MATHEMATICS COLLEGE

en una canasta se tienen 10 bolas cafes, 5 bolas azules y 15 verdes. Si se saca una al azar, ¿cual es la probabilidad de que esta no sea azul? ¿cual es probabilidad de que sea verde?

Answers

Answer 1

Answer:

Answer:

The probability that the selected ball is not blue is $(5)/(6)$ .

The probability that the selected ball is green is $(1)/(2)$ .

Step-by-step explanation:

The question is:

There are 10 brown balls, 5 blue balls and 15 green balls in a basket. If one is drawn at random, what is the probability that it is not blue? What is the probability that it is green?

Solution:

The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.

$P(E)=(n(E))/(N)$

The probability of the given event not taking place is known as the complement of that event.

Complement of the event E is,

1 – P (E)

The number of different color balls are as follows:

Brown = n (Br) = 10

Blue = n (Bu) = 5

Green = n (G) = 15

Total = N = 30

Compute the probability of selecting a blue ball as follows:

$P(\text{Bu})=\frac{n(\text{Bu})}{N}=(5)/(30)=(1)/(6)$

Compute the probability of not selecting a blue ball as follows:

$P(\text{Not Bu})=1-P(\text{Bu})$

$=1-(1)/(6)\n\n=(6-1)/(6)\n\n=(5)/(6)$

Thus, the probability that the selected ball is not blue is $(5)/(6)$ .

Compute the probability of selecting a green ball as follows:

$P(\text{G})=\frac{n(\text{G})}{N}=(15)/(30)=(1)/(2)$

Thus, the probability that the selected ball is green is $(1)/(2)$ .

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Ordered pair of -x+3y=9

Simplify 3x/4 X 4y/2

Answers

3xy / 20

Aaaaaaaaaaaaaaaaaaaaaaa

I am not understanding this question.

Answers

Answer:

boardgamegeek.com/boardgame/245655/kings-dilemma

Step-by-step explanation:

Which ordered pairs are solutions to the inequality −2x+y≥−4 ?Select each correct answer.

(0, −5)

(3, −1)

(1, −2)

(0, 1)

(−1, 1)

Answers

Answer:

(0,-5) , (1,-2) , (0,1) and (-1,1)

Step-by-step explanation:

-2x + y ≥ -4

y ≥ 2x - 4

Taking a point (0,-5):

-5 ≥ 0 - 4 , 5 ≥ -4

This situation is true.

Taking a point (3,-1):

-1 ≥ 2(3) - 4 , -1 ≥ 2

This situation is not true.

Taking a situation (1,-2):

-2 ≥ 2(1) - 4 , -2 ≥ -2

This situation is true.

Taking a point (0,1):

1 ≥ 0 - 4 , 1 ≥ -4

This situation is true.

Taking a point (-1,1):

1 ≥ 2(-1) - 4 , 1 ≥ -6

This situation is true.

The correct answers are

(−1, −1)

(5, −12)

(0, 1)

Have a nice day!

The director of student health at a large university was concerned that students at his school were consuming too many calories each day. For a certain population of college-age students, it is recommended to consume around 2,000 calories/day. The director would like to test the hypothesis that H0:μ=2000 vs. HA:μ>2000. In a random sample of 50 students the director found that the average was 2105 calories/day with a standard deviation of 288 calories/day. Calculate the appropriate test statistic for this situation. Round your answer to 3 decimal places.

Answers

Answer:

The calculated test statistic is 2.578

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 2,000 calories/day

Sample mean, $\bar{x}$ = 2105

Sample size, n = 50

Alpha, α = 0.05

Sample standard deviation, s = 288

First, we design the null and the alternate hypothesis

$H_(0): \mu = 2000\text{ calories per day}\nH_A: \mu > 2000\text{ calories per day}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_(stat) = \displaystyle\frac{\bar{x} - \mu}{(\sigma)/(√(n)) }$

Putting all the values, we have

$t_(stat) = \displaystyle(2105 - 2000)/((288)/(√(50)) ) = 2.578$

Thus, the calculated test statistic is 2.578

Answer:

Test statistics = 2.578

Step-by-step explanation:

We are given that the director of student health at a large university was concerned that students at his school were consuming too many calories each day. For a certain population of college-age students, it is recommended to consume around 2,000 calories/day.

Also, given Null Hypothesis, $H_0$ : $\mu$ = 2000