Which of these best orders the rock layers from the youngest to the oldest? (1 point)1) Layer A - Layer B – Layer C – Layer D
O2) Layer A - Layer D - Layer B - Layer C
O 3) Layer D - Layer C - Layer B - Layer A
4) Layer D - Layer A - Layer C - Layer B
Which of these best orders the rock layers from the - 1

Answers

Answer 1
Answer:

Answer:

D-C-B-A

Explanation:

Oldest crust on the bottom

Answer 2
Answer: 3) layer D, layer C, layer B, layer A

Related Questions

After double fertilization, a zygote and ________ form.an ovuleendosperma cotyledona suspensor
Which describes the particle or particles that are in the nucleus of anatom? *1. proton and electron2.electron only3.electron and neutron4.neutron and proton
You are an aspiring botanist and decide to study some orchid genetics. Knowing that the pink color phenotype is an incompletely dominant phenotype, you decide to study it further. You discover that when you cross two pink orchids, you only ever obtain a phenotypic ratio of 1/3 white orchids to 2/3 pink orchids. How might you explain this phenomenon
Which of the following processes is/are example(s) of diffusion and/or osmosis that occur in your cells? Mark all that applya. O2/CO2 moving in/out of your blood cells as they flow through your lungs. b. Na+ (sodium) & K+ (potassium) ions moving between the inside and outside of you nerve cells creating electrical impulses. c. H2O moving in and out of all your cells to maintain homeostasis. d. All of the above e. None of the above
When neither gene in a genotype pair is dominant and neither gene is recessive, the genes are said to be

Label the brain parts

Please help me with this assignment

Answers

Answer:

A = parietal labe | B = gyrus of the cerebrum | C = corpus callosum | D = frontal lobe

E = thalamus | F = hypothalamus | G = pituitary gland | H = midbrain

J = pons | K = medulla oblongata | L = cerebellum | M = transverse fissure | N = occipital lobe

 

Explanation:

hope this helppss

You have a culture of yeast that is at a concentration of 6.74 x 10^6 cells/ml. You dilute the sample 1:100, and then 1:100 again, and finally you dilute the sample an additional 1:3. You add 0.1 ml of the final dilution to a spread plate. 1. Assuming that most of the cells in the original culture were living, how many CFUs do you expect to count on your spread plate the next day?

Answers

Answer:

22 cells

Explanation:

The concentration of numbers of cells = 6.74 x 10⁶ cells/ml

Dilution stages includes =  1:100  ;     1:100    &        1:3

The consecutive dilution stages can be calculated as:

= (6.74 x 10⁶) × (1/100)(1/100)(1/3)

=  222.42 cells/ml

= 2.22 × 10² cells/ml

So after addition  0.1 ml of the final dilution to a spread plate, the number of CFUs ( Colony forming units) we expect to count will be:

= (2.22 × 10² cells/ml)(0.1 ml)

= 22.2 cells

≅ 22 cells.

what is a gamete A. a diploid cell that split during meiosis B.the number of chromosomes in a cell C. a haploid cell produced by meiosis D. two sets of sister chromatids

Answers

Answer:

C. a haploid cell produced by meiosis

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During photosynthesis, the energy from sunlight is used to split water molecules. What happens to the hydrogen ions that are
split from the water molecules?

Answers

Answer: hydrogen is incorporated into glucose

Explanation:

6CO2 + 6H2O —> C6H12O6 + 6O2

How many ATP and NADPH molecules are required in the C3 pathway to make one six-carbon sugar? If the synthesis of a molecule of ATP were to require four protons, would you expect that these relative requirements for ATP and NADPH could be met by noncyclic photophosphorylation in the absence of cyclic photophosphorylation?

Answers

Answer:

The correct answer is 18 ATP and 12 NADPH and noncyclic photophosphorylation can produce ATP molecule in the absence of cyclic photophosphorylation.

Explanation:

ATP and NADPH molecules are synthesized during light reaction of the photosynthesis which is utilized during the reactions of the dark phases. Dark reaction or Calvin cycle (C3 cycle) is the cyclic pathway of producing glucose triose phosphates (3C) from carbon dioxide and water. This reaction proceeds into 3 phases: carboxylation, reduction and regeneration.

First ATP and NADPH are utilized during the reduction step in the reduction of 3-phosphoglycerate to glucose-3-phosphate by the transfer of phosphate group from 6 ATP to 3-phosphoglycerate and 6 NADPH reduction as it donates an electron. Regeneration step also uses 3 ATP in conversion of G3P to RUBP molecules.  

A total of 9 ATP and 6 NADPH are utilized in producing 3C G3P molecule, So, to produce 6C sugar molecule 18 ATP AND 12 NADPH are used.

During chemiosmosis synthesis of ATP, 4 protons produce 1 molecule of ATP which could be able to generate 3 molecules of ATP for each pair of NADPH. so, noncyclic photophosphorylation or Z-scheme will be able to produce ATP in the absence of cyclic photophosphorylation.

Thus, 18 ATP and 12 NADPH and noncyclic photophosphorylation can produce ATP molecule in the absence of cyclic photophosphorylation are the correct answer.

The phase of mitosis that is characterized by the disappearance of the nuclear membrane is

Answers

Answer:

Prometaphase (late prophase)

Explanation:

Mitosis is the kind of cell division in which two genetically identical copies of a cell is formed from a cell. Mitosis comprises of stages which include prophase, metaphase, anaphase and telophase. Each phase is characterized by specific occurrences that all work together to achieve the main goal of forming two daughter cells.

According to this question, PROPHASE stage is the stage characterized by the condensation of chromatids into chromosomes, the disappearance of nucleolus and BREAKDOWN of NUCLEAR MEMBRANE.