18. In their last basketball game, Holly scored25 points and Juanita scored 16 points. The
mean number of points Holly scores is 20 with
a standard deviation of 2. The mean number
of points Juanita scores is 12 with a standard
deviation of 1.25. Whose score is better relative
to her average number of points per game?

Answer:

Juanita's score was better

Step-by-step explanation:

Juanita scored 6.4 points above her average score whereas Holly only scored 2.5 points above her average score. (this was calculated via z-scores)

Final answer:

To find who performed better relative to their average, we calculated the z-scores of both players. Juanita's score was 3.2 standard deviations above her mean, whereas Holly's was 2.5 standard deviations above her mean, making Juanita's performance relatively better.

Explanation:

To answer this question, we need to find how many standard deviations each player's score deviates from their respective means. This is referred to as the z-score. The z-score is calculated using the formula (X - μ) / σ, where X is the score, μ is the mean score and σ is the standard deviation.

For Holly, her z-score would be (25 - 20) / 2 = 2.5. This means Holly's score was 2.5 standard deviations above her mean score.

For Juanita, her z-score would be (16 - 12) / 1.25 = 3.2. This means Juanita's score was 3.2 standard deviations above her mean score.

Since Juanita's z-score is higher than Holly's, Juanita's score is better relative to her average number of points per game.

Learn more about Z-score here:

brainly.com/question/15016913

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