What is the theoretical yield of sodium oxide (Na₂O) in grams when 20.0g of calcium oxide (CaO) reacts with an excess amount of Sodium chloride? *10 points
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10.0g
22.1g
32.9g
5.6g

Answers

Answer 1
Answer:

Answer:

22.1 g

Explanation:

The balanced reaction equation which serves as a guide in solving the problem is given as;

CaO(s) + 2NaCl(aq) ------> Na2O(s) + CaCl2(aq)

The question clearly specifies that sodium chloride is the reactant in excess. This means that calcium oxide should be used to calculate the theoretical yield of sodium oxide.

Number of moles of calcium oxide reacted = mass of calcium oxide / molar mass of calcium oxide

Molar mass of calcium oxide = 56.0774 g/mol

Mass of calcium oxide = 20.0g

Number of moles of calcium oxide = 20.0 g/ 56.0774 g/mol = 0.3566 moles

From the balanced reaction equation;

1 mole of calcium oxide produces 1 mole of sodium oxide

Therefore, 0.3566 moles of calcium oxide will produce 0.3566 moles of sodium oxide.

Mass of sodium oxide produced = number of moles × molar mass

Molar mass of sodium oxide= 61.9789 g/mol

Mass of sodium oxide = 0.3566 moles × 61.9789 g/mol

Mass of sodium oxide= 22.1 g

Answer 2
Answer:

Answer:

22.1g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaO + 2NaCl —> Na2O + CaCl2

Next, we shall determine the mass of CaO that reacted and the mass of Na2O produced from the balanced equation.

This is illustrated below:

Molar mass of CaO = 40 + 16 = 56g/mol

Mass of CaO from the balanced equation = 1 x 56 = 56g

Molar mass of Na2O = (23x2) + 16 = 62g/mol

Mass of Na2O from the balanced equation = 1 x 62 = 62g

From the balanced equation above,

56g of CaO reacted to produce 62g of Na2O.

Finally, we can determine the theoretical yield of Na2O as follow:

From the balanced equation above,

56g of CaO reacted to produce 62g of Na2O.

Therefore, 20g of CaO will react to produce = (20 x 62)/56 = 22.1g of Na2O.

Therefore, the theoretical yield of Na2O is 22.1g


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Answers

Answer:  

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Answers

Answer:

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Explanation:

mixture of iron powder and sulphur heated it glows because sulphur and iron are more reactive metals that they shine and sulphur can react with water produce fire it's write

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Answers

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Hi there, thanks for asking a question here on Brainly!


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List at least three ways of forming/ molding pewter and explain how each is achieved.

Answers

Answer:

1. Sand Casting: Sand casting is a popular method used to create pewter objects. Here's how it's achieved:

- First, a pattern or model of the desired object is created using materials like wood, plastic, or metal.

- The pattern is then pressed into a special type of sand called green sand, leaving an impression.

- Next, the pattern is removed, leaving a cavity in the sand.

- Molten pewter is poured into the cavity and left to cool and solidify.

- Once cooled, the sand is carefully removed, revealing the pewter object.

2. Spin Casting: Spin casting, also known as centrifugal casting, is another way to mold pewter. Here's how it works:

- A rubber mold of the object is created, usually using a master pattern made of wax or another material.

- The rubber mold is placed in a casting machine that rotates at high speed.

- Molten pewter is poured into the mold while it spins.

- The centrifugal force evenly distributes the pewter, filling the mold's cavities.

- As the pewter cools, it solidifies and takes the shape of the mold.

- Once cooled, the mold is opened, and the pewter object is removed.

3. Die Casting: Die casting is a method used for producing high-quality pewter objects. Here's how it's done:

- A metal mold, called a die, is created to match the desired shape of the object.

- Molten pewter is injected into the die under high pressure.

- The pressure ensures that the pewter fills the mold completely and captures all the intricate details.

- After a short cooling period, the die is opened, and the pewter object is ejected.

Explanation:

These are just a few ways to form or mold pewter. Each method has its advantages and is suitable for different types of objects. It's important to choose the appropriate method based on the complexity of the design and the desired quality of the final product.