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Show steps how to solve for y!!!!!
2y+2=3y/2
Please help me

Answers

Answer 1
Answer:

\text{Solve for y:}\n\n2y+2=(3y)/(2)\n\n\text{Multiply both sides by 2 to cancel the denominator}\n\n4y+4=3y\n\n\text{Subtract 3y from both sides}\n\ny+4=0\n\n\text{Subtract 4 from both sides}\n\n\boxed{y=-4}
Answer 2
Answer:

Answer:-4

Step-by-step explanation:

2y+2=3y/2

Cross multiply

2(2y+2)=3y

Open bracket

4y+4=3y

Collect like terms

4y-3y=-4

y=-4

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Answers

Answer:

y=3x-2

Step-by-step explanation:

You can verify it's not D because the y-intercept is at -2.

You can verify it's not A because that would mean the x-intercept is 2 despite it appearing to be closer to one.

You can verify it's not B because that would mean the x-intercept is 1.5
It’s C. If I’m wrong sorry

Write true or false.​

Answers

Answer:

1. False

2. True

3. False

4. True

5. True

6. False

7. True

8. False

9. True

10. False

Answer:

❌1.

✅2.

❌3.

✅4.

✅5.

❌6.

✅7.

❌8.

✅9.

❌10.

#SahreYourKnowledge!

✅ = True.

❌ = False.

The inside diameter of a randomly selected piston ring is a randomvariable with mean value 12 cm and standard devtiation of .04cm. a. If Xbar is the sample mean diameter form a random sample of=16 rings, where is the sampling distrbution of Xbar centered andwhat is the standard deviation of the Xbar distribution?

b. Answer the questions above for a sample of size n=64

c.find the probability that the average diameter of pistonrings from a sample size 16 is more than 11.95cm

d. For which of the above two random saples is Xbar morelikely to be within .01cm of 12cm? Explain.

Answers

Using the normal distribution and the central limit theorem, it is found that:

a) The sampling distribution is approximately normal,centered at 12 cm and with a standard deviation of 0.01 cm.

b) The sampling distribution is approximately normal,centered at 12 cm and with a standard deviation of 0.005 cm.

c) 100% probability that the average diameter of piston rings from a sample size 16 is more than 11.95 cm.

d) Due to the lower standard error, the sample of 64 is more likely to be within 0.01 cm of 12 cm.

In a normal distribution with mean\mu and standard deviation\sigma, the z-score of a measure X is given by:

Z = (X - \mu)/(\sigma)

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = (\sigma)/(√(n)).

In this problem:

  • Mean of 12 cm, thus \mu = 12
  • Standard deviation of 0.04 cm, thus \sigma = 0.04.

Item a:

Sample of 16, thus n = 16 and s = (0.04)/(√(16)) = 0.01

The sampling distribution is approximately normal,centered at 12 cm and with a standard deviation of 0.01 cm.

Item b:

Sample of 64, thus n = 64 and s = (0.04)/(√(64)) = 0.005

The sampling distribution is approximately normal,centered at 12 cm and with a standard deviation of 0.005 cm.

Item c:

This probability is 1 subtracted by the p-value of Z when X = 11.95, thus:

Z = (X - \mu)/(\sigma)

By the Central Limit Theorem:

Z = (X - \mu)/(s)

Z = (11.95 - 12)/(0.01)

Z = -5

Z = -5 has a p-value of 0.

1 - 0 = 1.

100% probability that the average diameter of piston rings from a sample size 16 is more than 11.95 cm.

Item d:

Due to the lower standard error, the sample of 64 is more likely to be within 0.01 cm of 12 cm.

A similar problem is given at brainly.com/question/24663213

Answer:

The answer is below

Step-by-step explanation:

Given that:

mean value (μ) = 12 cm and standard deviation (σ) = 0.04 cm

a) Since a random sample (n) of 16 rings is taken, therefore the mean (μx) ans standard deviation (σx) of the sample mean Xbar is given by:

\mu_x=\mu=12\ cm\n\sigma_x=(\sigma)/(√(n) )=(0.04)/(√(16) )=0.01

The sampling distribution of Xbar is centered about 12 cm and the standard deviation of the Xbar distribution is 0.01 cm

b) Since a random sample (n) of 64 rings is taken, therefore the mean (μx) ans standard deviation (σx) of the sample mean Xbar is given by:

\mu_x=\mu=12\ cm\n\sigma_x=(\sigma)/(√(n) )=(0.04)/(√(64) )=0.005\ cm

The sampling distribution of Xbar is centered about 12 cm and the standard deviation of the Xbar distribution is 0.005 cm

c) n = 16 and the raw score (x) = 11.95 cm

The z score equation is given by:

z=(x-\mu_x)/(\sigma_x) =(x-\mu)/(\sigma/√(n) ) \nz=(11.95-12)/(0.04/√(16) )\n z=-5

P(x > 11.95 cm) = P(z > -5) = 1 - P(z < -5) = 1 - 0.000001 ≅ 1 ≅ 100%

d) for n = 64, the standard deviation is 0.01 cm, therefore it is more likely to be within .01cm of 12cm

SOMONE HELP WITH MATH

Answers

Answer:

x = 28

Step-by-step explanation:

HFG = EFI

6x - 4 = 164

6x = 164 + 4

6x = 168

x = 168/6

x = 28

An ice cream cone is filled with vanilla and chocolate ice cream at a ratio of 2:1. If the diameter of the cone is 2 inches and the height is 6 inches, approximately what is the volume of vanilla ice cream in the cone? (round to nearest tenth) A) 1.0 in3 B) 2.1 in3 C) 4.2 in3 D) 6.3 in3

Answers

Answer:

D. 6.3 in^3

Step-by-step explanation:

V= 1/3 (3.14)(r^2)(h)

V= 1/3 (3.14) (1^2)(6)

V=6.3 in^3

Answer:

c

Step-by-step explanation: it was on usa test prep and the answer that was there was wrong.

Simplify each equation 3(5x2+2x-4)-x7x2+2x-3)

Answers

Answer:  -7x3 + 13x2 + 9x - 12

Answer:

3(5x2+2x-4)-x7x2+2x-3)

15 x 6 + 6x -12 - x7 + x2 + 2x -3

90 + 6x - 12 - x7 + x2 + 2x -3

(6x + 2x) (+90 - 12 - 3) (-x7 + x2)

8x + 75 - x5
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