PHYSICS MIDDLE SCHOOL

A concave mirror can produce _____.either a virtual image or a real image

a real image

a virtual image

a refracted image

Answers

Answer 1
Answer:

Answer:

a virtual image

Explanation:

gradpoint

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Calculate the average speed (in m/s) of a cheetah that runs 140 meters in 5 seconds

Answers

should be 28 meters per second.
140m รท 5s

Final answer:

The average speed of a cheetah that runs 140 meters in 5 seconds is calculated by dividing the distance by time, which equals 28 m/s.

Explanation:

To calculate the average speed of a cheetah running a distance of 140 meters in 5 seconds, we use the formula for average speed which is:

Average Speed = Distance / Time

Substituting the given values of distance and time in this equation, we get:

Average Speed = 140 meters / 5 seconds

Solving this, we obtain the average speed of the cheetah as 28 m/s.

The average speed is a scalar, meaning we do not include direction in the answer. For comparison purposes, the speed of a typical automobile might be around 15 m/s.

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The orientation of which of the following does not influence the phases of the moon?a.
Earth

c.
Sun

b.
the moon

d.
Stars

Answers

So we want to know what is not influencing the phases of the Moon. What influences Moon phases are celestial bodies that are close enough to have enough gravitational force to have an influence. Those celestial bodies would be the Earth and the Sun, since moon itself cant influence itself and all other stars are too far to exert gravitational force. So the correct answer would be the Moon and the stars do NOT have an influence on the Moon phases.

Answer:

So the correct answer would be the stars do NOT have an influence on the Moon phases.

A ball is dropped from the top of a tall building. As the ball falls, the upward force of air rsistance becomes equal to the downward pull of gravity. When these two forces become equal in magnitude the ball will: a) flatten due to the forces b) fall at a constant speed c) continue to speed up d) slow to a stop

Answers

fall at a constant speed

Final answer:

When the force of air resistance equals the downward force of gravity, the net force on a falling object becomes zero, meaning it will fall at a constant speed.

Explanation:

The subject of this question is Physics, specifically focusing on the aspects of forces, gravity, and air resistance involved when an object is in free fall. When the magnitude of the upward air resistance equals the downward pull of gravity, the net force on the ball becomes zero. According to Newton's second law of motion, when the net force on an object is zero, its acceleration is also zero, meaning it will not speed up or slow down. In this case, the ball will fall at a constant speed. Therefore, the correct answer is b) fall at a constant speed.

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how to control stage fear or get rid of it ( please help me or share ur experience that how u got rid of it )

Answers

I have that problem, the only thing that helps me is to look at someone I know, like my parents or my sister or grandma etc. and don't think about what other people might think about you.
So good luck.

I hope this helps you.

a 0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. what force was necessary for this change in velocity?

Answers

Answer: 90N

Explanation:

Mass of ball = 0.45 kg

Change in velocity = 20.0 m/s

Time = 0.10 seconds

Force required for change = ?

Since force refers to the change in momentum per unit time, hence

Force = Momentum / Time

i.e Force = Mass x (change in velocity / time)

Force = 0.45kg x (20.0m/s /0.10second)

= 0.45kg x (200 m/s^2)

= 90N

Thus, 90N of force was necessary for this change in velocity

Figure 1.18 (Chapter 1) shows the Hoover Dam Bridge overthe Colorado River at a height of 271 m. If a heavy object is
dropped from the bridge, how much time passes before the
object makes a splash?

Answers

Answer: 7.436 s

Explanation:

This situation is related to vertical motion, specifically free fall and can be modelled by the following equation:

y=y_(o)+V_(o) t+(gt^(2))/(2)  

Where:

y= 0m is the final height of the object (when it makes splash)

y_(o)=271 m  is the initial height of the object

V_(o)=0 m/s  is the initial velocity of the object (it was dropped)

g=-9.8m/s^(2)  is the acceleration due gravity (directed downwards)

t is the time since the objecct is dropped until it makes splash

0=y_(o)+0+(gt^(2))/(2)  

Clearing t:

t=\sqrt{(-2y_(o))/(g)}  

t=\sqrt{(-2(271 m))/(-9.8m/s^(2))}  

Finally:

t=7.436 s  

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