Lee and Celia are lab partners. While Celia pours a chemical into a graduated cylinder, some of the chemical splashes onto her arm. what should they do next? A. Lee should continue working with Celia after helping wipe off her arm. B. Lee should tell the teacher what happened to Celia when he leaves the lab. C. Lee should tell the teacher while Celia washes her arm with soap and water. D. Lee should have Celia stand in the safety shower while another student tells the teacher.

Answers

Answer 1
Answer: I think the best answer from the choices listed above is option C. With this accident, both should be alert and do what should be done.  Lee should tell the teacher while Celia washes her arm with soap and water. Doing this, Celia will prevent the chemical to spread more and harm further. Telling the teacher immediately will also alert the in-charge and do what should be done.

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The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine. Cl2 ⇌ 2Cl (fast, reversible) Cl + CHCl3 → HCl + CCl3 (slow) Cl + CCl3 → CCl4 (fast) What rate law does this mechanism predict? (Choose from the list below and enter your answers in alphabetical order, e.g. ABC ).

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Answer:

Explanation:

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The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine.Cl2 ⇌ 2Cl (fast, reversible) Cl + CHCl3 → HCl + CCl3 (slow) Cl + CCl3 → CCl4 (fast) What rate law does this mechanism predict?A)kG) [CHCl3]1/2M) [CCl3]2B) [Cl2]H) [CCl3]1/2N) [HCl]2C) [Cl]I) [HCl]1/2O) [Cl2]2D) [CHCl3]J) [Cl2]1/2P) [Cl]2E) [CCl3]K) [Cl]1/2 F) [HCl]L) [CHCl3]2

The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine.Cl2 ⇌ 2Cl (fast, reversible) Cl + CHCl3 → HCl + CCl3 (slow) Cl + CCl3 → CCl4 (fast) What rate law does this mechanism predict?A)kG) [CHCl3]1/2M) [CCl3]2B) [Cl2]H) [CCl3]1/2N) [HCl]2C) [Cl]I) [HCl]1/2O) [Cl2]2D) [CHCl3]J) [Cl2]1/2P) [Cl]2E) [CCl3]K) [Cl]1/2 F) [HCl]L) [CHCl3]2

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Asked Oct 30, 2019

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The following mechanism has been proposed for the gas-phase reaction of chloroform (CHCl3) and chlorine.

Cl2 ⇌ 2Cl (fast, reversible)

Cl + CHCl3 → HCl + CCl3 (slow)

Cl + CCl3 → CCl4 (fast)

What rate law does this mechanism predict?

A)k G) [CHCl3]1/2 M) [CCl3]2

B) [Cl2] H) [CCl3]1/2 N) [HCl]2

C) [Cl] I) [HCl]1/2 O) [Cl2]2

D) [CHCl3] J) [Cl2]1/2 P) [Cl]2

E) [CCl3] K) [Cl]1/2

F) [HCl] L) [CHCl3]2

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Expert Answer

Step 1

The three step mechanism of the given reaction is,

CL2 dissociate to give chorine a fast and reverse reaction.

React with CHCL3 to give HCL and CCL3 a slow reaction

React with CL to give CCL4.

Step 2

Add equation (1), (2), and (3) to get the overall reaction.

The overall reaction is expressed as,

CL2 dissociate to give chorine a fast and reverse reaction.

React with CHCL3 to give HCL and CCL3 a slow reaction

React with CL to give CCL4.

Step 3

The chlorine atom produced in equation (1) is consumed in equation (3) and CCl3 a molecule is produced in equation (2) is consumed in equation (3).

CL react with CHCL3 to give a reversible reaction of HCL and CCL4.

Which region of the visible light spectrum bends the most when passed through a diffraction grating?Red
Yellow
Green
Blue

Answers

Answer:

Red

Explanation:

Red is diffracted the most due to its long wavelength. Compared to violet which is the shortest and is diffracted the least.

