MeV32MeV. This can be explained by the fact that the predictions of the formula apply when the only force involved is the electromagnetic force and will break down if the incoming particles make contact with the nucleus. Use the fact that Rutherford's prediction ceases to be valid for alpha particles with an energy greater than 32MeV32MeV to estimate the radius rrr of the gold nucleus.

Answers

Answer:

r = 7.1 × 10⁻¹⁵

Explanation:

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After a package is dropped from the plane, how long will it take for it to reach sea level from the time it is dropped? assume that the package, like the plane, has an initial velocity of 342 km/hour in the horizontal direction. express your answer numerically in seconds. neglect air resistance.

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