PHYSICS COLLEGE

A curve of radius 35 m isbanked; therefore, no friction
is required at a speed of 7
m/s of a car. What is the?
banking angle


​

Answers

Answer 1
Answer:

Answer:

The banking angle is 23.98 degrees.

Explanation:

We have,

Radius of a curve is 35 m

Speed of a car is 7 m/s

It is required to find the banking angle. At equilibrium, net force is equal to the centripetal force between vehicle and the road such that the banking angle is given by :

\tan\theta=(v^2)/(rg)

g is acceleration due to gravity

\tan\theta=(7^2)/(35* (22)/(7))\n\n\theta=\tan^(-1)\left(0.445\right)\n\n\theta=23.98^(\circ)

So, the banking angle is 23.98 degrees.

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What electric field strength would store 12.5 JJ of energy in every 6.00 mm3mm3 of space?

Answers

To develop this problem we will apply the concepts related to the potential energy per unit volume for which we will obtain an energy density relationship that can be related to the electric field. From this formula it will be possible to find the electric field required in the problem. Our values are given as

The potential energy,  U = 13.0 J

The volume,  V = 6.00 mm^3 = 6.00*10^(-9)m^3

The potential energy per unit volume is defined as the energy density.

u = (U)/(V)

u= ((13.0 J))/((6.00*10^(-9) m^3))

u= 2.167109 J/m^3

The energy density related with electric field is given by

u = (1)/(2) \epsilon_0 E^2

Here, the permitivity of the free space is

\epsilon_0 = 8.85*10^-{12} C^2/N \cdot m^2

Therefore, rerranging to find the electric field strength we have,

E = \sqrt{(2u)/(\epsilon_0)}

E = \sqrt{(2(2.167109))/(8.85*10^(-12))}

E = 2.211010 V/m

Therefore the electric field is 2.21V/m

Final answer:

To calculate the electric field strength that would store 12.5 Joules of energy in every 6.00 mm^3 of space, we use the energy density formula. We firstly find the energy density and input it into the formula to solve for the electric field strength. The result is approximately 6.87 X 10^6 N/C.

Explanation:

The energy stored in an electric field is given by the formula U = 1/2 ε E^2. Here, U is the  energy density (energy per unit volume), E is the electric field strength, and ε is the permittivity of free space.  

Given that the energy stored U is 12.5 joules, and the volume is 6.00 mm^3 or 6.00X10^-9 m^3, the energy density (U) can be computed as 12.5 J/6.00X10^-9 m^3 = 2.08X10^12 Joule/meter^3.

We can solve the formula for E (electric field strength): E = sqrt ((2U)/ε). Substituting the value of ε (8.85 × 10^-12 m^-3 kg^-1 s^4 A^2), we can find E to be approximately 6.87 X 10^6 N/C.

Learn more about Electric Field Strength here:

brainly.com/question/1812671

#SPJ3

Air is a good conductor of heat. Please select the best answer from the choices provided T F

Answers

If air were a good conductor of heat" then soup will not stay hot for longer because this time convection+conduction will both help to transfer heat away from soup. Because conduction is the transfer of heat through a substances as a result of neighbouring vibrating particles, The particles in air are far apart.

the answer is false. Hope this helps

An object having a net charge of 25.0 µC is placed in a uniform electric field of 620 N/C directed vertically. What is the mass of this object if it "floats" in the field?

Answers

Answer:

Mass of the object, m=1.58* 10^(-3)\ kg

Explanation:

It is given that,

Charge on an object, q=25\ \mu C=25* 10^(-6)\ C

Electric field, E = 620 N/C

We need to find the mass of this object. Let m is the mass of the object. It can be calculated as :

ma=qE

m=(qE)/(a), here a = g (as it is vertically downward)

m=(25* 10^(-6)* 620)/(9.8)

m = 0.00158 kg

m=1.58* 10^(-3)\ kg

So, the mass of the object is 1.58* 10^(-3)\ kg. Hence, this is the required solution.

A 75-m-long train begins uniform acceleration from rest. The front of the train has a speed of 18 m/swhen it passes a railway worker who is standing 125 m from where the front of the train started. What will be the speed of the last car as it passes the worker?

Answers

Answer:22.76 m/s

Explanation:

Given

Train length(L)=75 m

Front of train after travelling 125 m is 18 m/s

Time taken by the front of train to cover 125 m

v^2-u^2=2as

18^2-0=2* a* 125

a=1.296 m/s^2

Speed of the last part of train when it passes the worker i.e. front of train has to travel has to travel  a distance of 125+75=200 m

v^2-u^2=2as

v^2=2* 1.296* 200

v=√(518.4)=22.76 m/s

A baseball leaves the bat with a speed of 40 m/s at an angle of 35 degrees. A 12m tall fence is placed 130 m from the point the ball was struck. Assuming the batter hit the ball 1m above ground level, does the ball go over the fence? If not, how does the ball hit the fence? If yes, how far beyond the fence does the ball land?

Answers

Answer:

The ball land at 3.00 m.

Explanation:

Given that,

Speed = 40 m/s

Angle = 35°

Height h = 1 m

Height of fence h'= 12 m

We need to calculate the horizontal velocity

Using formula of horizontal velocity

V_(x)=V_(i)\cos\theta

V_(x)=40*\cos35

V_(x)=32.76\ m/s

We need to calculate the time

Using formula of time

t = (d)/(v)

t=(130)/(32.76)

t=3.96\ sec

We need to calculate the vertical velocity

v_(y)=v_(y)\sin\theta

v_(y)=40*\sin35

v_(y)=22.94\ m/s

We need to calculate the vertical position

Using formula of distance

y(t)=y_(0)+V_(i)t+(1)/(2)gt^2

Put the value into the formula

y(3.96)=1+22.94*3.96+(1)/(2)*(-9.8)*(3.96)^2

y(3.96)=15.00\ m

We need to calculate the distance

s = y-h'

s=15.00-12

s=3.00\ m

Hence, The ball land at 3.00 m.

Enter your answer in the provided box. In water conservation, chemists spread a thin film of certain inert materials over the surface of water to cut down on the rate of evaporation of water in reservoirs. This technique was pioneered by Benjamin Franklin three centuries ago. Franklin found that 0.10 mL of oil could spread over the surface of water of about 32.0 m2 in area. Assuming that oil forms a monolayer (that is, a layer that is only one molecule thick) estimate the length of each oil molecule in nanometers. Assume that oil molecules are roughly cubic. (1 nm = 1 × 10−9 m)

Answers

Answer:

≅3.2 nm

Explanation:

Using the converter units as know for this case that:

1 ml is 1 cubic centimeter  ⇒   0.1 ml is 0.1 cubic centimeters

32.0 m² so :

32.0 m² *100 *100 cm²   ⇒ 0.1 / ( 32.0 * 100 *100 )  = 100,000,000 * 0.1  /  (32.0 * 100 * 100 ) nm

v = 100/32.0 nm = 3.125 nm thick.

v ≅3.2 nm

As oil is one molecule thick and the molecules are cubic, length of each oil is 3.2 nm
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