MATHEMATICS COLLEGE

9x-3=87 what is the anwser

Answers

Answer 1

Answer:

Answer:

x=10

Step-by-step explanation:

9x-3=87

you add 3 to both sides

9x-3(+3)=87(+3)

which equals

9x=90

90/9= 10

answer:

x =10

I hope this helped!

Answer 2

Answer:

Answer:

x=10

Step-by-step explanation:

9x-3=87

add 3 to both sides

9x=90

divide by 9 on both sides

x=10

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Find the equation of the line through the points (-3,-3) and (2,-1) using point-slope form. Then rewrite theequation in slope-intercept form.

Answers

Answer: See below

Step-by-step explanation:

The point-slope equation is y-y₁=m(x-x₁). Since we don't know our slope, we can use the formula $m=(y_(2)-y_(1) )/(x_(2)-x_(1) )$ to find the slope. All we have to do is use the coordinate we were given and plug it into the formula.

$m=(-1-(-3))/(2-(-3)) =(2)/(5)$

Now that we have the slope, we can fill out the point-slope equation.

y-(-3)=2/5(x-(-3))

y+6=2/5(x+3)

This is the point-slope form.

Now, we can distribute and solve to get slope-intercept form.

y+6=2/5x+6/5

y=2/5x-24/5

Final answer:

The equation of the line through the points (-3,-3) and (2,-1) can be found using point-slope form. It is y = (2/5)x - 9/5 in slope-intercept form.

Explanation:

To find the equation of a line using the point-slope form, we need to determine the slope of the line and use one of the given points to write the equation. Firstly, let's find the slope of the line using the formula: m = (y2 - y1) / (x2 - x1). Plugging in the coordinates (-3, -3) and (2, -1) into the formula gives us m = (-1 - (-3)) / (2 - (-3)) = 2/5. Now, we can choose one of the points (for example, (-3, -3)) and use the point-slope form equation: y - y1 = m(x - x1). Substituting the values, we get y - (-3) = (2/5)(x - (-3)). Simplifying the equation yields y + 3 = (2/5)(x + 3), which is the equation of the line in point-slope form.

To rewrite the equation in slope-intercept form y = mx + b, we need to isolate the y variable. Distributing the (2/5) to (x + 3) in the point-slope form equation gives us y + 3 = (2/5)x + 6/5. Subtracting 3 from both sides gives us y = (2/5)x + 6/5 - 3. Simplifying further, the equation becomes y = (2/5)x - 9/5. Therefore, the equation of the line through (-3, -3) and (2, -1) in slope-intercept form is y = (2/5)x - 9/5.

Learn more about Equation of a line here:

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Arc Length and Radians question- please help! Will mark brainliest! Is 20pts!The answer is shown but please give me an explanation so I can show my work!

Answers

Answer:

Step-by-step explanation:

If we convert from degrees into radians, we can use the formula

$s=r\theta$ , where s is the arc length, r is the radius and θ is the angle in radians.

To convert from degrees to radians, we multiply by $(\pi)/(180)$

So $(140 \pi)/(180)$ is our angle in radians, and we have the radius - we can now plug in these two values into our equation.

$s=24*(140 \pi)/(180) =58.64$

Answer:

Step-by-step explanation:

length of arc= (arc angle/360) * 2πr

length= 140/360 *2*22/7*24

length=58.88 feet ~59 feet(approx)

Over three days I earn 2568. On the first day I made twice as much as the second day. On the third day I made three times as much as the second day. How much did I earn on the first day.

Answers

Answer:

I earned $856 on the first day

Step-by-step explanation:

Let's call

x = earning on the second day

2x = earnings on the first day

3x = earnings on the third day

The total earnings are $2568, thus

x + 2x + 3x = 2568

Simplifying:

6x = 2568

Dividing by 6:

x = 2568/6

x = 428

I earned $428 on the second day.

2x = 2*$428 = $856

I earned $856 on the first day

If f Subscript x(a,b)equals f Subscript y(a,b)equals0, does it follow that f has a local maximum or local minimum at (a,b)? Explain. Choose the correct answer below. A. Yes. The point (a,b) is a critical point and must be a local maximum or local minimum. B. Yes. The tangent plane to f at (a,b) is horizontal. This indicates the presence of a local maximum or a local minimum at (a,b). C. No. One (or both) of f Subscript x and f Subscript y must also not exist at (a,b) to be sure that f has a local maximum or local minimum at (a,b). D. No. It follows that (a,b) is a critical point of f, and (a,b) is a candidate for a local maximum or local minimum.

Answers

Answer:

Step-by-step explanation:

The point must be a critical point but it could be a saddle point. If the point is a saddle point it would not be neither a maximum nor a minimum. So it must be critical but it does not follow directly that it has a local maximum or local minimum.

Therefore D. (a,b) would be a candidate, but is not necessarily a maximum or minimum. It could be a saddle.

two angles are supplementary. One of the angles has a measure of 60 degrees. What is the measure of the other angle?