COMPUTERS AND TECHNOLOGY HIGH SCHOOL

How to stay organized in an online school?

Answers

Answer 1
Answer: to stay organized on an online school is no cursing. and keep your files clean and organized
Answer 2
Answer:

Answer:

dont procrastinate and try to keep all your files organized

Explanation:

Related Questions

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To use the AutoCalculate area, select the range of cells containing the numbers for a calculation you want to verify and then press and hold or double-click the AutoCalculate area to display the Customize Status Bar shortcut menu.A) TrueB) False

In the Microsoft Office Suite, what tells a database what to insert information in the document? A. Placeholder
B. Table
C. Event handler
D. Object

Answers

A. a placeholder tells you were database should be inserted

How do computers work

Answers

Computers have an Bios which is the base of the whole OS. (Bios helps to boot up your OS for example Windows on your PC) The Bios has simple hardware settings whilst the OS has system software settings. the Hardware is linked with the system OS software to help make them work. All software in the OS system folder is linked and has permissions to work to help provide a power UI (User Interference)

Which database tool is best for simple flat files that involve calculations?

Answers

The database tool Spreadsheet software is best for simple flat files that involve calculations.
The Spreadsheet software is a computer software that performs general computation tasks using spatial relationships.
Excel is example of spreadsheet software. It organizes, stores and analyzes data in tabular form.

To select a new theme for a slideshow use the blank tile in the ribbon

Answers

to get a new slide show title just go to PowerPoint and you can find it
Go onto th tab called design, and choose which you want

What is decoding?a. putting thoughts, ideas, and feelings into words and messages
b. filtering messages through past experiences
c. minimizing external and psychological noise
d. making sense out of words and messages

Answers

Decoding is the ability of a person to perceive once ideas, writings, and words in a clear manner that is understandable by anyone and able to interpret it to another meaning also. The Answer of your question is (D.) Making sense out of words and messages

A pincode consists of N integers between 1 and 9. In a valid pincode, no integer is allowed to repeat consecutively. Ex: The sequence 1, 2,1, 3 is valid because even though 1 occurs twice, it is not consecutive. However, the sequence 1, 2, 2, 1 is invalid because 2 occurs twice, consecutively. Utilize a for loop and branch statements to write a function called pinCodeCheck to detect and eliminate all the consecutive repetitions in the row array pinCode. The function outputs should be two row arrays. The row array repPos contains the positions pinCode where the consecutive repeats occurs, and the row array pinCodeFix is a valid pincode with all the consecutive repeats removed in pinCode. Hint: The empty array operator [] is will be helpful to use.

Answers

Answer:

function [ repPos, pinCodeFix ] = pinCodeCheck( pinCode )

       pinCodeFixTemp = pinCode;

       repPosTemp = [];

   for i = 1:length(pinCode)

       if((i > 1)) & (pinCode(i) == pinCode(i - 1))

           repPosTemp([i]) = i;

       else

           repPosTemp([i]) = 0;

       end

   end

   for i = 1:length(pinCode)

       if(repPosTemp(i) > 0)

           pinCodeFixTemp(i) = 0;

       end

   end

   repPosTemp = nonzeros(repPosTemp);

   pinCodeFixTemp = nonzeros(pinCodeFixTemp);

   repPos = repPosTemp';

   pinCodeFix = pinCodeFixTemp';

   

end

Explanation:

Let me start off by saying this isn't the most efficient way to do this, but it will work.

Temporary variables are created to hold the values of the return arrays.

       pinCodeFixTemp = pinCode;

       repPosTemp = [];

A for loop iterates through the length of the pinCode array

       for i = 1:length(pinCode)

The if statement checks first to see if the index is greater than 1 to prevent the array from going out of scope and causing an error, then it also checks if the value in the pinCode array is equal to the value before it, if so, the index is stored in the temporary repPos.

        if((i > 1)) & (pinCode(i) == pinCode(i - 1))

        repPosTemp([i]) = i;

Otherwise, the index will be zero.

         else

         repPosTemp([i]) = 0;

Then another for loop is created to check the values of the temporary repPos to see if there are any repeating values, if so, those indexes will be set to zero.

         for i = 1:length(pinCode)

         if(repPosTemp(i) > 0)

         pinCodeFixTemp(i) = 0;

Last, the zeros are removed from both temporary arrays by using the nonzeros function. This causes the row array to become a column array and the final answer is the temporary values transposed.

         repPosTemp = nonzeros(repPosTemp);

         pinCodeFixTemp = nonzeros(pinCodeFixTemp);

         repPos = repPosTemp';

         pinCodeFix = pinCodeFixTemp';
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