PHYSICS COLLEGE

Tonya picks up a leaf from the ground and holds it at arm’s length. She lets go, and the leaf falls to the ground. What force pulled the leaf to the ground?

Answers

Answer 1

Answer:

Answer:

Gravity

Explanation:

Gravity is constantly pulling objects downward. Without it, everything would float out into space.

I hope this answer helps :)

Answer 2

Answer:

Answer:

The answer for the given question above would be option C. GRAVITATIONAL FORCE. Based on the given scenario above of a leaf that falls to the ground when Tonya let it go, the force that pulled the leaf to the ground is the gravitational force. This kind of force is a force that attracts any object with mass.

Hope this helps!!!

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Why must the Ojibwe people pay close attention to the seasons? a.) they must be ready to move to a new place where they can hunt

b.) they only fish during the warmest times of the day

c. they must know the right time of year for Gathering certain foods

d.) they still catch walleye with the steering method

Answers

The Ojibwe people pay close attention to the seasons in order to know right

time of year for gathering certain foods.

The Ojibwe mostly hunt for fishes through the use of various techniques

such as:

Fishing at night

Use of flashlight

Why do they hunt for Fishes at night?

They hunt for fishes at night because they are usually docile during that time

which enables them to catch them easily as against during the day when

they are much active.

Read more about Ojibwe people here brainly.com/question/24963033

Answer:C. They must know the right time of year for gathering certain foods

Explanation:

I got it correct

an object down, but this is not true. If you place a box of mass 8 kg on a moving horizontal conveyor belt, the friction force of the belt acting on the bottom of the box speeds up the box. At first there is some slipping, until the speed of the box catches up to the speed of the belt, which is 5 m/s. The coefficient of kinetic friction between box and belt is 0.6. (a) How much time does it take for the box to reach this final speed

Answers

Answer:

Explanation:

ASSUMING the belt is horizontal

kinetic friction force is μmg = 0.6(8)(9.8) = 47.04 N

Horizontal acceleration is

a = F/m = 47.04 / 8 = 5.88 m/s²

t = v/a = 5.0 / 5.88 = 0.85034...

t = 0.85 s

A rocket sled accelerates at a rate of 49.0 m/s2 . Its passenger has a mass of 75.0 kg. (a) Calculate the horizontal component of the force the seat exerts against his body. Compare this with his weight using a ratio. (b) Calculate the direction and magnitude of the total force the seat exerts against his body.

Answers

Explanation:

It is given that,

Mass of the passenger, m = 75 kg

Acceleration of the rocket, $a=49\ m/s^2$

(a) The horizontal component of the force the seat exerts against his body is given by using Newton's second law of motion as :

F = m a

$F=75\ kg* 49\ m/s^2$

F = 3675 N

Ratio, $R=(F)/(W)$

$R=(3675)/(75* 9.8)=5$

So, the ratio between the horizontal force and the weight is 5 : 1.

(b) The magnitude of total force the seat exerts against his body is F' i.e.

$F'=√(F^2+W^2)$

$F'=√((3675)^2+(75* 9.8)^2)$

F' = 3747.7 N

The direction of force is calculated as :

$\theta=tan^(-1)((W)/(F))$

$\theta=tan^(-1)((1)/(5))$

$\theta=11.3^(\circ)$

Hence, this is the required solution.

Final answer:

The horizontal component of the force the seat exerts against the passenger's body is 3675 N. The ratio of this force to the passenger's weight is 5. The total force the seat exerts has a magnitude of 3793 N.

Explanation:

(a) To calculate the horizontal component of the force the seat exerts against the passenger's body, we can use Newton's second law, which states that force is equal to mass times acceleration. In this case, the mass of the passenger is 75.0 kg and the acceleration of the rocket sled is 49.0 m/s2. So the force exerted by the seat is:

Force = mass * acceleration

Force = 75.0 kg * 49.0 m/s2

Force = 3675 N

Now let's compare this force to the passenger's weight. The weight of an object is given by the formula:

Weight = mass * gravitational acceleration

Weight = 75.0 kg * 9.8 m/s2

Weight = 735 N

To find the ratio, we divide the force exerted by the seat by the weight of the passenger:

Ratio = Force / Weight

Ratio = 3675 N / 735 N

Ratio = 5

(b) The total force the seat exerts against the passenger's body has both a horizontal and vertical component. The direction of the total force is the same as the direction of the acceleration of the rocket sled. The magnitude of the total force can be found using the Pythagorean theorem:

Total Force = √(horizontal component2 + vertical component2)

Total Force = √(36752 + 7352)

Total Force = 3793 N

Learn more about Force here:

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Question 3 of 10Which of the following is an example of revolution?
O A. The Moon spinning on its axis
O B. The Sun spinning on its axis
C. Earth orbiting the Sun
D. A ballet dancer spinning in place

Answers

Answer:

Option C

Explanation:

Revolution: When an object moves around another object it is called revolution.

Rotation: When an object spins around its axis it's called rotation

Answer:C

Explanation:

Good luck!

An electron in a vacuum chamber is fired with a speed of 7400 km/s toward a large, uniformly charged plate 75 cm away. The electron reaches a closest distance of 15 cm before being repelled. What is the plate's surface charge density?

Answers

Answer:

2.29e-9C/m²

Explanation:

Using E = σ/ε₀ means the force on the electron is F = eE = eσ/ε₀.

The work done on the electron is W = Fd = deσ/ε₀. This equals the kinetic energy lost, ½mv².

½mv² = deσ/ε₀

d = 75cm – 15cm = 60cm = 0.6m

σ = mv²ε₀/(2de)

. .= 9.11e-31 * (7.4e6)² * 8.85e-12 / (2 * 0.6 * 1.6e-19)

. .= 2.29e-9 C/m² (i.e. 2.29x10^-9 C/m²)

James weighs 120 pounds. He ran up the steps which rose 12 feet. John weighs 91 pounds. He ran up the same steps as James. If both boys reached the top of the 12-foot stairs at the same time, which boy had the greatest horsepower?

Answers

Mass of James = 54.431kg
Distance ran by James = 3.6576m
Mass of John= 41.277kg
Distance relan by John= 3.6576m

Work done by James = 54.431kg*10N/kg*3.6576m= 1990.87J

Work done by John= 41.277kg*10N/kg*3.6576m=1509.75J

Horsepower = work done / time since time is same, James has larger horsepower

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