You wash dishes for a chemistry laboratory to make extra money for laundry. You earn 12 dollars/hour, and each shift lasts 75 minutes. Your laundry requires 12 quarters/load. How many loads of laundry will each shift pay for if the cost per load rises to 16 quarters?

Answers

You calculate the amount of loads of laundry as follows:

((6 x 0.25)/ load) x 10 loads = 15.00 total cost required for laundry 

(6.00 / 60 min) x (75 min/shift) = 7.50 cost / shift 

15.00 / (7.50 / shift) = 2 loads of  laundry

Hope this answers the question.

Each shift worked can pay for 3.75 loads of laundry if each load costs 16 quarters.

Further Explanation

This problem can be solved using simple dimensional analysis. The steps are:

  1. Sort the given. Identify the conversion factors or equalities that may be used. Identify what is required.
  2. Set up the dimensional analysis ensuring that units cancel out until only the desired unit is left. The equalities in the problem may be used as conversion factors.

STEP 1: Sort first the given in the problem to identify possible conversion factors to be used in the dimensional analysis.

The following equalities are given in the problem:

  • 1 shift = 75 minutes
  • 12 dollars = 1 hour
  • 1 load = 16 quarters
  • 1 dollar = 4 quarters

STEP 2: From these equalities, the following dimensional analysis can be set up:

no. \ of \ load \ = 1 \ shift * (75 \ min)/(1 \ shift) * {(1 \ hr)/(60 \ min) * (12 \ dollars)/(1 \ hr) * { (4 \ quarters)/(1 \ dollar) * (1 \ load)/(16 \ quarters)

no. \ of \ load \ = 3.75 \ load

Therefore, one shift can pay for 3.75 loads of laundry.

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Keywords: dimensional analysis, problem solving

Hydrochloric acid (HCl) is combined with cesium hydroxide (CsOH) in a neutralization reaction. Which ions will combine to form a salt? Check all that apply.H+
H3O+
Cl-
Cs+
OH-

Answers

HCl + CsOH --> CsCl + H2O

So the ions making up the salt: Cl- and Cs+

Answer:

The answers are C and D

Explanation:

Which of the following circumstances will result in a reaction that is spontaneous only at low temperatures?A.) positive enthalpy change and positive entropy change
B.) negative enthalpy change and negative entropy change
C.) positive enthalpy change and negative entropy change
D.) negative enthalpy change and positive entropy change

Answers

Answer: B.) negative enthalpy change and negative entropy change

Explanation:

According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy  

\Delta H = enthalpy change

\Delta S = entropy change  

T = temperature in Kelvin

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

Thus when \Delta H = -ve

\Delta S = -ve

\Delta G=(-ve)-T(-ve)

\Delta G=(-ve)(+ve)=-ve   only at low temperature

Reaction is spontaneous only if temperature is low.

D) negative enthalpy and positive entropy,
since the formula G=H-TS when a reaction is spontaneous then G must be negative, and if values of t are low then the only time it is guaranteed to be a negative G value is if H is positive and S is negative

A mixture of two gases has a total pressure of 5.7 atm . If one gas has a partial pressure of 4.1 atm , what if the partial pressure of the other gas ?

Answers

Answer:

1.6 atm

Explanation:

We are given that total pressure of mixture of two gases=5.7 atm

Partial pressure of one gas=4.1 atm

We have to find the partial pressure of other branch.

We know that Dalton;s law of partial pressure

It states that pressure exerted by mixture of gases is equal to sum of partial pressure exerted by  gases in mixture.

Let x bet the pressure exert by other gas

Apply this law

Total pressure=4.1+x

5.7=4.1+x

x=5.7-4.1=1.6

Hence, the partial pressure of other gas=1.6 atm.

if the two gases has a total pressure of 5.7 atm and one of the gases has a partial pressure of 4.1 the the other one has the pressure of 1.6