URGENT!!True or false: Light waves, gamma rays, and ocean waves are all 3 examples of energy traveling in waves.

Answers

Answer 1

Answer:

Answer:

False

Explanation:

Ocean waves are something you can physically see whereas Gamma Rays and Light Waves are something on the Electromagnetic Spectrum.

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Name 3 some sources of CO2
Which of the following is formed at a collision zone?Continental rift valleyVolcanic island chainMountain rangeDeep-ocean trench
Please help me ASAP! Giving out a nice amount of points! Correct answer gets Brainliest! :D Which would be a good example to demonstrate the principle of conservation of energy?A) A stone is crushedB) Light bends around a sharp edgeC) A pendulum swings back and forthD) A balloon inflates when air is blown into it

A student states that ALL Substances that are uniform throughout are pure substances. Why is this false?

Answers

The statement is false because a solution, which consists of two or more substances, is also uniform throughout. An example is sugar in water.

Using only the periodic table, write the symbol of the ion most typically formed by each of thefollowing elements:
a. K
d. Ci
b. Ca
c. S e. Ba f. Br

Answers

Answer:

The ion is written in the attached file

Explanation:

Final answer:

The most typical ions formed by K, Ca, and S are K+, Ca2+, and S2-, respectively.

Explanation:

The symbol of the ion most typically formed by each of the elements can be determined by looking at their positions on the periodic table and considering their electron configuration.

K (Potassium): The most typical ion formed by potassium is K+ (Potassium ion). Potassium has one valence electron in its outermost shell, and it tends to lose this electron to form a stable ion.
Ca (Calcium): The most typical ion formed by calcium is Ca2+ (Calcium ion). Calcium has two valence electrons in its outermost shell, and it tends to lose these electrons to achieve stability.
S (Sulfur): The most typical ion formed by sulfur is S2- (Sulfide ion). Sulfur has six valence electrons in its outermost shell, and it tends to gain two electrons to achieve stability.

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If a base is added to water, what will occur?hydronium ion concentration is increased.
hydroxide ion concentration is decreased.
[H+] is decreased.
[OH-] is decreased.

Answers

Answer:

[H+] is decreased.

Explanation:

Arrhenius Theory:

An acid is a substance which produces one or more hydrogen ions, (H+) in aqueous solution.

Examples:

$HCl(aq)>H^+(aq)+Cl^-(aq)\n\nHBr(aq)>H^+(aq)+Br^- (aq)\n\nH_2 SO_4(aq)>2H^+(aq)+SO_4^2- (aq)\n\nH_3 PO_4(aq) >3H^+ (aq)+PO_4^3-(aq)\n\nCH_3 COOH(aq)>CH_3 COO^- (aq)+H^+ (aq)$

A Base is a substance which produces one or more hydroxyl ion or hydroxide ion (OH-) in aqueous solution.

Examples

$NaOH(s)>Na^+ (aq) + OH^- (aq)\n\nKOH(s)>K^+ (aq) +OH^- (aq)\n\nCa(OH)_2 (s)>Ca^(2+) (aq)+2OH^-(aq)\n\nAl(OH)_3 (s)> Al^(3+)(aq)+ 3OH^- (aq)$

Please note:

(aq) stands for aqueous which means in the presence of water that is, water acts as a solvent

So, on adding a base to the water increase in $[OH^-]$ will take place and this will decrease the Hydrogen ion concentration

Pure water contains $[H^+]=[OH^-]$

if the solution is acidic $[H^+ ]>[OH^- ]$

if the solution is Basic $[H^+ ]<[OH^- ]$

Answer:

Explanation:

The first and most obvious statement is that [OH-] is increased, but that is not offered to you.

The second most obvious statement is that the [H+] ion is decreased. That is offered to you. It is C

Increase the brightness of the light for the colors red, yellow, orange, and green. What effect did the brightness of the light have on the metal? (science)

Answers

make me brainliest

Explanation:

The observations are as follows: Initially with the plates in the dark, no electrons pass between the plates and no current flows. As we shine light on the plates, going from low energy red to high energy blue, suddenly current begins to flow. How?

Einstein explained the result be describing the light waves as packets of energy. He called the packets of energy photons. Each photon has a specific energy, the shorter the wavelength, the higher the energy. When a high-energy photon hits the plate (such as a green or blue), the photon has enough energy to knock out an electron and then the electron, being negative, will fly to the positive side. At this point, current flows.

The lower energy photons are unable to know out the electrons and no energy can flow.

The exciting thing to note is the treatment of energy as a particle or a packet, it is consistent with the fact energies are not additive. If we can bump electrons with light at 600 tera-hertz , we can�t just use 300 tera-hertz for twice the time and still expect to bump electrons.

What if the photon has greater than the threshold energy required to pop out an electron? The extra energy just goes into the kinetic energy of the electron. This relationship can be described by the following equation.

hf = w + KE

where hf is the energy of the photon.

w is the energy required to bump an electron.

KE is the kinetic energy of the electron.

If the photon has less energy than w, no electron is emitted.

Final answer:

Increasing the brightness of light for red, yellow, orange, and green colors can cause a metal to absorb more energy and potentially undergo physical or chemical changes such as expansion or emitting light of a certain color.

Explanation:

Increasing the brightness of the light for the colors red, yellow, orange, and green will affect the metal in different ways depending on the specific metal being used. Generally, metals will absorb some of the energy from the light and convert it into heat. This increase in heat can cause the metal to expand, change its color, or undergo other physical or chemical changes.

For example, when a metal is exposed to bright light, it may heat up and expand, leading to changes in its shape or dimensions. Additionally, depending on the metal and its properties, the increased brightness of light can lead to certain metals absorbing specific wavelengths of light, which can cause the metal to emit photons and exhibit a characteristic color.

In summary, increasing the brightness of light for red, yellow, orange, and green colors can cause a metal to absorb more energy and potentially undergo physical or chemical changes such as expansion or emitting light of a certain color.

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Select the correct answer.If a silver nitrate solution is added to excess sodium sulfide, this reaction takes place: 2AgNO3(aq) + Na2S(aq) → Ag2S(s) + 2NaNO3(aq).
Suppose you use 0.0150 liter of a 2.50 M solution of silver nitrate. Assuming the reaction goes to completion, how much silver sulfide is produced? Use the periodic table.
A. 1.49 g
B. 4.65 g
C. 9.30 g
D. 18.6 g

Answers

Answer:- B. 4.65 g.

Solution:- The given balanced equation is:

$2AgNO_3(aq)+Na_2S(aq)\rightarrow Ag_2S(s)+2NaNO_3(aq)$

It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.

Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.

Molar mass of $Ag_2S$ = 2(107.87)+32.06 = 247.8 g per mol