PHYSICS HIGH SCHOOL

If frequency is kept constant, how are the velocity and wavelength of a wave related?

Answers

Answer 1

Answer:

Answer;

Velocity and wavelength are directly proportional when frequency is kept constant.

Explanation;

Frequency of a wave is the number of complete oscillations made by a given wave in one second.
Wavelength on the other hand, is the distance between two successful crests or troughs in a transverse wave or two successful rarefactions or compressions in a longitudinal waves.
The speed of a wave is given by the product of the frequency of a wave and the wavelength.
Speed = Frequency × wavelength,
Therefore, if frequency is kept constant, then the speed of a wave is directly proportional to the wavelength, such that an increase in wavelength increases the speed of the wave and vice versa.

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Does a light bulb with a greater wattage have a greater brightness

Answers

Only within the same technology. / / / If both of the bulbs you're comparing are incandescent, or both fluorescent, or both CFL, or both LED, then the one that uses more power is brighter. But a CFL with the same brightness as an incandescent bulb uses less power, and an LED bulb with the same brightness as both of those uses less power than either of them.

Yes. If a lamp develops a higher power certainly produce more luminosity, more brightness.

Frequency corresponds to the perception of a sound's A) Loudness B) Timbre C) Pitch D) Duration

Answers

Answer:

d.] duration

Explanation:

no explanation

A 2210 kg 2210 kg space station orbits Earth at an altitude of 5.39 × 10 5 m. 5.39×105 m. Find the magnitude of the force with which the space station attracts Earth. The mass and mean radius of Earth are 5.98 × 10 24 kg 5.98×1024 kg and 6.37 × 10 6 m, 6.37×106 m, respectively.

Answers

Answer:

18466.68 N

Explanation:

mass of satellite, m = 2210 kg

mass of earth, M = 5.98 x 10^24 kg

distance between surface of earth and the satellite, h = 5.39 x 10^5 m

radius of earth, R = 6.37 x 10^6 m

The force between the earth and the satellite is given by

$F = (GMm)/(\left (R+h \right )^(2))$

$F = (6.67* 10^(-11)* 5.98* 10^(24)* 2210)/(\left (6.37+0.539 \right )^(2)* 10^(12))$

F = 18466.68 N

Consider two metallic rods mounted on insulated supports. One is neutral, the other positively charged. You bring the two rods close to each, but without contact, and briefly ground the the neutral rod by touching it with your hand.

Answers

Answer:The rod touching your hand will have a Negative charge.

Explanation: This phenomenon is described as charging by induction,the other iron rod became charged as a result the repulsion force existing between the positively charged iron rod and the electronic forces around the election sphere. This make it different from the charging done by contact where both iron rods have close contact and electron transfer is achieved through contact. The shows that an electric charge can be persuaded and caused to transfer to another metallic particle without physical contact with the charged metallic particle.

Answer:

The initial neutral rod would be induced with negative charges.

Explanation:

This process is called charging by induction. When you bring the charged rod close to that of the neutral, the charges in it would be redistributed. The positively charged rod attracts the negative charges within the neutral rod and repel like charges. Touching the neutral with hand causes the positive charge to be neutralised due to earthing. Thus the neutral rod has now been charged negatively.

a. Define Valency. b. Write the symbol and valency of the following : (i) Oxygen (ii) potassium 7. a. Magnesium burns in Oxygen to form Magnesium Oxide. a) Name the reactants b) Name the Products c) Write the word equation for the above reaction.

Answers

⚘ YourAnswers:

A) Valency is the combining capacity of any element. Valence electrons refers to the electrons found in the outermost shell of the atom of the element.

B) Symbol and valency:

Oxygen(O) = (At. no. 8) = -2(Valency)
Potassium(K) = (At. no. = 19) = +1(Valency)

C) The reaction would be:

$\large{ \boxed{ \rm{2Mg + O_2 \longrightarrow \: 2MgO}}}$

Reactants = Magnesium and Oxygen
Products = Magnesium oxide
Word equation:

$\large{ \boxed{ \rm{Magnesium + Oxygen \longrightarrow Magnesium oxide.</p><p>}}}$

━━━━━━━━━━━━━━━━━━━━

Answer:

Oxygen-Symbol-O Potassium Symbol-K

A driver in a Volkswagen bug (mass = 1335 kg) pulls out going 10 miles per hour in front of a Ford pickup truck (mass = 2675 kg) which is traveling 40 miles per hour. The two vehicles experience a head-on collision. Which of the following statements is true concerning the forces that each vehicle (and driver) experience in this collision? a. The Volkswagen bug experiences a much greater force than the Ford pickup truck due to the greater speed of the truck.
b. The Volkswagen bug experiences a much greater force than the Ford pickup truck due to the larger mass of the truck.
c. The Volkswagen bug experiences a force that is the same as the Ford pickup truck experiences.
d. The Volkswagen bug experiences a much smaller force than the Ford pickup truck due to the smaller speed of the Volkswagen bug.
e. The Volkswagen bug experiences a much smaller force than the Ford pickup truck due to the smaller mass of the Volkswagen bug

Answers

Answer:C

Explanation:

Given

mass of Volkswagen $m_1=1335 kg$

speed of Volkswagen $v_1=10 mi/hr$

mass of Ford pick up $m_2=2675 kg$

speed of ford pick up $v_2=40 mi/hr$

When two bodies collide head-on then force experienced by both the bodies will be the same but opposite in direction.

According to newton's third law, the force exerted by one particle on another is equal to the force exerted by the second particle on first.

Thus two bodies will experience the same force

Answer:

c. The Volkswagen bug experiences a force that is the same as the Ford pickup truck experiences.

Explanation:

Given:

mass of Volkswagen bug, $m_v=1335\ kg$

speed of Volkswagen bug, $v_v=10\ mi.hr^(-1)$

mass of Ford pickup, $m_f=2675\ kg$

speed of Ford pickup, $v_f=40\ mi.hr^(-1)$

Since both undergo a head-on collision they both face the equal impact in accordance with the Newton's third law of motion which states that every action has equal and opposite reaction.

So the bug the force applied by the bug on the pickup is equal to the force applied by the pickup on the bug. This happens only till both the masses are in contact with each other.

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