the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle

Answers

Answer 1

Answer: $l-the\ length\nl+8-the\ width\nA=172\ cm^2\n\nA=lengtf\cdot width\n\nsubtitute\n\nl(l+8)=172\n\nl^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\n\nl^2+8l-172=0\na=1;\ b=8;\ c=-172\n\n\Delta=b^2-4ac\n\n\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\n\nl_1=(-b-\sqrt\Delta)/(2a)\ and\ l_2=(-b+\sqrt\Delta)/(2a)\n\n\sqrt\Delta=√(752)=√(16\cdot47)=4√(47)\n\nl_1=(-8-4√(47))/(2\cdot1)=-4-2√(47) < 0\n\nl_2=(-8+4√(47))/(2\cdot1)=-4+2√(47) > 0\n\nThe\ width:l+8=-4+2√(47)+8=4+2√(47)\n\nAnswer:\boxed{length=(2√(47)-4)cm;\ width=(4+2√(47))cm}$
$length\approx9.71cm;\ width\approx17.71cm$

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Answer:

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Step-by-step explanation:

Variable g is 8 more than variable w. Variable g is also 4 less than w. Which pair of equations best models the relationship between g and w? A) g=w-8 , q=w+4 B) w=8g , w=g-4 C) g=w+8 , g=w+4 D) w=8g , w=g+4

Answers

Answer:

$\Rightarrow g=w+8$

$\Rightarrow w=g-8$

and

$\rightarrow g=w-4$

$\rightarrow w=g+4$

Step-by-step explanation:

We are given that Variable g is 8 more than variable w.

$\Rightarrow g=w+8$

$\Rightarrow w=g-8$

We are also given that

Variable g is also 4 less than w.

$\rightarrow g=w-4$

$\rightarrow w=g+4$

Hence pair of equations best models the relationship between g and w are:

$\Rightarrow g=w+8$

$\Rightarrow w=g-8$

and

$\rightarrow g=w-4$

$\rightarrow w=g+4$

Given:
Variable g is 8 more than variable w. ⇒ g = w + 8
Variable g is also 4 less than w ⇒ g = w - 4

g = w + 8 or w = g - 8
g = w - 4 or w = g + 4

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Answers

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