Type in expanded form. Use to indicate multiplication. 5^2
Answers
Answer:
5 x 5
Step-by-step explanation:
Hope this helps.
Related Questions
Check by divisibility test the number 26458900 is divisible by 11 and 4.
What is 1÷0?and is it possible
An equation is shown below:3(4x − 2) = 1 Which of the following correctly shows the first two steps to solve this equation? Step 1: 12x − 2 = 1; Step 2: 12x = 3 Step 1: 12x − 6 = 1; Step 2: 12x = 7 Step 1: 7x + 1 = 1; Step 2: 7x = 0 Step 1: 7x − 5 = 1; Step 2: 7x = 6
Which is true of point K at (0, –5)? A. Point K is to the left of the y-axis. B. Point K is on the x-axis. C. Point K is on the y-axis. D. Point K is to the right of the y-axis.
3x + 2y = 4
A) (-2, 5)
B) (1, 4)
C) (2, -1)
D) (4, -4)
Answers
Answer:
(C) (2,-1)
Step-by-step explanation:
The given system of equations is :
(1)
and (2)
Multiply equation (1) with 2 and then subtract equation (2) from it, we get
⇒
⇒
⇒
Substitute the value of x=2 in equation (1), we get
⇒
⇒
⇒
Therefore, x=2 and y=-1. that is (2,-1).
A : 5.-2 + 5 ≠9 not solution
B : 5.1 + 4 = 9 so 3.1 + 2.4 = 11 ≠4 not solution
C: 5.2 + = 9 so 3.2 + 2.-1 = 4 both are right then C is solution
D: 5.4 - 4 = 16 ≠ 9 not solution
Answers
Answers
Let a the greater number
b the smaller one
a-b=18
2b=3a-56
==>
a-b=18 |*(-2)
3a-2b=56
==>a=56-2*18
==>a=20 and b=a-18=2
Proof a-b=20-2=18
2=3*20-56
Numbers are 20 and 2.
Answers
3/4
1/4
1/12
1/36
0/60
The pattern is -1/x every 2 +x/8
How i got this was 36/12=3
3*12=36
so 60-36=24
24x3/2+24=60
then 60/5=12
Hopethis helped
To find density use: density
mass
volume
5 cm
16 cm
10 cm
Determine the density of the Geometry textbook in g/cm3.
Round your answer to the nearest hundredths place.
Answers
The density of the Geometry textbook is 0.06 g/cm^3.
To find the density of the Geometry textbook in g/cm^3, we need to find its volume first. The volume of a rectangular prism is given by the formula V = l x w x h, where l is the length, w is the width, and h is the height.
In this case, the length is 16 cm, the width is 10 cm, and the height is 5 cm. Therefore, the volume of the Geometry textbook is:
V = l x w x h = 16 cm x 10 cm x 5 cm = 800 cm^3
Now, we can find the density of the textbook using the formula:
Plugging in the given mass of 48 grams and the calculated volume of 800 cm^3, we get:
density = 48 g / 800 cm^3 = 0.06 g/cm^3
Therefore, the density of the Geometry textbook is 0.06 g/cm^3. We rounded our answer to two decimal places as the original mass was given in grams to two decimal places.
Learn more about Geometry here:
#SPJ11
3x-2y=9
y=2x-7
Answers
3x-2(2x-7)=9
3x-4x+14=9
-1x=-5
x=5
next solve for y
y=2x-7
y=2(5)-7
y=10-7
y=3
And now we have x=5, and y=3.
3x - 2y = 9
3x - [2(2x-7)]= 9
3x - (4x - 14) = 9
3x - 4x + 14 = 9
-x + 14 = 9
-x = -5
x = 5
y = 2x - 7
y = 2(5) - 7
y = 10 - 7
y = 3