MATHEMATICS COLLEGE

1. Two angles are supplementary. Angle 1 measures4x + 6 degrees and Angle 2 measures 38 degrees.
What is the value of x? *
doaroor​

Answers

Answer 1
Answer:

Answer:

34 degrees

Step-by-step explanation:

supplementary Angles are pair of angles whose sum is 180 degrees.

Given

Angle 1 =4x + 6 degrees

Angle 2 = 38 degrees

Condition : angles are supplementary Angles

therefore

Angle 1 + Angle 2 =180

4x+6+38 = 180

=>4x+44 = 180

=> 4x = 180-44

=> 4x= 136

=>x = 34

Thus value of x is 34 degrees.

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A restaurant has a capacity of 120 patrons. If the restaurant is full, how many patrons are at the restaurant?

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Answer:120?

Step-by-step explanation:

Simplify The square root of 5 (6-4 the square root of 3)

Answers

Answer:

7.75

Step-by-step explanation:

6-4=2

2 times the square root of 3=3.46410161514

square root of 5 times 3.46410161514=7.74596669242

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Solve the differential equation x^2 y"-xy' +y 0

Answers

Answer:

y(x)\ =\ √(x)[C_1cos(√(3))/(2)logx+C_2sin(√(3))/(2)logx]

Step-by-step explanation:

Given differential equation is

x^2y                     (1)

Let's assume that

x=e^t

=>\ t\ =\ logx

then,

(dx)/(dt)=e^t

and\ (d^2x)/(dt^2)=e^t

We can write,

(dy)/(dx)=(dy)/(dt).(dt)/(dx)

                      =e^(-t)(dy)/(dt)

Similarly,

(d^2y)/(dt^2)=(d^2y)/(dt^2).(dt^2)/(dx^2)

                            =e^(-2t).(d^2y)/(dt^2)

Putting these values in equation (1), we will get

e^(2t).e^(-2t).(d^y)/(dt^2)-e^t.e^(-t)(dy)/(dt)+y=0

=>(d^2y)/(dt^2)-(dy)/(dt)+y=0

So, the characteristics equation can be given as

D^2-D+1=0

=>D\ =\ (1+√(1-4))/(2)\ or\ (1-1√(1-4))/(2)

=>D=\ (1)/(2)+i(√(3))/(2)\ or\ (1)/(2)-i(√(3))/(2)

Hence, the general solution of the equation can be give by

y(t)\ =\ e^{(t)/(2)}[C_1cos(√(3))/(2)t+C_2sin(√(3))/(2)t]

Now, by putting the value of t in above solution, we will have

y(x)\ =\ e^{(1)/(2)logx}[C_1cos(√(3))/(2)logx+C_2sin(√(3))/(2)logx]

y(x)=\ √(x)[C_1cos(√(3))/(2)logx+C_2sin(√(3))/(2)logx]

Hence, the solution of above given differential equation can be given by

y(x)=\ √(x)[C_1cos(√(3))/(2)logx+C_2sin(√(3))/(2)logx]

                           

If;= V-1, what is the value of ; i3?

-1
i
1
-i

Answers

Answer:

A. -1

Step-by-step explanation:

hope this helps

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A train leaves the station at time t=0. Traveling at a constant​ speed, the train travels 280 kilometers in 2 hours. Answer parts a and b.a. Write a function that relates the distance traveled d to the time t.

The function that relates the distance traveled d to the time t is

Answers

The function that relates the distance travelled d to the time t is d = f(t) = 140t.

What is Speed?

Speed is a scalar quantity which measures the rate of change of the position of an object without measuring on the direction.

In other words, it can be defined as the ratio of distance covered by an object to the time taken by the object to cover the distance.

The train leaves the station at time t = 0.

Distance travelled by the train = 280 kilometers

Time taken to travel the distance = 2 hours

Speed = Distance / Time

           = 280 / 2

           = 140 kilometers/ hour.

Given that train travels at a constant speed.

So for any distance 'd' and the time taken to travel the distance 't',

d / t = 140

d = 140t

d = f(t) = 140t

Hence the distance travelled by the train can be related to the time taken by the function, d = f(t) = 140t

To learn more about Speed, click :

brainly.com/question/28224010

#SPJ5

Answer:

d = 140t

Step-by-step explanation:

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