Find the area of the following parallelogram
Find the area of the following parallelogram - 1

Answers

Answer 1
Answer:

Answer:

6 cm^2

Step-by-step explanation:

The area of a parallelogram is

A = bh where b is the base and h is the height

A = 3 *2 = 6 cm^2


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Which one is smaller than 2500ml and 25ml

Answers

25 ml is smaller than 2500 ml

What is the ratio of 5 hours to 100 minutes

Answers

for this question you should know that 5 hours is equal to 300 minutes so the ratio of 300 minutes to 100 minutes is 300/100 which is equal to 3/1 or 3 :)))
i hope this is helpful
have a nice day 
first 5x60=300
therefore...   300:100
300/50=6   and    100/50=2
6:2
therefore is 3/1

--+--+--+--+-- =30.Solve the puzzle with the--+--+--+--+-- =30.Solve the puzzle with the numbers(1,3,5,7,9,11,13,15).Numbers can be repeated.Only addition operation allowed.

Answers

I don't think it's possible, because any odd number of odd numbers
always add up to an odd number.
All given numbers are odd. The sum of odd number (in this case 5) of odd numbers is odd as well and 30 is an even number. Because of that, there's no solution.

Please help! Super confused lol

Answers

The length of OX would be 6.5 units.

If you look at the angle, it is bisected equally - meaning the ray separating it is a bisector. (The two triangles are similar by angle-angle similarity.) Since the line is a bisector, you simply divide 13 by 2 to get 6.5.

OX = 6.5

13=DX,

OX = 0.5*DX

13*0.5=6.5

NEED HELP AND FAST!
WILL GIVE BRAINLEST TO HOWEVER ANSWERS CORRECTLY.

Answers

Answer:

Polygon name: Quadrilateral

Sides: 4

Angles: 4

Concave

Step-by-step explanation:

     This polygon has 4 sides, so it is a quadrilateral. It also has 4 angles. One of the interior angles is greater than 180 degrees, meaning that this polygon is concave.

GIVEN:MN is an angle bisector of ∠JMK
Prove:m∠JMN=1/2m∠JMK

Answers

Answer:

Step-by-step explanation:

                  Statements                                           Reasons

1. MN is an angle bisector of ∠JMK        1. Given

2. ∠JMN ≅ ∠NMK                                    2. Definition of an angle bisector

3. m∠JMN ≅ m∠NMK                              3. Definition of congruent angles

4. m∠JMN + m∠NMK = m∠JMK              4. Angle addition postulate

5. m∠JMN + m∠JMN = m∠JMK              5. Substitution property

6. 2(m∠JMN) = m∠JMK                           6. Addition property of equality

7. m∠JMN = (1)/(2)(m\angle JMK)                         7. Division property of equality