To simplify each expression and use positive exponents for m^3n^-6p^0.

Answers

Answer 1

Answer: $m^(3n) -6 p^(0)$
= $m^(3n) -6$

Answer 2

Answer: $m^3n^-6p^0$

$Use \ Negative \ Power \ Rule$ $x^-^a= (1)/(x^a)$

$m^3* (1n)/(6) p^0$

$Use \ Rule \ of \ Zero$ $x^0=1$

$m^3*1 (1)/(n^6) *1$

$\boxed{\boxed{(m^3)/(n^6)}}$ $Solution$

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12.5% of what number is 24? Please help and show work

Answers

$\n y- number\n \n12.5\% \ of \ y = 24 \n \n (12.5)/(100)*y=24 \n \n y=24: (12.5)/(100)\n \n y=24* (100)/(12.5) \n \n y= (2400)/(12.5)= \n \n y=192 \n \n\huge\text{The answer is y=192 !!!}$

Solve the system of equations graphed on the coordinate axes below.�
=
y=

−
2
3
�
+
4
−
3
2

x+4
�
=
y=

1
2
�
+
4
2
1

x+4

Answers

The solution to the system of equations y = -2x + 4 and y = 1/2x + 4 is the point (0, 4)

Calculating the solution to the system

A system of equations is a set of two or more equations that are to be solved simultaneously.

The solution of a system of equations is a set of values that satisfy all the equations in the system.

Given the equations:

y = -2x + 4

y = 1/2x + 4

The question implies that we solve graphically

So, we create a plot of the equations y = -2x + 4 and y = 1/2x + 4

And we write out the coordinate of the point of intersection between the two equations

From the graph of the system of equations (see attachment), we have the point of intersection to be (0, 4)

This means that the solution to the system of equations is (0, 4)

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Complete question

Solve the system of equations graphed on the coordinate axes below.

y = -2x + 4

y = 1/2x + 4

A carpenter uses the equation y = 3.75x to determine how many hours (y) it will take him to build a desk (x). The carpenter built 5 desks. How long did it take him?

Answers

y = 3.75x...he built 5 desks...so x = 5
y = 3.75(5)
y = 18.75 hrs

Answer:

18.45

Step-by-step explanation:

The ratio of Sam's age to Hank's age is 5 to 3. If the sum of their ages is 24, how old is Hank?

Answers

$S-Sam's\ age\nH-Hank's\ age\n\n \left\{\begin{array}{ccc}(S)/(H)=(5)/(3)\nS+H=24&\to S=24-H\end{array}\right\n\nsubstitute\ S=24-H\ to\ (S)/(H)=(5)/(3)\n\n(24-H)/(H)=(5)/(3)\n\ncross\ multiply\n\n5H=3(24-H)\n5H=72-3H\n5H+3H=72\n8H=72\ \ \ /:8\nH=9\n\nAnswer:Hank\ is\ 9\ years\ old.$

A company that translates books between various languages is currently testing a computer-based translation service. The founder of the company expects the computer program to make some errors, but then so do human translators. The computer error rate is supposed to be an average of 2 per 500 words of translation. Suppose the company founder randomly selects a 3,000-word passage. Assume that the Poisson distribution applies and that the computer error rate is actually 2 errors per 500 words. Complete parts a through c.a. Determine the probability that no errors will be found.
The probability is ___. Round to four decimal places as needed.)

b. Calculate the probability that more than 30 errors will be found.
The probability is ___. (Round to four decimal places as needed.)

c. Find the probability that fewer than 15 errors will be found.
The probability is ___. (Round to four decimal places as needed.)

Answers

The probability that noerrors will be found is 0.

The probability of finding more than 30 errors is 0.0001.

The probability of finding fewer than 15 errors is 0.9452.

What is probability?

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

Example:

The probability of getting a head in tossing a coin.

P(H) = 1/2

We have,

The number of errors in a 3,000-word passage follows a Poisson distribution with a mean of 12 errors.

i.e

Since 3,000 is six times 500.

The probability that no errors will be found.

P(X = 0) = $e^(-12)$ x $12^0$ / 0!

= 0.000006

Rounded to four decimal places.

= 0.0000.

The probability of finding more than 30 errors.

P(X > 30) = 1 - P(X ≤ 30)

We can use a Poisson table.

P(X ≤ 30) = 0.9999.

P(X > 30) = 1 - 0.9999

= 0.0001

Rounded to four decimal places.

= 0.0001.

The probability of finding fewer than 15 errors.

P(X < 15) = P(X <= 14)

= ∑(k=0 to 14) $e^(-12)$ x $12^k$ / k!

From the Poissontable.

P(X ≤ 14) = 0.9452

P(X < 15) = P(X ≤ 14)

= 0.9452

Rounded to four decimal places.

= 0.9452.

Thus,

The probability that no errors will be found is 0.

The probability of finding more than 30 errors is 0.0001.

The probability of finding fewer than 15 errors is 0.9452.

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Step-by-step explanation:

this is the answer of this question

51.66 the 6 in the tenths place is _______ the value of the 6 in the hundredths place

Answers

The value of 6 in the tenths place is 10 times the value of 6 in the hundredths place.

0.06 x 10 = 0.6

Final answer:

The 6 in the tenths place in the number 51.66 is ten times greater in value than the 6 in the hundredths place, due to positional values in decimal numbers.

Explanation:

In the decimal number 51.66, the value of the 6 in the tenths place is indeed ten times the value of the 6 in the hundredths place. This is because each place to the right of the decimal point is ten times smaller than the place to its immediate left. Therefore, although both of these digits are 6, the 6 in the tenths place represents a value of 0.6 (or 6/10), whereas the 6 in the hundredths place represents a value of 0.06 (or 6/100). So, when you divide 0.6 by 0.06, you get 10, showing that the 6 in the tenths place is ten times the value of the 6 in the hundredths place.

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Other Questions

There are 25 gold cards and 25 silver cards in a deck. The gold cards are number 1,3,5,.....49 and the silver cards are numbered 2,4,6,.....50. The cards are thoroughly shuffled and one card is randomly selected.A.) Find the probability of selecting a gold card or a card with a multiple of 10 on it. B.) Find the probability of selecting a silver card or a card with a multiple of 7 on it.

What is the 10th term of the sequence 64, 16, 4,...?a. 1/1024 b. 1/256 c. 1/4096 d. 1/496

A pie is cut into eight pieces.at what acute angle is each piece cut?

2. What is the sample space for the chance experiment described on this scenario card?