Pythagorean Theorem: Jason only has room for a TV that is less than 30” wide. Can he fit the TV in his room?
Answers
Answer:
No
Step-by-step explanation:
Using the Pythagorean Theorem, make 40 = c, 24 = b and the remaining side (the width) = a.
Solving for a we get a = . Then plugging in the values for c and b, we get a =
= 32
Since the width of the TV needs to be less than 30" wide, it will not fit since the width of the TV is 32" wide.
Answer:
No, the tv is 32 inches wide.
Step-by-step explanation:
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The actual area of the park in square yards from the given scale is;
Actual area of park = 56000 yds²
We are told that;
There is a scale drawing of a rectangular park with dimensions;
Width = 5 inches
Length = 7 inches
Now, we are told that the Actual length of the park is 280 yards.
Since the length on the scale drawing is 7 inches, then it means that;
7 inches represents 280 yards
Thus, 1 inch will represent; 280/7 = 40 yards
Thus, actual width = 5 × 40
Actual width = 200 yards
Formula for area of rectangle is;
Area of rectangle = Length × width
Thus;
Actual area of rectangle = actual length × actual width
Actual area of rectangle = 280 × 200
Actual area of rectangle = 56000 yds²
Read more at; brainly.com/question/13654487
Answer:
Area of the actual park is 56000 square yards.
Step-by-step explanation:
A scale drawing of a rectangular park has dimensions as 5 inches width and 7 inches length.
Actual length of the park has been given as 280 yards.
So scale factor used in the drawing is 7 inches = 280 yards
Or 1 inch = 40 yards
Since width of the rectangular park is = 5 inch
So actual width of the park will be = 5×40 = 200 yards
Now we can calculate the area of the park.
Actual area of the park = Length × Width
= 280×200
= 56000 yards²
Therefore, area of the actual park is 56000 square yards.