Simplify for 2 points cosx + cos(180º -x)

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Answer 1

Answer: cos x+ cos(180-x)
=cos x + (cos 180)(cosx) +sin(180)(sinx))
=cos x+{-1(cos x)+0(sinx)
Note cos 18 $0^(o)$ =-1 sin 18 $0^(o)$
= cos x-cos x
=0

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Please help with number 1 please ?

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It's asking you to set -x and x equal to each other...

-x = x
2x = 0
x = 0.

Evaluate limit as x approaches 0 sin^2x/(1-cosx).

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$\lim_(x \to 0) (sin ^(2)x )/(1-cos x) = ( (0)/(0) )= \n = \lim_(x \to 0) (1-cos ^(2)x )/(1-cosx)= \n = \lim_(n \to 0) ((1+cosx)(1-cosx))/((1-cosx))= \n = \lim_(x \to 0) (1+cos x) =$
= 1 + cos 0 = 1 + 1 = 2

AB¯¯¯¯¯ and BC¯¯¯¯¯ are tangent to ⊙ O. Identify BC.

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Answer:

Step-by-step explanation:

$2(3x-7)=4x+8\nx=11\n4(11)+8=52$

A phone company uses the equation y=0.15x+10 to find y the monthly charge for a customer sending x text messages. How many text messages are sent if the monthly charge is $77.50?

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y=0.15.77.5+10 y=11.62+10 y=21

Given the function f ( x ) = − 1 x + 3 x 4 , f(x)=− x 1 + 4 3 x , find f ′ ( 4 ) . f ′ (4). Express your answer as a single fraction in simplest form.

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Step-by-step explanation:

The question is not well written. Let us say the function given as expressed as;

f(x) = -1/x + 3/x⁴

f'(x) means we are to differentiate the function with respect to x;

Given f(x) = axⁿ

f'(x) = naxⁿ⁻¹

f(x) = -x⁻¹ + 3x⁻⁴

Applying the differentiation formula we will have;

f'(x) = -1(-x⁻²)+(-4)3x⁻⁴⁻¹

f'(x) = x⁻²-12x⁻⁵

Express as a fraction

f'(x) = 1/x²-12/x⁵

To get f'(4), we will have to substitute x = 4 into the resulting expression

f'(4) = 1/4²-12/4(5)

f'(4) = 1/16-12/20

f'(4) = 1/16-3/5

Find the LCM

f'(4) = (5-48)/80

f'(4) = -43/80

Note that the function used was assumed but the same method can be employed to any other functions.

Round 38217 to 2 significant figures

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38000 rounded to two significant figures

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