Write the complete name (prefix + unit) for each of the following numerical values:a) 0.10 g

b) 1 × 10^-6 g

c) 1000 g

d) 0.01 g

e) 0.001 g

f) 1 × 10^9 g

Answers

Answer 1
Answer:

The (standard) unit of mass is gram. So, the complete name of each of the units is the name of the numerical value followed by the term "gram".

The complete names are:

  1. 1 decigram
  2. 1 microgram
  3. 1 kilogram
  4. 1 centigram
  5. 1 milligram
  6. 1 gigagram

In numerical representation of numbers, the meaning of the given numbers are:

0.10 \to deci

10^(-6) \to micro

1000 \to kilo

0.01 \to centi

0.001 \to milli

10^9 \to giga

To complete the names, we simply add "gram" to the above representations. So, we have:

0.10 \to decigram

10^(-6) \to microgram

1000 \to kilogram

0.01 \to centigram

0.001 \to milligram

10^9 \to gigagram

Read more about names of numerical values at:

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At the end of chemical reactions, what is the total mass of the reactants compared to the total mass of the products? a) The product is doubled. b) The product is half the mass of the reactants. c) The mass is the same. d) The mass changes depending on the reaction.

Answers

Answer:

c) The mass is the same

Explanation:

According to the Law of Conservation of Mass, the total mass of the reactants in a chemical reaction is always equal to the total mass of the products formed. This means that the total mass of the reactants and the total mass of the products will always be the same.

What is the definition of chemistry​

Answers

: a science that deals with the composition, structure, and properties of substances and with the transformations that they undergo
2a : the composition and chemical properties of a substance
the chemistry of iron
b : chemical processes and phenomena (as of an organism)

Fill in the missing reactant: NaOH + _____ → NaClO₂ + H₂O a. Cl₂
b. HCl
c. HClO
d. HClO₂
e. HClO₃

Answers

THE ANSWER IS OPTION D HClO2

In the flame test, barium ions produce a green flame whereas calcium ions produce a red flame. In your own words, explain these observations in terms of the electron structure of these two ions. In other words explain how these different colors are produced and why using your understanding of atomic structure.

Answers

Answer:

The Barium flame is green because it is a difficult flame to excite, therefore for it to trigger a flame it is necessary that it be too excited for it to occur.

The reddish color of calcium is due to its high volatility and it is sometimes very difficult to differentiate it from strontium.the compression of these elements is due to being able to make them work during combustion

Explanation:

The flame test is a widely used qualitative analysis method to identify the presence of a certain chemical element in a sample. To carry it out you must have a gas burner. Usually a Bunsen burner, since the temperature of the flame is high enough to carry out the experience (a wick burner with an alcohol tank is not useful). The flame temperature of the Bunsen burner must first be adjusted until it is no longer yellowish and has a bluish hue to the body of the flame and a colorless envelope. Then the tip of a clean platinum or nichrome rod (an alloy of nickel and chromium), or failing that of glass, is impregnated with a small amount of the substance to be analyzed and, subsequently, the rod is introduced into the flame, trying to locate the tip in the least colored part of the flame.

The electrons in these will jump to higher levels from the lower levels and immediately (the time that an electron can be in higher levels is of the order of nanoseconds), they will emit energy in all directions in the form of electromagnetic radiation (light) of frequencies characteristics. This is what is called an atomic emission spectrum.

At a macroscopic level, it is observed that the sample, when heated in the flame, will provide a characteristic color to it. For example, if the tip of a rod is impregnated with a drop of Ca2 + solution (the previous notation indicates that it is the calcium ion, that is, the calcium atom that has lost two electrons), the color observed is brick red .

Answer:

The different colours produced come from the different wavelength of the spectrum of light as the excited electrons in the metals return to their original state on cooling down.

Explanation:

The flame test is an analytical procedure used to identify different metals by passing them through a flame.

The flame, which is a source of heat energy heats up the metals and excites their outermost electrons which transit to the next energy level. On cooling down, as the excited electrons return to their original state, they emit different colours corresponding to the spectrum of light. Electrons of larger atoms like Barium emit light of higher frequency and lower wavelength and hence exhibits colours closer to the ultraviolet part of the electromagnetic spectrum while smaller atoms like Calcium emit light of lower frequency and higher wavelength and emit light closer to the infrared part of the spectrum

Baruim (atomic number 56) and Calcium (atomic number 20) are both metals in group two of the periodic table.

They both have two electrons in their outermost shell and are represented by Ba²⁺ and Ca²⁺.

When both metals are passed to through the flame test, the two outermost electrons in both metals are excited.

However because the outermost electrons in Barium are farther to the nucleus than those in Calcium, it takes a lesser amount of heat energy to excite them than that of Calcium which is closer to the nucleus.

The spectrum of light which is usually represented by 'ROYGBIV' has the following colours : Red, Orange,Yellow, Green, Indigo and Violet with Red having their highest wavelength (or shortest frequency) and Violet the shortest wavelength (or highest frequency).

Barium's green colour is because it outermost electrons emit light in the range of the Green spectrum of light and calcium's red colour is because its outermost electrons emit light in the range of the Red spectrum of light

What is the IUPAC name for the compound FeS?(1) iron(II) sulfate (3) iron(II) sulfide
(2) iron(III) sulfate (4) iron(III) sulfide

Answers

The correct answer is option 3. The IUPAC name is Iron(II) sulfide. It is the less stable amorphous form.  When this is powdered, it is pyrophoric or it ignites spontaneously in air. It readily reacts with hydrochloric acid producing hydrogen sulfide.

The IUPAC name for the compound FeS is "iron(II) sulfide." Therefore, option 3 is correct.

The IUPAC (International Union of Pure and Applied Chemistry) name is a systematic way of naming chemical compounds.

The compound FeS consists of iron (Fe) and sulfur (S) atoms. In FeS, iron has a +2 oxidation state, and sulfur has a -2 oxidation state.

According to the IUPAC nomenclature rules for naming inorganic compounds, the cation (iron) is named first, followed by the anion (sulfide).

To indicate the oxidation state of iron, the Roman numeral II is used in parentheses after the name "iron." The resulting name is "iron(II) sulfide."

To learn more about IUPAC, follow the link:

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The molar heat of fusion for water is 6.01 kJ/mol. How much energy is released when 36.8 g of water freezes at its freezing point?

Answers

The answer there is 12.3 kJ. First you have to calculate the amount of heat released (n) based on the given. Just multiply 36.8 grams of water to a mole of water per 18.015 grams, which will give you 2.04 moles of H2O. Using the formula heat released (q) = number for moles of the substance (n) multiplied to the molar enthalpy of fusion of the substance (H), you will have the (2.04 mole)(-6.01 kJ/mole), giving you an answer of -12.3kJ.

Answer:

12.3 kJ

Explanation: