MATHEMATICS HIGH SCHOOL

Solve 1/2n + 3 < 5 ??

Answers

Answer 1

Answer:

Answer:

n<4

Step-by-step explanation:

Answer 2

Answer:

Answer:

$n < 4$

Step-by-step explanation:

$(1)/(2) n + 3 < 5 \n subtract \: 3 \: from \: both \: sides \n \n (1)/(2) n < 2 \n divide \: both \: sides \: by \: (1)/(2) \n \n n < 4$

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1What is the y-intercept of a line that has a slope of 2 and passes through point (8,3)?13511

A 135 degree angle is classified as what

Answers

An Acute angle is an angle is under 90 degrees, a right angle is 90 degrees, and obtuse angle is greater than 90 degrees but less than 180 degrees.... which out of these angles you would choose an Obtuse angle.

Select True or False for each statement.True False

The graph of a function is always a straight line.

The equation y=xy=x represents a function.

Answers

1. False
2. False
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Explain when each method(graphing, substitution,linear combinations) is a good method to find a solution to a system of equations.

Answers

Graphing is a good method when you have small integers or fractions as your slope.
Substitution is a good method when you have two equations, and when one of the coefficient of the variables is one.
Linear combinations is a good method when you have the same coefficient for the same variable in 2 different equations.

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If the eccentricity of an ellipse is 0.43 and the length of its major axis is 11 units, how far from the center are the foci located?

Answers

Answer:

2.365 unit far away the center are the foci located.

Step-by-step explanation:

Given : If the eccentricity of an ellipse is 0.43 and the length of its major axis is 11 units.

To find : How far from the center are the foci located?

Solution :

The eccentricity of an ellipse is defined as

$e=(c)/(a)$

Where, e is the eccentricity

c is the distance from center to focus

a is the distance between focus to vertex.

We have given,

Eccentricity of an ellipse is 0.43 i.e. e=0.43

The distance between focus to vertex is the half of the length of its major axis.

i.e. $a=(11)/(2)$

Substitute in the formula,

$0.43=(c)/((11)/(2))$

$c=0.43* (11)/(2)$

$c=2.365$

Therefore, 2.365 unit far away the center are the foci located.

A function g(x) has x-intercepts at (1/2, 0) and (6, 0). which could be g(x)?A. g(x) = 2(x + 1)(x + 6)
B. g(x) = (x – 6)(2x – 1)
C. g(x) = 2(x – 2)(x – 6)
D. g(x) = (x + 6)(x + 2)

Answers

The x-intercepts of a function are used to express the function into factored form:
From (1/2, 0)
(x - 1/2)

From (6, 0)
(x-6)

(x - 1/2) (x-6) = 0
(2x -1)(x-6) = 0

The function is:
B. g(x) = (x – 6)(2x – 1)

Answer:

I believe the answer is B.

What is '7b-2b+3-1' ? Need working and it's equations!!

Answers

7b - 2b + 3 - 1 = 0

(7b - 2b) = 5b
3 - 1 = 2

Thus:

5b + 2 = 0
5b = -2
b = -2/5 = -0.4

7b-2b+3-1=0
5b+2=0
5b=-2
b=-2/5

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