MATHEMATICS HIGH SCHOOL

How would I rewrite this?

Answers

Answer 1

Answer:

Answer:

-The answer is $y^2$ .

Step-by-step explanation:

When you divide numbers/variables with exponents, the exponents will subtract each other:

$(y^5)/(y^3) =y^2$

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Find the distance between the two points rounding to the nearest tenth(if neccesary) (0,-9) and (-4,-3)

Answers

Answer:

To find the distance between two points, we can use the formula for the distance between two points in a coordinate plane, which is:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

Given the coordinates of the two points:

Point 1: (0, -9)

Point 2: (-4, -3)

Let's calculate the distance using the formula:

Distance = √((-4 - 0)^2 + (-3 - (-9))^2)

= √((-4)^2 + (-3 + 9)^2)

= √(16 + 36)

= √52

≈ 7.2 (rounded to the nearest tenth)

Therefore, the distance between the points (0, -9) and (-4, -3) is approximately 7.2 units (rounded to the nearest tenth)

(2x raised to fourth power) raised to the negative fourth power

Answers

${ \left( { \left( 2x \right) }^( 4 ) \right) }^( -4 )\n \n =\frac { 1 }{ { \left( { \left( 2x \right) }^( 4 ) \right) }^( 4 ) }$

$\n \n =\frac { 1 }{ { \left( 2x \right) }^( 16 ) } \n \n =\frac { 1 }{ { 2 }^( 16 ){ x }^( 16 ) } \n \n =\frac { 1 }{ 65536{ x }^( 16 ) }$

$(2x^4)^(-4)=2^(-4)\cdot (x^4)^(-4)=(1)/(2^4)\cdot (1)/((x^(4))^4)=(1)/(16)\cdot (1)/(x^(16))=(1)/(16x^(16))$