The period of the secant function is 2π, the correct option is C.
The period of a function is the value at which the function repeats itself.
The secant function is
f(x) = sec x
The period of the secant function can be determined from its graph.
A graph of y = sec x is plotted and the period is determined.
The period of the secant function is 2π, the correct option is C.
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Answer: C 2pi
Step-by-step explanation:
Which of the following could represent a diver’s position in relation to the surface of the water after diving into a pool? Select all that apply.
3 meters
-2 meters
-3.1 meters
1 and StartFraction 7 over 8 EndFractionmeters
Negative 2 and one-halfmeters
The numbers to represents a diver’s position in relation to the surface of the water after diving into a pool is;
-2 meter
-3.1 meter
Negative 2 and one-half meters
Given that;
A diver’s position is in the surface of the water diving into a pool.
We have to find number to represents a diver’s position in relation to the surface of the water after diving into a pool.
What is Negative number?
A number less than zero is called the negative number.
A diver’s position is in the surface of the water diving into a pool.
Since, Diving into a pool is represents negative number.
Hence, The number to represents a diver's position is in negative sign.
So, The numbers are;
⇒ -2 meter
⇒ -3.1 meter
⇒ Negative 2 and one-half meters.
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Answer:
-2, -3.1, -2.5
Step-by-step explanation:
Since the diver dived into the pool, they are below the surface (assuming it is an inground pool). So the correct answers will be the negative answers.
a.) 1/6
b.) 1/7
c.) 7/6
d.) 6/7
y-9x=3
9x-y=2
27x-3y=2
The requried line is not parallel to the graph of y = 9x + 1 is 1. 9y - x = 2. Option A is correct.
To determine which line is not parallel to the graph of y = 9x + 1, we need to compare the slopes of each line to the slope of y = 9x + 1.
The equation y = mx + b represents a line with slope m. In the case of y = 9x + 1, the slope (m) is 9.
Now, let's check the slopes of each equation given:
A. 9y - x = 2:
To write this equation in the form y = mx + b, we rearrange it as y = (1/9)x + 2/9. The slope is (1/9), which is not equal to 9. Therefore, this line is not parallel to y = 9x + 1.
B. y - 9x = 3:
Rearranging this equation as y = 9x + 3, we can see that the slope is 9, which is equal to the slope of y = 9x + 1. Therefore, this line is parallel to y = 9x + 1.
C. 9x - y = 2:
Rewriting this equation in the form y = mx + b, we get y = 9x - 2. The slope is 9, which is equal to the slope of y = 9x + 1. Therefore, this line is parallel to y = 9x + 1.
D. 27x - 3y = 2:
To put this equation in the form y = mx + b, we divide both sides by 3, which gives 9x - y = 2/3. The slope is 9, which is equal to the slope of y = 9x + 1. Therefore, this line is also parallel to y = 9x + 1.
In summary, the line not parallel to the graph of y = 9x + 1 is 1. 9y - x = 2. Option A is correct.
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Secant and tangent theorem: Square of measure of tangent is equal to the product of length of whole secant and length of exterior secant segment, i.e.
.
The whole secant with exterior secant 5 in is 5+y in. Using this theorem you can state that
.
Solve this equation:
in.
Answer: y=11.2 in.
b. Write a two-step ordered-pair rule, for the transformation sequence.
Answer:
a) Δ ABC is rotated around the origin by angle 180° and then translated 1
unite to the right and 3 units up
b) R (O , 180°) and T (x + 1 , y + 3)
Step-by-step explanation:
* Lets revise some transformation
- If point (x , y) rotated about the origin by angle 180° then its image
is (-x , -y)
- If the point (x , y) translated horizontally to the right by h units
then its image is (x + h , y)
- If the point (x , y) translated horizontally to the left by h units
then its image is (x - h , y)
- If the point (x , y) translated vertically up by k units
then its image is = (x , y + k)
- If the point (x , y) translated vertically down by k units
then its image is (x , y - k)
* Lets solve the problem
∵ Δ ABC change its place from 2nd quadrant to the 4th quadrant
and reverse its direction Point A up and its image A" down
∵ No change in its size
∴ Triangle ABC rotates 180° clockwise around the origin
# Remember : There is no difference between rotating 180° clockwise
or anti-clockwise around the origin
∵ The vertices of Δ ABC are:
# A = (-3 , 5)
# B = (-3 , 2)
# C = (-1 , 2)
∵ If point (x , y) rotated about the origin by angle 180° then its image
is (-x , -y)
∴ A'' = (3 , -5)
∴ B'' = (3 , -2)
∴ C'' = (1 , -2)
∴ Triangle ABC rotates 180° around the origin to form ΔA"B"C"
∵ The vertices of Δ A'B'C are:
# A' = (4 , -2)
# B' = (4 , 1)
# C' = (2 , 1)
- By comparing the x-coordinates and y-coordinates of points of
Δ A''B''C'' and Δ A'B'C' we will find that every x-coordinate add by 1
and every y-coordinate add by 3
∵ 4 - 3 = 1 and 2 - 1 = 1 ⇒ x- coordinates
∵ -2 - (-5) = -2 + 5 = 3 and 1 - (-2) = 1 + 2 = 3 ⇒ y-coordinates
∴ ΔA''B''C'' translates to the right 1 unite and up 3 units to form
Δ A'B'C'
a) Δ ABC is rotated around the origin by angle 180° and then
translated 1 unite to the right and 3 units up
b) R (O , 180°) and T (x + 1 , y + 3)