MATHEMATICS HIGH SCHOOL

Raj is visiting the United States and needs to convert 2,000 rupees to US dollars.

Answers

Answer 1

Answer:

The first thing we must do for this case is to find the conversion of rupees to US dollars.

Currently, the conversion is:

1 rupee = 0.014 $

Then, to find the amount of $ in 2000 rupees, we make the following rule of three:

1 rupee -----------------> 0.014 $

2000 rupees ----------> x

From here, we clear the value of x.

We have then:

$x = (2000) * (0.014) x = 28$

Answer:

2,000 rupees are 28 US dollars.

Answer 2

Answer:

2,000 Indian Rupees is equivalent to 24 United States Dollars.

To convert 2,000 Indian Rupees to United States Dollars, you can multiply the amount in rupees by the conversion rate.

In this case, since 1 Indian Rupee equals 0.012 United States Dollars, the conversion can be calculated as follows:

2,000 Indian Rupees x 0.012 United States Dollars/Indian Rupee = 24 United States Dollars

Therefore, 2,000 Indian Rupees is equivalent to 24 United States Dollars.

Learn more about conversion rate click;

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Find the difference. (2x^2 - 3x + 7) - (x^2 + 6x - 12)A) A) x^2 + 3x - 5

B) x^2 - 3x + 19

C) x^2 - 6x + 12

D) x^2 - 9x + 19

Answers

Its D.

(2x^2 - 3x + 7) - (x^2 + 6x - 12)

Distribute the negative over the second parentheses:-

= (2x^2 - 3x + 7) - x^2 - 6x + 12

= x^2 - 9x + 19 (answer)

line AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to line AB ?

Answers

Since the line is parallel to AB, the two slopes are the same

slope of AB = m = (y₂-y₁)/(x₂-x₁)

m= (5-0)/(-6-(-3))= - 5/3
The equation of the line is y-y₁=m(x-x₁)
The origin P(0,0)
y=mx
y= - $(5)/(3)$ x Solution

-2(a-8)+6a=36
what's the value of a
A=

Answers

Distribute -1 into the brackets.
-2(a - 8) + 6a = 36
-2a + 16 + 6a = 36
Take 16 to the other side
-2a + 6a + 16 = 36
- 16 -16
-2a + 6a = 36 - 16
Combine like terms
4a = 20
Divide by 4 on either sides to isolate a
$(4a)/(4) = (20)/(4)$
4 and 4 cancels out.
a = 5

Jonathan has been on a diet since January 2013. So far, he has been losing weight at a steady rate. Based on monthly weigh-ins, his weight, w, can be modeled by the function w=-3m+205 where m is the number of months after January 2013a) How much did Jonathan weigh at the start of the diet?

b) How much weight has Jonathan been losing each month?

c) How many month did it take Jonathan to lose 45 pounds?

Show work plz

Answers

$a)\ \ \ w(m)=-3m+205\n\nm=0\ \ \ - at\ the\ start\ of\ the\ diet\n \nw(0)=-3\cdot0+205=205\n \nAns.\ weigh\ at\ the\ start\ of\ the\ diet\ is\ 205\ pounds\n \nb)\ \ \ w(m+1)=-3(m+1)+2015=-3m-3+205=-3m+202\n \nw(m+1)-w(m)=-3m+202-(-3m+205)=\n \n=-3m+202+3m-205=-3\n \nAns.\ Jonathan\ has\ each\ month\ 3\ been\ losing \n \n w(m)=205-45=160\ \ \ \Rightarrow\ \ \ -3m+205=160\ \ \ \Rightarrow\ \ \-3m=-45\n \nm=15\n \nAns.\ 15\ month$