Read the real-world situation and substitute in values for the projectile motion formula. Then solve the resulting quadratic equation by factoring to answer the question. An airplane pilot jumps out of an airplane and has an initial velocity of 60 feet per second downwards. How long does it take to fall from 1000 feet to 900 feet before the parachute opens? The pilot falls for seconds before the parachute opens.

Solving quadratic equation 16 t² -60t -100=0 formed by Projectile Motion Formula and given conditions it is found that it takes t = 5 seconds to fall from 1000 feet to 900 feet before the parachute opens.

What is a quadratic equation?

Quadratic equation is an equation which contains one unknown variable and the highest power of this unknown variable is 2. Let x be the unknown variable then the standard quadratic equation in x is given by

ax²+bx+c =0, where a, b, c are constants and a≠0

We can solve this equation by factorizing ax²+bx+c and  putting those factors equal to zero to solve for x.

Projectile Motion Formula h = -16 t² + v t + s,

where t = time in seconds

h = height of the projectile

v = initial velocity

s= starting height of fall

Given s = 1000 feet, v= 60 feet per second, h = 900 ft

And t we have to find.

Projectile motion equation becomes:

900 = -16 t² + 60 t + 1000

⇒16 t² -60t + 900-1000=0

⇒16 t² -60t -100=0, which is a quadratic equation in variable t

Factorizing this quadratic equation

⇒ 16t² - 80t + 20t -100 =0

⇒16t(t -5) + 20( t - 5 ) =0

⇒ (16t +20) ( t-5)=0

Putting these factors equal to zero

16t +20 =0 ⇒ t = -20/16, which is neglected as time cannot be negative.

t-5 = 0⇒ t =5

Therefore it takes 5 seconds to fall from 1000 feet to 900 feet before the parachute opens.

Also, Learn more about the quadratic equations from the link below:

brainly.com/question/17177510

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Answer:It will take 5 sec for a parachute to open.I did it on a piece of paper for u to show u more information

Step-by-step explanation: