What do you think will happen if you pinch your arm after you stub your toe?

Answers

Answer 1

Answer: It would distract the pain in your toe. That's all I got

Answer 2

Answer:

it would distract the pain

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Ca(OH)2 is added to a large beaker of water. How is the solution different from the original water?A...The solution turns blue litmus to red. B...The solution turns phenolphthalein pink. C...The solution has more hydrogen ions. D....The solution has fewer hydroxide ions.

What tool can be used to measure the volume of a liquid to one decimal place?

Answers

graduated cylinder could be the answer u are loking for

im guessing a ruler. Because it can help with the lengths that you need to be finding.

What mass of ammonium sulfate ((NH4)2SO4 132.15 g/mol) is required to produce 282 mL of a 2.50M solution of ammonium sulfate?

Answers

Answer:

93.17 g

Explanation:

Recall that: mol = mass/molar mass

Also; mol = molarity x volume

mole of (NH4)2SO4 to be prepared = 282/1000 (dm3) x 2.50 (mol/dm3)

= 0.705 mol

This can be used to determine the mass of (NH4)2SO4 that will be required.

mass = mole x molar mass

Hence, mass of (NH4)2SO4 required = 0.705 x 132.15

= 93.17 g

Hence, the mass of ammonium sulfate that will be required to prepare 282 mL of a 2.50M solution is 93.17 g

The study of all chemicals containing carbon1. Applied Chemistry
2. Bio Chemistry
3. Organic Chemistry
4. Inorganic Chemistry

Answers

The correct answer is
3. Organic Chemistry.....

Answer:

Organic chemistry

Explanation:

A solute is added to water and a portion of the solute remains undissolved. When equilibrium between the dissolved and undissolved solute is reached, the solution must beA)dilute B) saturated C) unsaturated D) supersaturated

Answers

Answer: Option (B) is the correct answer.

Explanation:

A solution that has maximum concentration of solute particles and on adding more solute the particles of solute remains undissolved is known as a saturated solution.

Whereas when particles of solute keep on dissolving in a solution then it is known as an unsaturated solution.

Thus, we can conclude that a solute is added to water and a portion of the solute remains undissolved. When equilibrium between the dissolved and undissolved solute is reached, the solution must be saturated.

when the solute can no longer dissolve in the solution the solvent becomes SATURATED. When no more solute can dissolve and if you look at the bottom of the beaker, test tube, pan, or glass of cold tea you can see the solute permeating out as little particles .

Compared to the freezing point of 1.0 M KCl(aq) at standard pressure, the freezing point of 1.0 M CaCl2(aq) at standard pressure is(1) lower
(2) higher
(3) the same

Answers

Answer : The correct option is, (1) lower

Explanation :

Formula used for lowering in freezing point :

$\Delta T_f=i* k_f* m$

where,

$\DeltaT_b$ = change in freezing point

$k_b$ = freezing point constant

m = molality

i = Van't Hoff factor

According to the question, we conclude that the molality of the given solutions are the same. So, the freezing point depends only on the Van't Hoff factor.

Now we have to calculate the Van't Hoff factor for the given solutions.

(a) The dissociation of $KCl$ will be,

$KCl\rightarrow K^++Cl^-$

So, Van't Hoff factor = Number of solute particles = 1 + 1 = 2

(b) The dissociation of $CaCl_2$ will be,

$CaCl_2\rightarrow Ca^(2+)+2Cl^-$

So, Van't Hoff factor = Number of solute particles = 1 + 2 = 3

The freezing point depends only on the Van't Hoff factor. That means higher the Van't Hoff factor, lower will be the freezing point and vice-versa.

Thus, compared to the freezing point of 1.0 M $KCl(aq)$ at standard pressure, the freezing point of 1.0 M $CaCl_2(aq)$ at standard pressure is lower.

water is mixed with solid calcium nitrate in a beaker. write balanced net ionic equation for the reaction

Answers

When calcium nitrate is added or mixed with water, the substance would dissociate into its corresponding ions which are calcium and nitrate ions. The ionic equation would be:

Ca(NO3)2 = Ca2+ + NO3-

Hope this answers the question. Have a nice day. Feel free to ask more questions.

Answer : The net ionic equation will be,

$Ca^(2+)(aq)+2OH^(-)(aq)\rightarrow Ca(OH)_2(s)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced ionic equation will be,

$2H_2O(aq)+Ca(NO_3)_2(aq)\rightarrow 2HNO_3(aq)+Ca(OH)_2(s)$

The ionic equation in separated aqueous solution will be,

$4H^+(aq)+2OH^(-)(aq)+Ca^(2+)(aq)+2NO_3^(-)(aq)\rightarrow Ca(OH)_2(s)+2H^+(aq)+2NO_3^(-)(aq)$

In this equation, $H^+\text{ and }NO_3^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Ca^(2+)(aq)+2OH^(-)(aq)\rightarrow Ca(OH)_2(s)$

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