When n is divided by 12, the remainder is 6. What is the answer when n is divided by 6?

Answers

Answer 1

Answer: their won't be a remainder, but n is not determinable

Answer 2

Answer: Hello,

if n=q*12+6 then
n/6=(q*12+6)/6=q*2+1
Remainder is 1.

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Evaluate |x + y|, for x = 8 and y = -15.

Answers

First, we substitute the numbers to the corresponding variables.

|(8) + (-15)|

And we change the plus sign since we’re just basically subtracting.

|8 - 15|

|-7|

Now to do absolute values, we must remember that it will always equal a positive unless there is a negative sign outside of the | |.

So the final answer will be 7.

Since slope is calculated using the formula m = StartFraction v 2 minus v 1 Over x 2 minus x 1 EndFraction, the slope of both lines is equivalent to ________. It is given that the lines are parallel, and we calculated that the slopes are the same. Therefore, parallel lines have the same slopes.

Answers

Answer: z-v/x-w

Step-by-step explanation: just did the test with this question and it’s right :)

Final answer:

Parallel lines have the same slopes.

Explanation:

The subject of this question is Mathematics as it involves calculating slopes using a formula.

Slope is calculated using the formula m = (v2 - v1) / (x2 - x1). When two lines are parallel, their slopes are equivalent, meaning that they have the same slope. This is because parallel lines have the same steepness or inclination.

For example, if Line A has a slope of 2 and Line B is parallel to Line A, then Line B will also have a slope of 2.

Learn more about Slope of parallel lines

Somebody help please

Answers

Answer:

$(2(a+4b))/(a^2 -b^2 )$

Step-by-step explanation:

$(3)/(a-b) -(1)/(a+b) +(4b)/((a-b)(a+b))$ =

$(3(a+b))/((a-b)(a+b)) -(a-b)/((a-b)(a+b)) +(4b)/((a-b)(a+b))$ =

$(3a + 3b -a + b + 4b)/((a-b)(a+b))$ =

$(2(a+4b))/(a^2 -b^2 )$

Answer: look at the picture i attached!

Prove the diagonal connecting these vertex angles is perpendicular to the diagonal connecting the non-vertex angles

Answers

Seg BA is congr to seg BC and seg DA is cong to seg DC by given Seg BD is congr to seg BD by reflexive Tr. BAD is congr to tr. BCD by SSS

The vertices of / are G(–4, 0), H(5, 2), and I(–2, –3). / is rotated 270° counterclockwise about the origin to form /. What are the coordinates of the vertices of /?

Answers

The coordinates of new vertices (after rotating 270 ° counterclockwise) are:
G 1 ( 0, 4 ),
I 1 ( -3, 2 )
H 1 ( 2, -5 )

Answer:

The new coordinate of vertices of triangle after rotation G'(0,4) , H'(2,-5) and I'(-3,2)

Step-by-step explanation:

The vertices of triangle are G(–4, 0), H(5, 2), and I(–2, –3).

It is rotated 270° counterclockwise about origin to form new triangle.

Rotation about origin counterclockwise.

Using Rule:

$R_(270^\circ)(x,y)\rightarrow (y,-x)$

$G(-4,0)\rightarrow G'(0,4)$

$H(5,2)\rightarrow H'(2,-5)$

$I(-2,-3)\rightarrow I'(-3,2)$

The new coordinate of vertices of triangle after rotation G'(0,4) , H'(2,-5) and I'(-3,2)

Jaida has $200 to spend on flowers for a school celebration. She decides that the only flowers that she wants to buy are roses and carnations. Roses cost $1.45 each and carnations cost $0.65 each. Jaida buys enough roses so that each of the 75 people attending the event can take home at least one rose. Write an inequality to represent the cost constraint.