Which of the following is not an identity?O A. 2cos2x-1 = 1 - 2sin2x
O B. secx cscx(tanx + cotx) = sec2x + csc2x
O C. 2sin?x- sinx = 1
D. sin2x + tan2x + cos2x = secax

Answers

Answer 1
Answer:

2sin^2 - x - Sinx =1 and sec x csc x (tanx+ cotx) = sec^2x + csc^2x is not an identity. Option B and C is correct.

Out of Four options are given, which of them is not an identity is to be determined.

What is identity?

An identity is the common case formula that helps to solve mathematics.

1)

2cos^2x-1 = 1 - 2 sin^2x\n \ncos2x =cos2x

It is also a perfect identity.

2)

secx cscx(tanx+ cotx) = sec^2x + csc^2x\n\n\nsec x cscx (sinx/cos x + cosx/sinx) = sec^2 + csc^2x\n\nsecx cscx (sin^x+cox^2x/cosxsinx) = sec^2x +csc^2x

     It is also not an identity.

3) 2sin^2-X- Sinx=1

It's not an identity cause it is form of equation and contain -x.

4)

sin^2x+ tan^2x + cos^2x = sec^2x\n sin^2x + cos^2x = sec^2x -tan^2x = 1

It is a perfect identity.

Thus, 2sin^2- x - Sinx =1 and sec x csc x (tanx+ cotx) = sec^2x + csc^2x is not an identity. Option B and C is correct.

Learn more about identity here:

brainly.com/question/6971003

#SPJ5

Answer 2
Answer:

Answer:

C. 2 sin^2x-sinx=1

Step-by-step explanation:

a p e c


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