if the range of the function f(x)=x/4 is {28,30,32,34,36}, what is its domain?a. {112, 120, 128, 136, 144}b. {118, 122, 124, 132, 145}c. {110, 118, 122, 124, 137}d. {111, 124, 128, 132, 146}

Answers

Answer 1

Answer: $f(x)=(x)/(4)\to y=(x)/(4)\to x=4y\n\ny\in\{28;\ 30;\ 32;\ 34;\ 36\}\n\n4\cdot28=112\n4\cdot30=120\n4\cdot32=128\n4\cdot34=132\n4\cdot36=144\n\nAnswer:D=\{112;\ 120;\ 128;\ 136;\ 144\}\to\fbox{a.}$

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Find the value of 8.3 times 24.2

Answers

8.3 times 24.2 is 200.86

24.2 * 8.3 = 200.86
All you need to do is use a calculator or a piece of paper to answer this qeustion. Just multiply the numbers.

Two lighthouses flash their lights every 20 seconds and 30 seconds respectively. Given that they flash together at 8 p.m, when will they next flash together?

Answers

The first one will flash at every 30 sec and the second one at 20 sec. The second one will go like 1- 4- 8 and then to 12. By the time the second one will reach first at 6 and then on 12. So, after every 1 minute they will flash together.

On a scale drawing of a fence, 3.75 inches represent 24 feet. What is the actual length of a second fence that is 2.8 inches in the drawing?

Answers

The actual length of the fence is 215 inches

Step-by-step explanation:

Length of fence in drawing = 3.75 inches

Actual length of the fence = 24 ft

= 288 inches

Scale factor = 288/3.75

= 76.8

Length of fence in drawing = 2.8 inches

Actual length = 2.8 x 76.8

= 215 inches

The actual length of the fence is 215 inches

Answer:

215 in

Step-by-step explanation:

215 in

Solve: 16x2 − 81 = 0.x = 4, 9
x = −4, −9
x = 9 over 4, x = −9 over 4
x = 81 over 16, x = −81 over 16

Answers

If you would like to solve 16x^2 - 81 = 0, you can calculate this using the following steps:

16x^2 - 81 = 0
(4x - 9) * (4x + 9) = 0
1. 4x - 9 = 0 ... 4x = 9 ... x = 9/4
2. 4x + 9 = 0 ... 4x = - 9 ... x = - 9/4

The correct result would be: x = 9 over 4, x = −9 over 4.

Please look at picture answer and explain work

Answers

Answer: The answer is D. 240 grams

Step-by-step explanation:

1. Find the volume.

2cm×3cm×5cm=30 cubic centimeters

2. Find the volume of the other box.

4cm×9cm×5cm=180 cubic centimeters.

3. Divide. 180÷30=6

4. 6 times the amount it can hold, 40=240 grams of clay.

Hope that helped!

Answer:

Step-by-step explanation:

we are told that the box is 2 cm high, 3 cm wide 5 cm long and holds 40 grams of clay

so 2*3*5 = 30 $cm^(3)$

so the 30 cubic centimeter volume holds 40 grams ( it would have been nice if they had let the box hold 30 grams but, no :(

40/30 = 1.333333 or 1 and $(1)/(3)$ of a gram okay, sooooo now we know each cubic centimeter holds that much clay, now let's solve for how many cubic centimeters are in the bigger box, you can try to solve it 1st if you'd like to practice, below I solve it