Start at 125 and make a pattern subtracting 6

Answers

Answer 1
Answer: 125
-6
119
-6
113
-6
107
-6
101
-6
95
-6
89
-6
83
-6
77
-6
71
-6
65
-6
59
-6
53
-6
47
-6
41
-6
35
-6
29
-6
23
-6
17
-6
11
-6
5
-6
-1
BOLD: 
Number after subtracting 6

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Jason entered the elevator of the skyscraper on the ground floor and rode up to the 45th floor. Since Jason was texting, he didn’t notice where he was, so he then rode down 28 floors and finally up 15 floors where he exited the elevator. On what floor did Jason exit the elevator?

Floor

Answers

ok here's how i think you do it you take 45-28 which gets you 17, then you do 17+15 which gets you 32

How many people will 5 pitchers serve if 1/8 pitcher serves one person?

Answers

5x8=40
8 divide 40 = 5

5 pitchers serve 40 people

What is the ratio of the change in y-values to the change in x-values?

Answers

Answer:

need to see the question

Step-by-step explanation:

Round 392 to the nearest 10

Answers

We need to consider the numbers in the tens digit and ones digit of 392

That would be 92

and if you think about it 92 is closer to 90 than it is closer 100

So 392 to the nearest ten would be 390
390 because 92 rounds to 90 and that's 390

Pls help ASAP!!!On a certain hot​ summer's day, 622 people used the public swimming pool. The daily prices are $ 1.75 for children and $ 2.50 for adults. The receipts for admission totaled $ 1375.00.  How many children and how many adults swam at the public pool that​ day? 22 POINTS

Answers

240 children and 382 adult swam at the public pool that day

Solution:

Let "c" be the number of childrens

Let "a" be the number of adults

Cost of 1 child ticket = $ 1.75

Cost of 1 adult ticket = $ 2.50

622 people used the public swimming pool

Therefore,

number of childrens + number of adults = 622

c + a = 622 ------ eqn 1

The receipts for admission totaled $ 1375.00

Therefore, we can frame a equation as:

number of childrens x Cost of 1 child ticket + number of adults x Cost of 1 adult ticket = 1375.00

c * 1.75 + a * 2.50 = 1375

1.75c + 2.50a = 1375 ----- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

c = 622 - a -------- eqn 3

Substitute eqn 3 in eqn 2

1.75(622 - a) + 2.50a = 1375

1088.5 - 1.75a + 2.50a = 1375

0.75a = 1375 - 1088.5

0.75a = 286.5

a = 382

Substitute a = 382 in eqn 3

c = 622 - 382

c = 240

Thus 240 children and 382 adult swam at the public pool that day

How do I solve x^2 - 8x + 16 = 25 using perfect factoring patterns?

Answers

x^2 - 8x + 16 = 25\n \n(x-4)^2=5^2\n \nx-4=5\ \ \ \vee\ \ \ x-4=-5\n \nx=5+4\ \ \ \ \ \ \ \ \ x=-5+4\n \nx=9\ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-1