K=1/2mv^2
How do I solve for m?

Answers

Answer 1

Answer: K=1/2m*v^2 | :v^2
K/v^2=1/2m | *2

2k/v^2=m

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Write a possible recursive rule and then find a7 for { 7,12,17,22,27}

Answers

Start from 7, then add 5 each time.

a7 is 7 plus 30, or 37.

which one of following statement expresses a true proportion 3:4=9:12 b. 2:1=1:2 c. 7:9=8:9 d. 54:9=6:3

Answers

a is the right one:
a. 3:4=9:12
3×3:4×3=9:12

FJ= 24
JH = 3x-3
21. x = ?

can someone help asap please!!!

Answers

Answer:

$\boxed {x = 7}$

Step-by-step explanation:

$FJ$ and $JH$ is half of the whole measurement of $FH$ . So, to find the value of $x$ , you need to write an expression by using those measurements of both $FJ$ and $JH$ . Then, solve for $x$ :

$FJ = 24$

$JH = 3x - 3$

$3x - 3 = 24$

-Solve:

$3x - 3 = 24$

$3x - 3 + 3 = 24 + 3$

$3x = 27$

$(3x)/(3) = (27)/(3)$

$\boxed {x = 7}$

So, the value of $x$ is $7$ .

What are the solutions to the quadratic equation x2 – 16 = 0?x = 2 and x = –2
x = 4 and x = –4
x = 8 and x = –8
x = 16 and x = –16

Answers

The correct statement is that the solution of this equation x² – 16 = 0, is 4 and -4.

What is a quadratic equation?

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation. The general form of the quadratic equation is ax² + bx + c = 0

Given

The quadratic equation x² – 16 = 0

To find

The root of the quadratic equtaion?

How do find the solutions to the quadratic equation?

The quadratic equation x² – 16 = 0

We know the formula,

a² - b² = ( a - b ) ( a + b )

Then

x² – 4² = 0

(x - 4)(x + 4) = 0

x = 4 and -4

Thus, the solution of this equation x² – 16 = 0, is 4 and -4.

More about the quadratic equation link is given below.

brainly.com/question/2263981

Answer: The correct option is (B) x = 4 and x = -4.

Step-by-step explanation: We are given to find the solutions to the following quadratic equation :

$x^2-16=0~~~~~~~~~~~~~~~~~~~~~(i)$

Since the coefficient of x is zero in the given equation, so we will be using the method of square root to solve the equation.

From equation (i), we have

$x^2-16=0\n\n\Rightarrow x^2=16\n\n\Rightarrow x=\pm√(16)~~~~~~~\textup{[taking square root on both sides]}\n\n\Rightarrow x=\pm4\n\n\Rightarrow x=4,~-4.$

Thus, the required solution is x = 4 and x = -4.

Option (B) is correct.

In a right-angled triangle, the side opposite the right angle is unknown, how do you find out the unknown length? (Hypotenuse I think)

Answers

Yes, it is the hypotenuse. You can use pythagoras' theorem or the sine rule. you can use either as long as you know the two other side lengths of the triangle

a²+b²=c² (c is the hypotenuses

Repeat Question 2 and Question 3 for corresponding points B and BGH, C and CGH, and D and DGH. With your measurements displayed in GeoGebra, move the line of reflection, , around the coordinate plane. Also, move the points of the preimage ABCD as you’d like. Based on your investigation, what can you conclude about the line of reflection with respect to the image and the preimage? Express your answer in geometric terms.

Answers

Answer:

A vertex on polygon ABCD and its corresponding vertex on polygon AGHBGHCGHDGH are always equidistant from the line of reflection. Each of the four line segments (, for example) is perpendicular to and cut in half by the line of reflection, . This means that is a perpendicular bisector of those line segments.

Step-by-step explanation:

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