Determine whether the function is linear or quadratic. Identify the quadratic, linear, and constant terms of the equation: y=(x-1)(4x+2)-4x^2

Answers

Answer 1
Answer:

The specified formula y = (x-1)(4x+2)A linear function, -4x² has a constant term of -2 and a linear term of 2x.

To determine whether the function y = (x-1)(4x+2)-4x^2 is linear or quadratic, we can analyze the equation and identify its terms.

Start with the equation:

y = (x-1)(4x+2)-4x²

Expand the equation by multiplying the terms:

y = 4x² + 2x - 4x - 2 - 4x²

Simplifying further,

y = 2x - 2.

Analyzing the equation, we can see that there is no x² term. This indicates that the function is linear.

Let's identify the terms of the equation:

Quadratic term: There is no x² term in the equation.

Linear term: The linear term is 2x.

Constant term: The constant term is -2.

Therefore, the given function y = (x-1)(4x+2)-4x² is a linear function with a linear term of 2x and a constant term of -2.

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Answer 2
Answer: Hello,

Multiplying (x-1) by (4x+2) the term in x² is x*4x=4x².
If we substract 4x² the term of y in x² will be 0.
The function is not quadratic.

Since 4x*(-1)+2*x=-2x (product of terms in x) : the function is thus linear.

Constant term is -1*2=-2


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GCF of 24s^3, 12s^4, and 18s

Answers

Answer:

6s

Step-by-step explanation:

when a number is added to 1/5 of itself the result is 24. the equatation that models this problem is n + 1/5 n equals 24. what is the value n

Answers

If you convert it to decimals you get 1.2n= 24.
Divide both sides by 1.2.

The answer is n=20.
It is N = 20 sure of it

Find the x-intercept of the parabola of with vertex (1,20) and the y-intercept (0,16). write your answer in this form: (x1,y1),(x2,y2)

Answers

I assume that the parabola in this particular problem is one whose axis of symmetry is parallel to the y axis. The formula we're going to use in this case is (x-h)2=4p(y-k). We know variables h and k from the vertex (1,20) but p is not given. However, we can solve for p by substituting values x and y in the formula with the y-intercept:

(0-1)^2=4p(16-20)

Solving for p, p=-1/16.

Going back to the formula, we can finally solve for the x-intercepts. Simply fill in variables p, h and k then set y to zero:

(x-1)^2=4(-1/16)(0-20)
(x-1)^2=5
x-1=(+-)sqrt(5)
x=(+-)sqrt(5)+1

Here, we have two values of x

x=sqrt(5)+1 and
x=-sqrt(5)+1

thus, the answers are: (sqrt(5)+1,0) and (-sqrt(5)+1,0).

Solve the equation for the given variable.
Bx+Cy=D

Solve for y

Answers

Bx + Cy = D

Solve for y . .  .

*subtract Bx from both sides

Bx - Bx + Cy = D - Bx

Cy = D - Bx

*now divide both sides by C

Cy/C = (D - Bx)/C

Cy/C = D/C - Bx/C

y = D/C - (B/C)x

y = -(B/C)x + D/C


Bx+Cy=D -- subtract Bx

Cy=D-Bx -- divide by C

y=(D-Bx)/C

Solve the following system of equations by graphing and select the correct answer below:2x + 6y = 20
3x _ 2y = 8


Answers:
x = 4, y = 2
x = 4, y = _2
x = _2, y = 4
x = 2, y = 4

Answers

the only answer is x = 4, y = 2, 
2(4) + 6(2) = 20
3(4) _ 2(2) = 8
the graph is so easy, please try!!

Answer:

Option A is correct.

x =4 , y = 2

Explanation:

Given the system of equation:

2x+6y = 20                   ......[1]

3x-2y = 8                       .....[2]

Multiply equation [2] by 3 both sides we get;

3 \cdot (3x-2y) = 3 \cdot 8

Using distributive property:a\cdot (b+c) = a\cdot b+ a\cdot c

9x - 6y = 24                     .....[3]

Add equation [1] and [3], to get eliminate y we get;

2x+6y+9x-6y= 20+24

Combine like terms we have;

11x = 44

Divide both sides by 11 we get;

x = 4

Substitute the value of x =4 in [1] we get;

2(4) + 6y = 20

8 + 6y = 20

Subtract 8 from both sides we have;

6y = 12

Divide both sides by 6 we have;

y = 2

Therefore, the values of x and y are; 4 and 2.


Use complete sentences to analyze the graph of the function f(x) = log 1/3 x.Part 1: Describe the domain, range, and general shape of this graph. (4 points)

Part 2: Using complete sentences, explain how plotting specific points helps graph the function and note any critical points such as its intercepts.

Answers

y = log (1/3) x
Part 1:
Domain :  x ∈ ( 0, + ∞ ).
Range:  y ∈ R.
General shape: The graph is decreasing.
Part 2 :
We will choose those points: x = { 1/3,  1,  3,  9 }
Ordered pairs ( for graphing the function ) are :
f ( x ) = { ( 1/3, 1 ), ( 1. 0 ), ( 3, - 1 ), ( 9, - 2 ) }. 
There is no y - intercept and x - intercept is 1.