What are the domain, range, and asymptote of h(x) = 6x – 4?

Answers

Answer 1
Answer:

The domain is x = 1, 2, 3, 4, 5...... ∈ R (set of real number).

Range:  (0,∞)

Asymptote: y=0.

What is Domain, Range and Asymptote?

The range of a function is the set of output values for the dependent variable.

The range, however, is bounded by the horizontal asymptote of the graph of f(x).

A straightline that continuously approaches a certain curve without ever meeting it is an asymptote.

Given:

h(x) = 6x – 4

Now, the domain is the input value as

x = 1, 2, 3, 4, 5...... ∈ R (set of real number)

So, h(1) = 6-4 =2

and, h(2) = 12-4 = 8

and, the range is (0,∞)

Now, the asymptote h(x)= 0

6x-4 = 0

x= 2/3.

Learn more about Domain and Range here:

brainly.com/question/28135761

#SPJ2

Answer 2
Answer: h(x)=6x−4  or  h(x)=6x−4 
If the former, the domain is all real numbers, often denoted by the symbol R
the range is (0,∞) 
asymptote is y = 0

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Put these into y=mx+b format SHOW YOUR WORK!!!! x-7y=7 and 6x-7y=-28

Answers

Answer:

Explanation:

x - 7y = 7
-7y = -x + 7
y = (-1/-7)x + 7/-7
y = (1/7)x - 1

6x - 7y = -28
-7y = -6x - 28
y = (-6/-7)x - 28/-7
y = (6/7)x + 4
x-7y=7
-x -x (isolate the y by subtracting x on both sides)
-7y= -x+7
— ——-
-7 -7 (Isolate the y by dividing both sides by -7)
Answer : y= 1/7x - 1
6x-7y= -28
-6x. -6x
-7y = -6x -28
—— ———-
-7. -7
Answer : y= 6/7x + 4

A line passes through the point (-3, -3) and has a slope of 1/2 What is the equation of the line? Solve the system of equations. 2x + 3y = 6 x + y = 4

Answers

y-y1=m(x-x1)
(x1,y1) is a given point
m=slope
y-(-3)=1/2(x-(-3))
y+3=1/2(x+3) is an equation



2x+3y=6
x+y=4
multiply second equation by -2 and add to first

2x+3y=6
-2x-2y=-8 +
0x+1y=-2

y=-2
sub back

x+y=4
x-2=4
add 2
x=6

x=6
y=-2
(6,-2)

6 students shared 5 small pizzas equally

Answers


Bon apetit !  What more can I say ?

Was there a question ?

If your objective is to feed 6 students with 5 pizzas, then do it like this:

(5 pizza) / (6 student) = 5/6 pizza per student.

Cut each pie in 6 equal pieces, and give each student 5 of the pieces.




Answer and workings in the doc below.

Which equation describes a line perpendicular to y=8x-9 that passes through the point (9,-9)?f. y=8x-81
G.y=-1/8x-63/8
h.8x-9
J.y=1/8X+585/8

Answers

The answer is G. Perpendicular lines have opposite reciprocal slopes

Part A: Solve −np − 90 < 30 for n. Show your work. Part B: Solve 5m − 3h = 45 for h. Show your work.

Answers

A.well to start you have to do  np + 90 >- 30
np > - 20
n > - 120/p

and for b
5m - 45 = 3h
so h = 5m/3 - 15

Please help me as soon as possible

Answers

The formula of the Lateral Area of a cylinder is:
Lateral Area = 2\pirh
                     =2\pi(12)(60)          (altitude is 5×radius)
                                                                           (5×12=60)
                     =4523.9 mm² ≈ 4524 m²

Answer is D. 4524 m²