+
9
To add or subtract fractions, their denominators
must be the same. We can get a common
denominator by multiplying the second fraction
by 3/3.
6
-
(-}).
What number belongs in the green box?
Enter
Using the Pythagorean theorem on the given conditions, the length of the quarterback's pass was calculated to be 13 yards.
The subject of this question falls under Mathematics, specifically in the topic of the Pythagorean Theorem. To solve this problem, we should recognize it as a right triangle problem. The quarterback is at one point, the goal line forms the base, and the player is at the third point. We can then use the Pythagorean Theorem (a^2 + b^2 = c^2), where c is the hypotenuse, or the path of the football.
In this case, the difference in yard lines (60 - 55 = 5 yards) and the distance to the left (12 yards) form the two other sides of the triangle. We then calculate the pass length using the formula, √((5^2) + (12^2)). The square root of (25 + 144) equals the square root of 169, which gives the answer 13 yards. Therefore, the length of the pass was 13 yards.
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Answer:
-31.32
Step-by-step explanation:
(–0.5)(–1.2)(–5.22)
6(-5.22)
=>-31.32
Answer:
290n + 120 ≤ 1400
4 days
Step-by-step explanation:
Given that:
Vacation budget = $1400
Cost on hotel = $110 per night
Cost on food = $80 per day
Cost on activities = $100 per day
Cost on gas = $120 for entire trip
Number of nights they can afford to stay
Let the Number of nights they can afford = n
((110 + 80 + 100) * number of nights) + 120 ≤ vacation budget
290n + 120 ≤ 1400
290n ≤ 1400 - 120
290n ≤ 1280
n ≤ 1280 / 290
n ≤ 4.4137
Hence, longest vacation they can take is 4 days
The family can afford up to 4 nights for their vacation, as per the inequality 290n + 120 ≤ 1400, where 'n' stands for the number of nights.
Let's first define the total expenses per day as the sum of the hotel costs ($110), food costs ($80), and the daily amount for activities ($100). This adds up to $290 per day. So for 'n' nights, the family will be spending $290n. In addition, there's a $120 onetime expense for gasoline. Hence, the inequality representing their spending will be: 290n + 120 ≤ 1400.
To find the longest vacation this family can afford, we simply need to solve this inequality. Pay attention as we do this: 290n ≤ 1280 (subtracting 120 from both sides), and then n ≤ 4.41 (dividing both sides by 290).
Since the number of nights 'n' should be a whole number, the family can afford up to 4 nights on their vacation.
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