What happens to the energy released by an exothermic reaction?

Answers

Answer 1
Answer: The surroundings of the reaction will experience an increase in temperature.
Answer 2
Answer: Heat is released during the reaction.

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Which of the following is not one of the three largest sources of materials needed to form carbon compounds?natural gas
petroleum
coal
wood

Answers

Answer:

The correct answer is option D, wood

Explanation:

The three major source of carbon on earth are – coal , petroleum and natural gas

Several carbon based products are formed from these three source after  processing. For example – coke and charcoal are produced from coal, like wise ink and paints also have coal as one of the constituents substance. Carbon black is also extracted from coal. Similarly,  from petroleum all lubricating oils and wax are derived using distill filtration.  

WOOD is not one of the three largest sources of materials needed to form carbon compounds. So the answer is wood.

Hope this helps :)

In a play, the rising action consists of the events that lead up to thea. last line in the scene.
c. external conflict.
b. climax.
d. internal conflict.

Answers

It leads up to the climax.

What is the density of an object having a mass of 5.0 g and a volume of 45.0 cm3?

Answers

Answer : The density of the object will be, 0.111g/cm^3

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

Density=(Mass)/(Volume)

Given :

Mass of an object = 5.0 grams

Volume = 45.0cm^3

Now put all the given values in the above formula, we get the density of an object.

Density=(5.0g)/(45.0cm^3)=0.111g/cm^3

Therefore, the density of the object will be, 0.111g/cm^3

d = m / V

d = 5.0 / 45.0

d = 0.111 g/cm³

If 3.00 g of limestone reacted, what mass of calcium chloride would be produced?A) Calcium chloride
B) Carbon dioxide
C) water

Answers

a) CaCO₃ + 2 HCl = CaCl₂ + H₂O + CO₂
  ↓                            ↓
1 mole                 1 mole

molar mass :

CaCO₃ = 100.0 g/mol     CaCl₂ = 111 g/mol

 100 g CaCO₃ ------------- 111 g caCl₂
  3.00 g CaCO₃ --------------- ?

3.00 * 111 / 100 = 

333 / 100 = 3.33 g of CaCl₂
________________________________________

b) molar mass CO₂ = 44.0 g/mol

100 g CaCO₃ ---------- 44.0 g CO₂
3.00 g CaCO3 ------------- ?

3.00 * 44 / 100 = 

132 / 100 = 1.32 g of CO2
____________________________________

c) molar mass H₂O = 18.0 /mol

100 g CaCO3 ------- 18.0 g 
3.00 g CaCO3 ------- ?

3.00 * 18.0 / 100 =

54 / 100 = 0.54 g of H₂O
___________________________________

hope this helps!

2. When lithium reacts with bromine to form the compound LiBr,each lithium atom1) gains one electron and becomes a negatively charged ion2) gains three electrons and becomes a negatively charged ion3) loses one electron and becomes a positively charged ion4) loses three electrons and becomes a positively charged ion

Answers

3) Each lithium atom will lose one electron and become positively charged.

This is an example of ionic bonding wherein an electron is transferred from one atom to another. As each atom wants to have complete outer shells (with lithium's having one electron and bromine's having seven) the electron will move from the Lithium to the Bromine. Lithium will become positive as electrons are negatively charged and it has one less electron than it originally had. 

calculate the volume of hydrogen produced at s.t.p when 25g and zinc are added to excess dilute hydrochloric acid at 31 degrees and 778 mm Hg pressure ( H= 1 , Zn = 65 , cl = 35.5 , volume of gas at stop = 22.4 dm cube​

Answers

Answer:

The volume of hydrogen gas produced at s.t.p. is 9.419 dm³

Explanation:

The balanced chemical equation for the reaction is given as follows;

Zn + 2HCl → ZnCl₂ + H₂

Therefore, we have;

One mole of Zn reacts with 2 moles of HCl to produce one mole of ZnCl₂ and one mole of H₂

Number of moles of Zn present = 25/65 = 5/13 = 0.385 moles

Therefore, number of moles of H₂ produced = 0.385 moles

The volume of hydrogen gas produced is given by the relation

PV = nRT, we have;

R = 8.3145 J/(mol·K)

V = nRT/P = 0.385 ×8.3145 ×298.15/(101325)= 0.009419 m³ = 9.419 dm³

The volume of hydrogen gas produced at s.t.p. = 9.419 dm³.